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TheoremStatement: AI-adaptedProof: AI-adaptedprecheck passaudited 2026-08-11
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A region between two continuous graphs is Jordan measurable, and a continuous integrand extending to its closure integrates by vertical sections

Statement

Let a<b, let α,β:[a,b]→R be continuous with α≤β, and put K:={(x,y):a≤x≤b, α(x)≤y≤β(x)}. Then K is compact and Jordan measurable. If a function on the open region between the graphs extends to a continuous H:K→R, then H is Riemann integrable over K and ∫KH=∫ab(∫α(x)β(x)H(x,y) dy)dx. The formula includes coincident graphs and uses the continuous extension on the boundary.

Facts & Assumptions

Given: Continuous α≤β on [a,b], the closed region K, and a continuous H:K→R.

[L1]

Jordan--Fubini integrates a bounded integrable function over a Jordan set by its Jordan sections (Fubini over a bounded Jordan set when all but a content-zero family of sections are integrable).

[L2]

A metric-bounded set is Jordan measurable if and only if its boundary is null, equivalently content zero (A bounded set in Rm is Jordan measurable iff its boundary is null, equivalently of content zero).

[L3]

The graph of a continuous real function on a compact Jordan domain has content zero (The graph of a continuous function on a closed nondegenerate rectangle in Rm has content zero in Rm+1).

[L4]

A continuous real function on a compact Jordan set is Riemann integrable there (A continuous real function on a compact Jordan measurable set is Riemann integrable over that set).

Proof

technique · direct
1.1

The boundary of K is contained in the graphs of α and β together with the two vertical endpoint segments. Each is a continuous graph, after exchanging coordinates for the vertical segments, and hence has content zero by [L3]. The set K is closed and bounded, hence compact by [L5], and [L2] makes it Jordan measurable.

L2L3L5given
2.1

The continuous H is integrable on the compact Jordan set by [L4]. Every vertical section is the closed interval [α(x),β(x)], and its restriction is continuous, so [L1] gives the displayed formula.

L1L4step 1.1
3.1

If α(x)=β(x), that section is degenerate and contributes 0; the endpoint sections and all other boundary changes have content zero. Requiring a continuous extension to K supplies boundedness and integrability that continuity only on the open region would not supply.

step 2.1algebra∎

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