Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedjudge pass (gpt-5.6-terra)audited 2026-09-14
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The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

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Doob L1 maximal inequality

Statement

Assume AC. If X is a nonnegative submartingale, λ>0, and N∈N0, then λ P ⁣(max⁡0≤k≤NXk≥λ)≤E ⁣[XN1{max⁡k≤NXk≥λ}]≤EXN.

Facts & Assumptions

Given: The hypotheses, objects, and conventions in the Statement.

[F1]

Martingale submartingale and supermartingale makes each first-crossing event measurable at its crossing time.

[F2]

Multistep martingale characterization gives Xk≤E[XN∣Fk] for k≤N.

[F3]

Conditional expectation as an ae class supplies the integral identity on Fk events, and The Lebesgue integral is linear on L1(μ) sums the finite partition.

[F4]

The Axiom of Choice is used only through the chosen conditional-expectation representatives in F2, F3.

Proof

1.1F1

Define the disjoint first-crossing events Ak={X0<λ,…,Xk−1<λ, Xk≥λ},0≤k≤N, with the preceding string empty for k=0. Each Ak∈Fk, and their union is A={max⁡j≤NXj≥λ}.

1.2F2F3

On Ak, Xk≥λ. By F2 and the conditional-expectation identity, λP(Ak)≤E[Xk1Ak]≤E[XN1Ak].

2.1F3F4step 1.1step 1.2∎

Sum over the finite disjoint partition to get λP(A)≤E[XN1A]. Since XN≥0, the latter is at most EXN. This finite-time proof does not presuppose stopping-time or optional-sampling results. AC has exactly the inherited use in F4.

Depends on

Used by

Dependency tree · two levels

19 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources