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TheoremStatement: Literature-sourcedProof: AI-adaptedprecheck passaudited 2026-08-26
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  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
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A map into Cn is holomorphic exactly when each of its components is

Statement

Let m,n≥1, let U⊆Cm be open, let a∈U and let F:U→Cn with components Fj=πj∘F for j<n. Then F is holomorphic at a (Holomorphic maps Cm→Cn and the complex Jacobian matrix) if and only if every Fj is holomorphic at a (Holomorphic functions on an open subset of Cm), and in that case

DF(a)h=(DF0(a)h,…,DFn−1(a)h),(JCF(a))jk=∂zkFj(a).

For n=1 this is the scalar definition read back.

Facts & Assumptions

Given: An open U⊆Cm, a∈U and F:U→Cn with components Fj; the spaces are read through Complex m-space and its real coordinate dictionary.

[L1]

F is holomorphic at a when there is a C-linear L:Cm→Cn with F(a+h)=F(a)+L(h)+r(h) and ∥r(h)∥/∥h∥→0; L is unique and its matrix in the standard bases is JCF(a), whose (j,k) entry is the jth coordinate of L(ek) (Holomorphic maps Cm→Cn and the complex Jacobian matrix, Coordinate columns [v]B and matrices [T]BC of linear maps relative to ordered bases).

[L2]

The scalar case is the same condition with ∣r(h)∣/∥h∥→0 and L a C-linear functional (Holomorphic functions on an open subset of Cm).

[L4]

Under the interleaved real-coordinate identification fixed in the Given, ∣wj∣2=(Re⁡wj)2+(Im⁡wj)2, so the Euclidean norm is ∥w∥=(∑j<n∣wj∣2)1/2 (The p-norms ∥x∥p for rational p≥1, and ∥x∥∞, The Euclidean inner product ⟨x,y⟩=∑k<nxkyk on Rn).

[L6]

Finite sums in the additive commutative monoid of C may be regrouped termwise, and complex-field distributivity permits scaling term by term (A finite sum in a commutative monoid indexed by an arbitrary finite set, C=R[x]/(x2+1) is a field, every element is uniquely a+bi, and every nonzero element has inverse (a−bi)/(a2+b2)).

[L7]

If a scalar function is complex differentiable at a, its complex-linear real differential has the form Dg(a)h=∑k<m(∂zkg(a))hk (A real-linear functional on Cm is complex linear exactly when its antiholomorphic part vanishes, Wirtinger operators in Cm).

[L8]

∣zw∣=∣z∣∣w∣ and ∣z+w∣≤∣z∣+∣w∣ (Conjugation is an involutive real-field automorphism, zz‾=∣z∣2, and modulus is definite, multiplicative, and subadditive).

Proof

technique · direct
1.1L4L6L8

By [L4] and [L6], every w∈Cn satisfies ∣wj∣≤∥w∥ for each j<n and ∥w∥≤∑j<n∣wj∣, the first because ∣wj∣2 is one term of a sum of nonnegative terms and the second because the square of the right-hand side dominates that sum.

2.1givenstep 1.1L1L2

Suppose F is holomorphic at a with L=DF(a) as in [L1]. For each j<n the map πj∘L is C-linear, being a coordinate of a C-linear map, and Fj(a+h)=Fj(a)+(πj∘L)(h)+rj(h) with ∣rj(h)∣≤∥r(h)∥ by step 1.1; so ∣rj(h)∣/∥h∥→0 and [L2] makes Fj holomorphic at a with DFj(a)=πj∘L.

2.2givenstep 1.1L1L2L6

Conversely, suppose every Fj is holomorphic at a with Lj=DFj(a), and set L(h)=(L0(h),…,Ln−1(h)). Then L is C-linear because each coordinate is and the operations on Cn are coordinatewise, and the remainder of F has ∥r(h)∥≤∑j<n∣rj(h)∣ by step 1.1; each summand is o(∥h∥) and there are finitely many, so [L6] makes the sum o(∥h∥) and [L1] makes F holomorphic at a with DF(a)=L.

3.1step 2.1step 2.2L1L2L5L7∎

In either direction DF(a)h=(DF0(a)h,…,DFn−1(a)h) by steps 2.1 and 2.2 and the uniqueness in [L1]. Evaluating at h=ek and reading the jth coordinate, [L1], [L5] and [L7] give (JCF(a))jk=DFj(a)ek=∂zkFj(a). For n=1 the two conditions of [L1] and [L2] coincide.

Depends on

Used by

Cited to discharge well-definedness by Holomorphic maps ℂᵐ → ℂⁿ and the complex Jacobian matrix.

Dependency tree · two levels

93 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources