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TheoremStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedprecheck passjudge pass (gpt-6-luna)
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Regular decomposition of zero-tangential H(curl) fields

Statement

Assume the Axiom of Choice. Let Ω⊂R3 be a nonempty bounded contractible Lipschitz polyhedron with connected boundary. For every u∈H0(curl⁡;Ω) there are z∈H01(Ω;R3) and p∈H1(Ω) such that u=z+∇p,∥z∥H1(Ω)+∥p−pΩ∥H1(Ω)≤CΩ∥u∥H(curl⁡;Ω). Here H0(curl⁡) is the closure definition of Zero tangential trace H(curl) space, and pΩ=∣Ω∣−1∫Ωp fixes the additive constant. The constant may depend on the domain but not on a mesh.

Facts & Assumptions

Given: AC and exactly the domain and zero-tangential field of the Statement. The stronger full Dirichlet supplier below applies to this domain without changing its stated hypotheses.

[F1]

A bounded regular decomposition with both summands satisfying full Dirichlet conditions gives z∈H01(Ω;R3) and q∈H01(Ω) with u=z+∇q and ∥z∥H1+∥q∥H1≤CΩ∥u∥H(curl⁡).

Proof

1.1F1construct

Apply [F1] and set p=q. This supplies the required vector and scalar spaces and the identity, with the original domain, topology, and connected-boundary clauses retained. The proof of [F1] uses only a scalar H2 extension and an explicitly proved Fourier split; it imports no H(curl) extension theorem and no smooth-to-weak cohomology identification.

2.1F1step 1.1algebra∎

By Holder, ∣pΩ∣∣Ω∣1/2≤∥p∥2, whence ∥p−pΩ∥H1≤2∥p∥H1. Combine this with [F1] and absorb the numerical factor into CΩ to obtain the asserted estimate. The construction in [F1] fixes p∈H01; the present statement only requires H1, so its complete original scalar freedom is retained.

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Sources