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Higher eigenvalues by orthogonality-constrained minimisation

Statement

Assume the Axiom of Choice, the ultrafilter lemma, DC and HB (The Axiom of Choice, The ultrafilter extension principle (UL/BPI), The axiom of dependent choice: a relation in which every element is related to something admits an N-indexed chain, The real dominated-extension principle as an additional hypothesis over ZF). Let n≥1, let Ω⊆Rn be a nonempty bounded open set, let λ1≤λ2≤⋯ and {ej} be the eigenvalues and orthonormal eigenbasis of the real Dirichlet Laplacian, supplied by Discrete spectrum of a symmetric elliptic Dirichlet operator with a0(v,w)=∫ΩDv⋅Dw (The L2 operator associated with a symmetric elliptic form, Symmetric elliptic weak eigenpairs, The notation Hk and the reserved zero-boundary symbol), and fix k≥2. Put Sk={u∈H01(Ω;R):∥u∥L2=1, (u,ej)L2=0 for j<k} and E(u)=∫Ω∣Du∣2 (Zero-boundary Sobolev space as a norm closure, Integer-order Sobolev spaces and their norms, The space Lp(μ) as the quotient by null functions, Orthogonality and the orthogonal complement). Then Sk is nonempty, E attains its infimum μk on Sk, every minimiser is a weak eigenpair with eigenvalue μk, and μk=λk (eigenvalues counted with multiplicity); moreover every minimiser lies in the eigenspace Eλk and is orthogonal in L2 to e1,…,ek−1.

Facts & Assumptions

Given: A nonempty bounded open set Ω⊆Rn, the principal Dirichlet form a0(v,w)=∫ΩDv⋅Dw with its eigenvalue list λ1≤λ2≤⋯ and orthonormal eigenbasis {ej}j≥1 of L2(Ω), an index k≥2, the set Sk and the energy E(v)=a0(v,v).

[F1]

Specialise the spectral theorem to the real form a0(v,w)=∫ΩDv⋅Dw (identity principal coefficients, zero drift and potential). Discrete spectrum of a symmetric elliptic Dirichlet operator, Symmetric elliptic weak eigenpairs, The L2 operator associated with a symmetric elliptic form: each ej lies in H01(Ω) with ∥ej∥L2=1, a0(ej,v)=λj(ej,v)L2 for every v∈H01(Ω), the list is nondecreasing, and {ej} is a Hilbert basis of L2(Ω) (Orthonormal families, complete orthonormal systems and Hilbert bases).

[F2]

Zero-boundary Sobolev space as a norm closure, Hk is a Hilbert space under the derivative-sum inner product, A closed subspace of a Banach space is Banach: H01(Ω) is a closed subspace of H1(Ω)=W1,2(Ω), hence a real Banach space, and under HB its closed subspace of the reflexive space W1,2(Ω) is reflexive (W^{1,p}(Omega) is reflexive for 1<p<infinity, Closed subspaces of reflexive spaces are reflexive, Reflexivity is surjectivity of the canonical map).

[F3]

Convex and strictly convex functionals on a convex subset of a real vector space, A convex norm-lower-semicontinuous functional is weakly lower semicontinuous: E is convex and continuous on H01(Ω) and therefore weakly sequentially lower semicontinuous on every nonempty convex subset (Axiom of Choice through the convex closedness lemma).

[F4]

A bounded sequence in a reflexive Banach space has a weakly convergent subsequence: under the ultrafilter lemma, DC and HB every norm-bounded sequence in a real reflexive Banach space has a weakly convergent subsequence.

[F5]

Weak H^1 convergence plus Rellich preserves the L^2 unit normalisation: for bounded open Ω, if (vj)⊆H01(Ω) is norm bounded with vj⇀v and ∥vj∥L2=1, then ∥v∥L2=1.

[F6]

Smooth compactly supported functions of an open set are dense in L2, The space Lp(μ) as the quotient by null functions: H01(Ω) is dense in L2(Ω); hence an L2 class orthogonal to H01(Ω) is zero. For each j the functional Lj(v):=(v,ej)L2 is bounded on H01(Ω) because ∥v∥L2≤∥v∥H01, so vj⇀v in H01(Ω) implies Lj(vj)→Lj(v).

[F7]

The Lagrange multiplier rule for finitely many regular constraints, Fréchet derivative between Banach spaces: for a real Banach space X, open U⊆X, I:U→R Fréchet differentiable at u and G:U→Rm of class C1 with DG(u) surjective, a local extremum of I on the level set {G=G(u)} admits a unique λ∈Rm with DI(u)=∑iλiDGi(u); the Axiom of Choice is consumed here.

[F8]

Eigenfunctions for distinct symmetric elliptic eigenvalues are L2-orthogonal: weak eigenfunctions of the symmetric case with distinct eigenvalues are L2-orthogonal.

Proof

technique · direct

Given: The spectral data and the set Sk above.

1.1givenF1

By [F1] the function ek has ∥ek∥L2=1 and (ek,ej)L2=0 for j<k, so ek∈Sk: the set Sk is nonempty and μk:=inf⁡SkE≤E(ek)=a0(ek,ek)=λk∥ek∥L22=λk<∞.

1.2F2F3F6

By [F2] the space H01(Ω) is a real reflexive Banach space, by [F3] the energy E is weakly sequentially lower semicontinuous on H01(Ω), and by [F6] each constraint functional Lj, j<k, is bounded on H01(Ω).

2.1step 1.1step 1.2F4

Since 0≤μk<∞, DC supplies a sequence vj∈Sk with E(vj)<μk+1/j for j≥1, so E(vj)→μk. Since ∥vj∥L2=1 and E(vj)≤λk+1 for all large j, one has ∥vj∥H012=1+E(vj)≤λk+2; by [F4] some subsequence satisfies vjl⇀v0 in H01(Ω).

3.1step 2.1F5F6

The limit stays constrained: [F5] applied to the subsequence gives v0∈H01(Ω) and ∥v0∥L2=1, while for every j<k the bounded functional Lj of [F6] gives (v0,ej)L2=lim⁡l(vjl,ej)L2=0. Hence v0∈Sk.

4.1step 1.2step 2.1step 3.1F3

By weak lower semicontinuity [F3] we get E(v0)≤lim inf⁡lE(vjl)=μk, and v0∈Sk gives E(v0)≥μk; hence E(v0)=μk, so E attains its infimum on Sk.

5.1step 4.1F1F6F7

Let v0∈Sk be any minimiser and define G:X→Rk on X=H01(Ω) by G(u)=(∥u∥L22−1,(u,e1)L2,…,(u,ek−1)L2); then {G=0}=Sk={G=G(v0)}, E and G are Fréchet differentiable at v0 with DE(v0)h=2∫ΩDv0⋅Dh and DG(v0)h=(2(v0,h)L2,(h,e1)L2,…,(h,ek−1)L2), because the remainders are ∫Ω∣Dh∣2 and the pairings ∫Ωh2. Surjectivity is explicit: DG(v0)(v0/2)=(1,0,…,0) and DG(v0)ej is the standard coordinate vector with its 1 in position j+1, for j<k, using orthonormality and the constraints. The derivative formula holds at every u∈X, its first component varies by at most 2∥u−v∥L2∥h∥L2≤2∥u−v∥H1∥h∥H1, and its other components are constant bounded functionals. Hence G is C1 with surjective derivative at v0, and [F7] gives unique multipliers α,η1,…,ηk−1∈R with 2a0(v0,h)=2α(v0,h)L2+∑j<kηj(h,ej)L2 for every h∈H01(Ω).

6.1step 4.1step 5.1F1

Test the identity of step 5.1 at h=ej with j<k. Symmetry and [F1] give 2a0(v0,ej)=2λj(v0,ej)L2=0, whereas its right-hand side is ηj by the constraints and orthonormality, so ηj=0. Testing at h=v0 gives 2E(v0)=2α∥v0∥L22, so α=μk. Therefore a0(v0,h)=μk(v0,h)L2 for every h∈H01(Ω), and every minimiser is a weak eigenpair with eigenvalue μk.

7.1step 3.1step 6.1F1F8

It remains to identify μk with λk; already μk≤λk by step 1.1. Suppose μk<λk: for every j≥k one has λj≥λk>μk, so the eigenfunctions v0 and ej have distinct eigenvalues and [F8] gives (v0,ej)L2=0; for j<k the same holds because v0∈Sk. Thus v0 is L2-orthogonal to every element of the Hilbert basis {ej} [F1], so v0=0 in L2, contradicting ∥v0∥L2=1. Hence μk=λk.

8.1step 3.1step 4.1step 6.1step 7.1F1F2F4F3F7F8∎

Consequently μk=λk, every minimiser is a weak eigenpair with eigenvalue λk by step 6.1 and therefore lies in the eigenspace Eλk, and by membership in Sk it is L2-orthogonal to e1,…,ek−1. The Axiom of Choice enters through the convex-lower-semicontinuity and multiplier suppliers [F3, F7], Countable Choice through the orthogonality corollary [F8] (it follows from the assumed DC via Dependent choice implies countable choice), and the ultrafilter lemma, DC and HB through the weak-compactness and reflexivity suppliers [F2, F4].

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