Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedverified 2026-10-22 (gpt-6.1-sol)
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Newton polygon edge slopes are boundary slopes

Statement

Assume full AC and let K⊂S3 be a nontrivial smooth knot. Form the Newton polygon of the ordinary A-polynomial using the exponent convention that the lattice point (a,b) represents the monomial MbLa, so edge slopes are measured in the preferred meridian-longitude convention. Every finite rational slope or infinite slope of an edge of this Newton polygon is a boundary slope of an incompressible, boundary-incompressible, orientable surface in the knot exterior. This statement does not assert that the realizing surface is non-fibered or that the slope is strict.

Facts & Assumptions

Given: Full AC, the nontrivial smooth knot with its chosen compact exterior and peripheral marking, and the stated Newton edge.

[A1]

Full AC is retained. The Axiom of Choice

[F1]

The exterior is compact orientable and irreducible, with no proper compressing disk. Full AC supplies the countable choice needed by its smooth Schoenflies branch. Its tube is a smooth S1×D2 product by the normal-circle frame supplier, so the boundary is the marked smooth torus. It is connected: join two distinct exterior points by an embedded spherical arc, perturb it relative to its endpoints to be transverse to the knot, and use 1+1<3 to conclude it misses the knot. Radial projection of nonzero tube fibers to their boundary fixes the exterior and retracts that arc to an exterior path; equal endpoints need the constant path. A smooth knot exterior is irreducible The boundary of a nontrivial knot exterior is incompressible The oriented normal bundle of a knot is trivial Choice-free relative transversality for a compact smooth embedding

[F2]

Every selected Newton edge has an ACTUAL finite representation field and extending local curve valuation with peripheral eigenvalue pair a positive multiple of its primitive minimum normal. For an enhanced edge the representation is absolutely irreducible, including when its factor is also L−1. Newton edges have valued finite peripheral representation models

[F3]

For that valued representation, the actual lattice-tree/equivariant-map construction gives a connected orientable smooth essential surface with nonempty boundary whose primitive class annihilates the valuation pair. It proves both incompressibility and boundary-incompressibility by map-preserving compression complexity. With an absolutely irreducible representation it also proves that the chosen component cannot be a fiber. Nonelliptic lattice-tree actions produce essential boundary surfaces

[F4]

In the stated marking a[λ]+b[μ] has slope b/a, including a=0 as infinity. Boundary slope of an incompressible surface in a knot exterior

Proof

1.1A1F2givenconstruct

Let e be any edge of the ordinary Newton polygon. Apply [F2] to the ordinary polynomial: it selects an irreducible peripheral curve factor with parallel minimum face, constructs the boundary-branch DVR by the unimodular toric chart, selects an actual generic representation over a finite extension of the peripheral function field by a closed point of the nonzero incidence fiber, and extends the valuation to that field. If (u,v) is the primitive minimum normal in exponent coordinates (a,b), its eigenvalues satisfy (w(L),w(M))=d(u,v) for an integer d>0. Nothing in this step assumes that this ordinary representation is irreducible; it includes the abelian L−1 factor.

2.1F1F3step 1.1construct

The manifold hypotheses of [F3] are exactly [F1]. Its valued-field hypotheses are supplied by step 1.1, and the valuation pair is nonzero. Thus [F3] gives a connected orientable neatly properly embedded smooth surface with nonempty boundary, no compression or boundary compression, and primitive boundary class (a,b) satisfying au+bv=0. This is an actual associated midpoint surface after the finite compression and deletion homotopies, not an assumed Culler–Shalen witness.

3.1F2F4step 1.1step 2.1algebra∎

Every direction (Δa,Δb) of the original edge also satisfies uΔa+vΔb=0. Consequently its extended rational slope Δb/Δa is exactly b/a by [F4], including the vertical case where both denominators vanish and the value is infinity. This is a boundary slope realized by the surface of step 2.1, as required. The proof uses only the ordinary branch of [F2]–[F3] and makes no nonfiber or strictness assertion for that branch.

Depends on

Used by

Dependency tree · two levels

26 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources