Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-generatedprecheck passaudited 2026-08-11
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Functions of bounded variation form an algebra

Statement

If f and g have bounded variation on [a,b], so do f+g, cf, and fg. If ∣f∣≤Mf and ∣g∣≤Mg, then

Var⁡(fg)≤MfVar⁡(g)+MgVar⁡(f).

Facts & Assumptions

Proof

technique · direct
1.1

By [L2] choose Mf,Mg≥0 with ∣f(x)∣≤Mf and ∣g(x)∣≤Mg on [a,b]. For a partition point pair x<y, the identity f(y)g(y)−f(x)g(x)=f(y)(g(y)−g(x))+g(x)(f(y)−f(x)) gives ∣(fg)(y)−(fg)(x)∣≤Mf∣g(y)−g(x)∣+Mg∣f(y)−f(x)∣.

L2L5algebra
2.1

Summing step 1.1 over any partition yields V(fg,P)≤MfV(g,P)+MgV(f,P)≤MfVar⁡(g)+MgVar⁡(f). Taking the supremum proves the displayed bound and that fg is BV.

step 1.1L3L4
3.1

Closure under sums and scalar multiples is [L1], and step 2.1 supplies closure under products, so the BV functions form an algebra under pointwise operations.

step 2.1L1∎

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

32 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources