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Adjoint graph inf-sup for ultraweak Poisson on connected Lipschitz polyhedra

Statement

Assume Countable Choice. For every bounded connected Lipschitz polyhedron Ω⊂Rd, d∈{2,3}, and every finite conforming shape-regular simplicial mesh, give U its L2/global-quotient product norm and V the full broken graph norm of Ultraweak Poisson DPG spaces and plan-consistent bilinear form. With C∗ from A topology-free bounded lifting of every ultraweak Poisson load, the primal and adjoint bounds are sup⁡y≠0∣b(x,y)∣∥y∥V≥C∗−1∥x∥U,sup⁡x≠0∣b(x,y)∣∥x∥U≥C∗−1∥y∥V. Both constants are independent of the mesh. The bounded operator B:U→V′ and its Riesz trial-to-test map T:U→V are boundedly invertible, with inverse norms at most C∗. No simple-connectivity or connected-boundary hypothesis is required; connected polyhedra with holes are included.

Facts & Assumptions

Given: Countable Choice, the stated connected Lipschitz polyhedron and finite mesh, and the exact real trial/test norms and bilinear form.

[A1]

Countable Choice is the hypothesis for the Hilbert and Riesz interfaces used below. (The Axiom of Countable Choice (ACω))

[F1]

The product trial and broken test spaces are real Hilbert spaces: their L2 factors, global trace quotient ranges, H(div⁡) factors and H1 factors have the stated real Hilbert structures. (L2 with the integral pairing is a Hilbert space, Ultraweak Poisson skeleton spaces are Hilbert trace quotients, H(div) is Hilbert and H0(div) is closed, The Sobolev space H1 is a Hilbert space)

[F2]

The real bilinear form defines a bounded operator B:U→V′ with ∣b(x,y)∣≤5∥x∥U∥y∥V. (The ultraweak Poisson DPG bilinear form is bounded)

[F3]

The trial operator has trivial kernel: Bx=0 implies x=0. (The ultraweak Poisson trial operator has trivial kernel)

[F4]

There is a linear R:V′→U with BR=IV′ and ∥R∥≤C∗. (A topology-free bounded lifting of every ultraweak Poisson load)

[F5]

The real Hilbert Riesz map JV:V→V′ is an isometric linear bijection. (Riesz representation for Hilbert spaces)

[F6]

The formulation fixes the five signs of b, the real trial/test spaces and the full broken graph norm. (Ultraweak Poisson DPG spaces and plan-consistent bilinear form)

Proof

1.1A1F2F3F4F6givenalgebra

The bounded form [F2] defines B, and [F4] makes B onto. By [F3], B is injective. For each x∈U, B(RBx−x)=BRBx−Bx=0, so injectivity gives RBx=x. Therefore B−1=R, ∥x∥U≤C∗∥Bx∥V′, and the dual norm identity ∥Bx∥V′=sup⁡y≠0∣b(x,y)∣/∥y∥V gives the primal bound.

2.1F1F4F5step 1.1algebra

For y≠0, set F=JVy and x=RF. Then Bx=F, so b(x,y)=F(y)=∥y∥V2, while [F4] and [F5] give ∥x∥U≤C∗∥F∥V′=C∗∥y∥V. Since F≠0, x≠0, and this x proves the adjoint bound; for y=0 the bound is immediate.

3.1F1F2F4F5F6step 1.1step 2.1algebra∎

Define T=JV−1B. By [F2], ∥T∥≤5. Since B−1=R, T−1=RJV and [F4] and [F5] give ∥T−1∥≤C∗. The lifting constant depends only on a fixed-domain Poincaré constant, so both graph inf-sup bounds are uniform over the stated mesh family; the construction uses no simple-connectivity or connected-boundary condition.

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