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RemarkRemark: Literature-sourcedProof: AI-adaptedPipeline-generatedprecheck passjudge pass (gpt-6-sol)audited 2026-09-30
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Weak derivatives are represented distributional derivatives

Remark

Assume Countable Choice, as required by the cited regular-distribution injection, weak-derivative uniqueness, measure, and interval-FTC results. Let Ω⊆Rn be open, n≥1, let u∈Lloc1(Ω), and let α∈N0n. Then Dαu exists as a weak Lloc1 derivative⟺∂αTu∈{Th:h∈Lloc1(Ω)}⊆D′(Ω). When such an h exists, its almost-everywhere class is unique. Every distribution has distributional derivatives, but these derivatives need not lie in the image of the regular-distribution map. In particular, a locally integrable function can belong to every Lp under consideration and still have no Lp weak derivative.

Example of the obstruction. On Ω=(−1,1) let u=1(0,1). This function is in Lp(Ω) for every 1≤p≤∞, but its distributional derivative is δ0. The delta distribution is not the regular distribution of any h∈Lloc1((−1,1)), so u has no locally integrable weak derivative, and consequently no Lp weak derivative.

Facts & Assumptions

Given: Countable Choice, an open set Ω⊆Rn, n≥1, u∈Lloc1(Ω), and α∈N0n.

[F1]

The regular pairing Tf(φ)=∫Ωfφ defines a distribution for each f∈Lloc1(Ω); under Countable Choice the map from almost-everywhere classes to distributions is injective (Locally integrable functions as regular distributions).

[F2]

The weak-derivative identity is equivalent to ∂αTu=Tv (Weak derivative of a locally integrable function).

[F3]

A weak derivative, when it exists, is unique as an almost-everywhere class under Countable Choice (Uniqueness of a weak derivative as an almost-everywhere class).

[F4]

Distributional differentiation maps every distribution to a distribution, with the signed-transpose convention (Distributional derivative).

[F5]

A complex Lp class is the quotient of measurable functions with finite Np (Complex Lp classes and Euclidean test-function conventions).

[F18]

For finite p, Np is the pth-root integral size; for p=∞, N∞ is the essential-supremum size (Complex Lp classes and Euclidean test-function conventions).

[F6]

The intervals (0,1) and (−1,1) have measures one and two, respectively, and [−ε,ε] has measure 2ε for 0<ε<1/2 (A box in Rn with parameters ai≤bi is Lebesgue measurable of measure ∏i<n(bi−ai), whichever of its faces are included).

[F7]

The nonnegative integral of an indicator equals the measure of its measurable set, and a nonnegative simple function has integral equal to its simple integral (The integral of a nonnegative simple function, The nonnegative integral agrees with the simple integral on simple functions).

[F8]

Every compact subset of R is measurable with finite measure under Countable Choice; the integral over a measurable set is the integral after restricting by its indicator, and the nonnegative integral is monotone (Lebesgue measure is sigma-finite, and every metrically bounded subset of Rn has finite outer measure, Integral over a measurable subset, Monotonicity and nonnegative homogeneity of the nonnegative integral).

[F9]

A complex function is integrable when its modulus has finite integral (Integrable real and complex functions, and their integrals).

[F10]

In one dimension there is a smooth β:R→[0,1] equal to one on [−1/2,1/2] and with support contained in (−1,1) (A smooth bump between concentric Euclidean balls).

[F11]

If h is integrable on a compact set, then its absolute integral over measurable subsets tends to zero as their measure tends to zero (Absolute continuity of the integral).

[F12]

For complex C1 functions, the Lebesgue integral of the derivative on a compact interval is the endpoint increment, under Countable Choice (Complex integration by parts on intervals and decaying lines).

[F13]

For a∈Ω, the Dirac distribution satisfies δa(φ)=φ(a) (Dirac delta and its derivatives).

[F14]

For open Ω, membership in Lloc1(Ω) means integrability on every compact subset of Ω (Regular distribution from a locally integrable function).

[F15]

A test function on an open set has compact support in that set, and its zero extension to Rn is smooth with compact support (Test function space d of an open set).

[F16]

Composing a smooth one-variable function with x↦x/ε preserves smoothness; iterating the chain rule gives (β(⋅/ε))(m)(x)=ε−mβ(m)(x/ε) (The chain rule, in one line from Carathéodory: if g is differentiable at c and f is differentiable at g(c), then f∘g is differentiable at c with (f∘g)′(c)=f′(g(c)) g′(c)).

[F17]

Countable Choice asserts that every countably indexed family of nonempty sets has a choice function (The Axiom of Countable Choice (ACω)).

Proof

technique · direct
1.1F1F2F4given

For every test φ∈Cc∞(Ω), the identity ∂αTu=Th expands by [F1] and [F4] to (−1)∣α∣∫ΩuDαφ dx=∫Ωhφ dx; since the sign squares to one, this is exactly the weak-derivative identity, and conversely that identity gives the distribution equality, proving both directions of the image criterion.

1.2F5F6F7F8F9F14F18given

On Ω=(−1,1), let u=1(0,1); [F6] gives λ((0,1))=1 and λ(Ω)=2, so [F7], [F5], and [F18] give ∫Ω∣u∣p=1 for finite p≥1 and essential supremum one, hence u∈Lp(Ω) for every 1≤p≤∞; also u∈L1(Ω) by [F7] and [F9], and for every compact K⊆Ω, [F8] gives ∫K∣u∣≤∫K1 dx=λ(K)<∞, so u∈Lloc1(Ω) by [F14].

1.3F1F2given

If Ω=∅, [F1] gives only the zero regular distribution and locally integrable class, so the image criterion holds and the weak test identity is vacuous.

2.1F3step 1.1given

If h and k both represent ∂αTu, step 1.1 makes both weak α-derivatives of u, and Countable-Choice uniqueness [F3] gives h=k almost everywhere.

2.2F1step 1.1given

If α=0, then D0u=u and ∂0Tu=Tu; step 1.1 and the injection [F1] identify every representing class h with u almost everywhere.

2.3F4F12F13F15step 1.2given

For φ∈Cc∞((−1,1)), its zero extension φ~ is smooth and vanishes at 1 by [F15], so the signed derivative and complex FTC [F4, F12] give ⟨∂Tu,φ⟩=−∫01φ~′(x) dx=φ~(0)−φ~(1)=φ(0)=δ0(φ) by [F13]; hence ∂Tu=δ0.

2.4F1F6F10F11F13F14F15F16step 1.2given

If δ0=Th for some h∈Lloc1((−1,1)), choose the bump β from [F10] with r=1/2 and R=1, and set φε(x)=β(x/ε) for 0<ε<1/2; iterating the chain rule [F16] and scaling its compact support [F15] make this a test with value one at zero and 0≤φε≤1, so [F1] and [F13] give 1=∣Th(φε)∣≤∫[−ε,ε]∣h∣. The function h is integrable on [−1/2,1/2] by [F14], while [F6] makes the interval measures tend to zero and absolute continuity [F11] makes the right side tend to zero, a contradiction. Thus δ0 has no locally integrable representative, and step 1.2's Lp function has no Lp weak derivative.

3.1F1F4step 1.1step 2.1given

If u=0, [F1] gives Tu=0 and [F4] gives ∂αTu=0=T0; step 1.1 makes zero a weak derivative, and step 2.1 makes its class unique.

4.1F1F3F6F8F12F17given∎

Countable Choice is used only by the injection and uniqueness [F1, F3], interval and compact-measure facts [F6, F8], and complex interval FTC [F12]; the test-pairing equivalence and shrinking-test contradiction are direct, and no full Axiom of Choice is used.

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