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Integral triangular decomposition and freeness of the Lusztig form

Statement

Assume the Axiom of Choice, inherited through the crystal/global-basis and generic/classical PBW-rank suppliers. Let UA be the Lusztig divided-power integral form of The Lusztig divided-power integral form UA, with its parts UA−,UA0,UA+ over A=Z[q,q−1]. Then:

(i) multiplication UA−⊗AUA0⊗AUA+→UA is an isomorphism;

(ii) the two divided-power halves are free A-modules with finite free root components of the classical PBW ranks;

(iii) the unmodified torus has the A-basis Kc∏iKiδiTi,0,ti with δi∈{0,1} and c running over a system of representatives of P∨/∑iZ(dihi); hence UA is free, and the degree-β component is ⨁α−γ=βUA−[−γ]⊗AUA0⊗AUA+[α];

(iv) unique coefficients refer to products of chosen basis elements, not to arbitrary sums of simple tensors.

Facts & Assumptions

Given: The divided-power form UA⊆Uq(g) with its half and toral parts, the skew derivations of the halves, and the toral elements Kh,Ti,c,t of The Lusztig divided-power integral form UA.

[F1]

Divided-power identities (Divided-power multiplication, toral binomials and the Ei(a)Fi(b) reordering identity): E(a)E(b)=(a+ba)iE(a+b) and F(a)F(b)=(a+ba)iF(a+b); the toral binomials reorder past Ei,Fi by index shifts; and every element of UA is a finite A-linear combination of products b−ub+ with b−∈UA−, u∈UA0, b+∈UA+, i.e. multiplication from the tensor product is surjective.

[F2]

Integral negative-half basis (The highest weight and negative half integral crystal triples are balanced, Bar invariance, congruence and uniqueness of the lower global basis): the lower global basis G∞(B(∞)) is an A-basis of UA−, and each finite root component UA−[−γ] is a free A-module of rank dim⁡Q(q)Uq−[−γ]. The positive half is carried to the negative half by the algebra isomorphism ι:Ei↦Fi of The Drinfeld pairing between the positive and negative quantum halves, so UA+ is free with finite free root components as well.

[F3]

Unmodified integral torus (The unmodified integral torus has a quantum-binomial basis, The quantum Pascal recurrences, the Gauss product formula and Gaussian integrality): the displayed family Kc∏iKiδiTi,0,ti is an A-basis of UA0, with Gaussian-integral coefficients and Laurent-extremal independence.

[F4]

Field triangular decomposition (Triangular decomposition of a quantized enveloping algebra, and the Drinfeld–Jimbo decomposition display (1.7) of Jeong–Kang–Kashiwara, §1, printed p. 6): the natural map Uq−⊗Q(q)Uq0⊗Q(q)Uq+→Uq(g) is an isomorphism of Q(q)-vector spaces, with homogeneous components of the stated shape.

[F5]

Classical PBW ranks (Generic quantum Serre halves have classical PBW ranks and a nondegenerate Hopf pairing): the field dimension of each homogeneous component of the generic quantum half equals the classical PBW rank dim⁡CU(n±)[±α]; this identification carries that theorem's stated Choice hypothesis, in addition to the inherited crystal/global-basis use of [F2].

[C1]

Choice: the Axiom of Choice is inherited through the crystal/global-basis suppliers of [F2] and the rank supplier [F5], as declared in The Axiom of Choice; the explicit tensor, localization and toral-basis computations add no choice use.

Proof

technique · direct
1.1F2F3

Freeness of the factors. By [F2] the negative half is a direct sum of free A-modules UA−[−γ] of finite rank; by the transport ι the same holds for UA+; and by [F3] the unmodified torus UA0 has the displayed A-basis. Each factor is therefore a free A-module, and the half factors have finite free root components; the toral degree-zero component can have infinite rank.

1.2F1

Surjectivity of the multiplication map. The spanning statement of [F1] says that every element of UA is a finite A-linear combination of products b−ub+; grouping the factors according to root degree exhibits UA as the image of UA−⊗AUA0⊗AUA+→UA, so the map is surjective.

2.1F4step 1.1step 1.2

Injectivity by field decomposition and torsion-freeness. Extending scalars along A↪Q(q) gives the field multiplication map, which is an isomorphism by [F4]. If x lay in the kernel of the integral map, its image in Uq−⊗Uq0⊗Uq+ would lie in the kernel of the field isomorphism after extension and hence would be 0; but the source is a free, hence torsion-free, A-module, so the natural map from it to its Q(q)-extension is injective, forcing x=0. Thus the multiplication map is an isomorphism, proving (i).

3.1F3step 2.1

Toral basis, freeness and the homogeneous form. Statement (iii) is the combination of the toral basis [F3] with the factorization of step 2.1; since a tensor product of free modules is free, UA is free, and restricting the isomorphism to homogeneous components gives the displayed degree-β decomposition, with UA0 contributing only degree 0. Unique coefficients are those of the products of the chosen basis elements of the three factors, not of arbitrary sums of simple tensors, because the isomorphism is one of A-modules with the displayed direct-sum decomposition.

4.1F2F5step 3.1C1∎

Ranks and conclusion. The ranks of the half components are their field dimensions by [F2]; by [F5], applied with its stated Choice hypothesis [C1], those dimensions equal the classical PBW ranks, proving (ii). Steps 1.1–3.1 prove (i), (iii) and (iv); no torsionfree-to-free conversion over the non-PID ring A and no modified dot-U basis was used, since freeness came from explicit bases.

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