TheoremStatement: Literature-sourcedProof: AI-adaptedSession-authored (Fable 5 assisted)precheck passaudited 2026-08-29

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Comparable primes with the same contraction are equal under an integral map

Statement

Let $f : A \to B$ be an integral ring map, and let $q_{1} \subseteq q_{2}$ be prime ideals of $B$ with $f^{- 1} (q_{1}) = f^{- 1} (q_{2}) = p$ . Then $q_{1} = q_{2}$ .

Facts & Assumptions

Given: An integral ring map $f : A \to B$ and prime ideals $q_{1} \subseteq q_{2}$ of $B$ with common contraction $p \subseteq A$ .

[L1]

Integrality is preserved by localisation (Integrality and integral closure commute with localisation).

[L2]

The localisation $A_{p}$ is local with maximal ideal $p A_{p}$ ( $R_{p}$ is local with unique maximal ideal $p R_{p}$ ).

[L3]

Prime ideals of a localisation correspond exactly to primes disjoint from the denominator set, with strict inclusions preserved (Prime ideals of a localization are exactly the primes disjoint from the denominator set).

[L4]

In an integral extension, a prime upstairs is maximal if and only if its contraction is maximal (Under an integral extension, a prime is maximal if and only if its contraction is maximal).

Proof

technique · direct

1.1

Let $S : = A ∖ p$ . By [L3], the primes $q_{1}$ and $q_{2}$ correspond to primes $S^{- 1} q_{1} \subseteq S^{- 1} q_{2}$ of $S^{- 1} B$ , and by [L1] the localized map $A_{p} \to S^{- 1} B$ remains integral.

L1L3given

2.1

By [L2], the contraction of each $S^{- 1} q_{i}$ to $A_{p}$ is the maximal ideal $p A_{p}$ . Therefore [L4] makes both $S^{- 1} q_{1}$ and $S^{- 1} q_{2}$ maximal ideals of $S^{- 1} B$ . Since one is contained in the other, they are equal.

L2L4step 1.1

3.1

Applying the inverse bijection of [L3] to the equality of step 2.1 gives $q_{1} = q_{2}$ .

L3step 2.1∎

Depends on

Used by

Dependency tree · two levels

18 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources

Allen B. Altman and Steven L. Kleiman, A Term of Commutative Algebra, 13th ed., Theorem (14.3)(2) (standard reference, not scraped)
J. S. Milne, A Primer of Commutative Algebra, v4.03, Corollary 7.4 (standard reference, not scraped)