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Green’s coproduct is an algebra map into the twisted tensor completion

Statement

For a finite-field hereditary Hall category, products of Green images converge coefficientwise and Δ′([M]⋆[N])=Δ′([M])⋅Δ′([N]) in the completion of The Green Hall completion and coproduct, where the target multiplication is the stated Euler-twisted tensor multiplication. The coproduct is coassociative and counital by The Green Hall coproduct is coassociative. It is not asserted that the whole completion is an algebra.

Facts & Assumptions

Given: A finite-field hereditary Hall category and basis objects M,N.

[F1]

The basis formulas for Δ′, the twisted Hall product and twisted tensor multiplication are those of The Green Hall completion and coproduct.

[F2]

Products Δ′([M])⋅Δ′([N]) have finite coefficient sums (Products of Green coproducts converge coefficientwise).

[F3]

The cross–square identity holds for the four external objects (The Green cross–square counting identity).

[F4]
[F5]

Endpoint-labelled exact-sequence counts and Hall numbers satisfy PA,BR=aAaBgA,BR (Exact-sequence counts equal endpoint automorphism counts times subobject counts).

Proof

technique · direct coefficient comparison
1.1F1given

Fix output objects K,L. From [F1], the coefficient of [K]⊗[L] in Δ′([M]⋆[N]) is ν⟨M,N⟩+⟨K,L⟩aMaN∑[J]PM,NJPK,LJaJ. The sum is finite because only middle terms of extensions of M by N occur.

1.2F1F2F5algebra

In Δ′([M])⋅Δ′([N]), denote the decompositions of M by (K2,L2) and those of N by (K1,L1). The Hall products in the two tensor factors contribute PK2,K1K and PL2,L1L. Consequently the coefficient of [K]⊗[L] is 1aMaN∑K1,K2,L1,L2νEPK2,L2MPK1,L1NPK2,K1KPL2,L1LaK1aK2aL1aL2, where E=⟨K2,L2⟩+⟨K1,L1⟩+(L2,K1)+⟨K2,K1⟩+⟨L2,L1⟩. The summation is finite by [F2]. Converting each Hall coefficient to the endpoint-labelled sequence normalization uses [F5].

2.1F4step 1.2algebra

Each nonzero summand in step 1.2 has [M]=[K2]+[L2], [N]=[K1]+[L1], [K]=[K2]+[K1] and [L]=[L2]+[L1]. Expanding the two desired Euler exponents by [F4] gives ⟨M,N⟩+⟨K,L⟩=E+2⟨K2,L1⟩. All terms in the expansion occur once in E except the two displayed copies of ⟨K2,L1⟩.

3.1F3F4step 1.1step 1.2step 2.1algebra

By [F3], the weighted square count in step 1.2 with factor ∣YExt⁡1(K2,L1)∣/∣Hom⁡(K2,L1)∣ equals the cross count in step 1.1. By [F4] and finite-dimensionality, ∣YExt⁡1(K2,L1)∣∣Hom⁡(K2,L1)∣=q−⟨K2,L1⟩=ν−2⟨K2,L1⟩. Thus the exponent E in step 1.2 contributes exactly ν⟨M,N⟩+⟨K,L⟩ times the required Ext/Hom ratio. Substitution of the identity [F3] makes the coefficients in steps 1.1 and 1.2 equal.

4.1F2step 3.1algebra∎

Equality holds at every output basis pair, proving multiplicativity on basis elements. Bilinearity and finite support of Hall products extend it to all finite Hall vectors. Coefficientwise convergence is [F2], and coassociativity and the counit are supplied by the flag proof in The Green Hall coproduct is coassociative.

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