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Bochner's theorem for LCA groups

Statement

Assume the Axiom of Choice and Dependent Choice. Let G be a locally compact Hausdorff abelian group with dual G^. A continuous function ϕ:G→C is positive definite if and only if there is a unique finite positive Radon measure μ on G^ with ϕ(x)=∫G^γ(x) dμ(γ)(x∈G), and then μ(G^)=ϕ(0). The measure is called the representing measure of ϕ.

Facts & Assumptions

Given: The Axiom of Choice and Dependent Choice, a locally compact Hausdorff abelian group G with Haar measure mG and dual G^, and a continuous function ϕ:G→C.

[F1]

If μ is a finite positive Radon measure on G^, then ϕμ(x):=∫G^γ(x) dμ(γ) is continuous and positive definite, and ϕμ(0)=μ(G^) (Fourier-Stieltjes transforms of positive measures are continuous positive definite, Positive definite functions on an abelian group, Radon measure on an LCH space).

[F2]

If ϕ is continuous and positive definite with k=ϕ(0), then the transform-core functional Fϕ of the preceding lemmas extends uniquely to a bounded positive linear functional L on C0(G^) with norm k, there is a finite positive Radon measure μϕ on G^ with L(H)=∫G^H dμϕ for all H∈C0(G^) and μϕ(G^)=k, and for every f∈L1(G,mG) one has Fϕ(f^)=Lϕ(f)=∫Gf(x)ϕ(−x) dmG(x) (Positive definite functions give positive bounded functionals on the transform core, The Bochner functional extends and has a Radon representing measure, The Fourier transform on an LCA group).

[F3]

Two finite regular complex Borel measures on G^ with the same inverse transform x↦∫G^γ(x) dσ(γ) are equal (Fourier-Stieltjes transforms determine finite Radon measures, Regular complex Borel measures).

[F4]

For f∈Cc(G) and the finite measure μϕ, Fubini gives ∫G^f^ dμϕ=∫Gf(x)(∫G^γ(−x) dμϕ(γ))dmG(x); the function x↦∫G^γ(x) dμϕ(γ) is continuous because ∣μϕ∣ is inner regular and characters converge uniformly on compact sets; and a continuous function on G annihilated by every nonnegative compactly supported bump is identically zero, since Haar measure is positive on nonempty open sets and Urysohn cutoffs exist (Fubini's theorem for L^1 functions on a sigma-finite product, Radon measure on an LCH space, Evaluation of characters is jointly continuous, The Pontryagin dual with the compact-open topology, Haar measure is positive on nonempty open sets and finite on compact sets, LCH Urysohn cutoff, Compact support, Cc(X), and C0(X)).

Proof

technique · direct
1.1F1

(The easy direction.) Assume ϕ(x)=∫G^γ(x) dμ(γ) for a finite positive Radon measure μ. Then by [F1] ϕ is continuous and positive definite with ϕ(0)=μ(G^); this proves the reverse implication and the mass identity for that direction.

1.2F2

(The converse: construction of the measure.) Assume ϕ continuous and positive definite, and put k:=ϕ(0). By [F2] there is a finite positive Radon measure μϕ on G^ with μϕ(G^)=k, representing the extension L of Fϕ on C0(G^), and with ∫G^f^ dμϕ=Fϕ(f^)=∫Gf(x)ϕ(−x) dmG(x) for every f∈L1(G,mG).

2.1F2F4F5step 1.2

(The representation ϕ=μˇϕ.) Let f∈Cc(G)⊆L1(G,mG) and put Ψ(x):=∫G^γ(x) dμϕ(γ). By [F4], Fubini and step 1.2 give 0=∫Gf(x)ϕ(−x) dmG(x)−∫G^f^ dμϕ=∫Gf(x)(ϕ(−x)−Ψ(−x))dmG(x). Replacing f by f(−⋅), which still ranges over Cc(G), and using the inversion invariance of Haar measure [F5] yields ∫Gf(x)(ϕ−Ψ)(x) dmG(x)=0 for every f∈Cc(G). The function D:=ϕ−Ψ is continuous by hypothesis and [F4]. If D(y0)≠0, choose c∈C with ∣c∣=1 and Re⁡(cD(y0))>0; continuity gives a nonempty open neighbourhood V of y0 on which Re⁡(cD)>0. Choose a nonzero nonnegative bump f∈Cc(G) supported in V. Since Haar measure is positive on nonempty open sets, ∫Gf(x)Re⁡(cD(x)) dmG(x)>0, contradicting c∫Gf(x)D(x) dmG(x)=0. Thus D=0, so ϕ(x)=Ψ(x)=∫G^γ(x) dμϕ(γ) for every x∈G.

2.2F3step 1.1

(Uniqueness of the representing measure.) Suppose finite positive Radon measures μ,ν on G^ satisfy ∫G^γ(x) dμ(γ)=∫G^γ(x) dν(γ) for every x∈G. Then σ:=μ−ν is a finite regular complex Borel measure whose inverse transform vanishes identically, so σ=0 by [F3], that is, μ=ν.

3.1step 1.1step 1.2step 2.1step 2.2∎

(Conclusion.) Step 2.1 proves that every continuous positive definite ϕ has a representing finite positive Radon measure μϕ with μϕ(G^)=ϕ(0) by step 1.2, step 2.2 proves uniqueness, and step 1.1 proves the converse direction and its mass identity.

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