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Ultraweak Poisson skeleton spaces are Hilbert trace quotients

Statement

Assume Countable Choice and Ultraweak Poisson DPG spaces and plan-consistent bilinear form. The elementwise trace map Γ0:H01(Ω)→∏KH1(K)/H01(K) and normal-trace map Γn:H(div;Ω)→∏K(H1(K)/H01(K))′ have real Hilbert quotient ranges with global lift infimum norms. These equal the infima over broken extensions whose gluing belongs to the respective global space. Compatibility means membership in these ranges, so normal traces are conservative on each interior facet in the weak distributional sense.

Facts & Assumptions

Given: The finite mesh, trace maps, Countable Choice.

[A1]

Countable Choice is declared for trace interfaces. (The Axiom of Countable Choice (ACω))

[F1]

H(div) is Hilbert and its zero-trace subspace is closed. (H(div) is Hilbert and H0(div) is closed)

[F2]

Cell weak normal traces are continuous. (Weak normal trace by Green duality)

[F3]

Cell scalar traces are bounded in H1. (H1 facet trace inequality on shape-regular simplices)

[F4]

Global H1 traces agree on interior facets. (H1 traces agree across interior mesh facets)

[F5]

The formulation fixes the trace ranges and lift norms. (Ultraweak Poisson DPG spaces and plan-consistent bilinear form)

[F6]

Real L2 with its integral inner product is a Hilbert space. (L2 with the integral pairing is a Hilbert space)

[F7]

H1 functions and their first derivatives are L2 classes defined by distributional derivatives; H1_0 is the stated closure. (Integer-order Sobolev spaces and their norms, Zero-boundary Sobolev space as a norm closure)

[F8]

A global H(div) field has an L2 distributional divergence, so for every ϕ∈Cc∞(Ω), ∫Ω(τ⋅∇ϕ+(div⁡τ)ϕ)=0. (The real H(div) space)

Proof

1.1A1F1F2F5F6F7algebra

H1 is complete: completeness of real L2 [F6] gives limits in L2 of a Cauchy sequence and each weak derivative satisfy distributional derivative identities by testing against compactly supported smooth functions and passing both integrals to their limits. H1_0 is closed by its closure definition. The scalar trace-quotient map is continuous because ∥[u∣K]∥H1(K)/H01(K)≤∥u∣K∥H1(K) on each cell; the finite product preserves continuity. The normal map is continuous by [F2], again with a finite product. Thus both kernels are closed.

1.2F2F8givenconstructalgebra

Let τ∈H(div⁡;Ω) and let an interior facet F=K+∩K− be fixed. For ψ∈Cc∞(relint⁡F), choose a smooth function ϕ∈Cc∞(Ω) supported in a small tubular neighborhood of supp⁡ψ meeting only K+ and K− and having trace ψ on F. The global distributional-divergence identity [F8] gives ∫Ω(τ⋅∇ϕ+(div⁡τ)ϕ)=0. Applying the cell Green identity [F2] to the two restrictions, with all other cell traces zero, yields ⟨γn+,K+(τ∣K+),[ϕ∣K+]⟩+⟨γn−,K−(τ∣K−),[ϕ∣K−]⟩=0. The two cell trace classes in this equation restrict to the same ψ on F and vanish on the other facets. Since this holds for every such ψ, the two outward weak normal traces cancel as distributions on the relative interior of each interior facet. This is the conservative facet relation for a global H(div) lift; it uses the distributional divergence identity and weak Green formula, not pointwise normal values.

2.1A1F1step 1.1algebra

For a closed subspace M of a Hilbert space, a distance-minimizing sequence is Cauchy by the parallelogram identity; its limit is nearest, and variation along M makes the residual orthogonal. Thus H=M⊕M⊥ and H/M is isometric to M⊥. Applying this to both kernels in step 1.1 proves the quotient ranges are Hilbert with their infimum norms.

3.1F2F3F4F5step 2.1step 1.2algebra∎

Global lifts restrict to broken lifts; conversely the admissible broken extensions in the Statement are exactly those gluing to a global lift, so the two infima have the same set. Cell scalar traces are bounded by [F3] and those of a global H1 lift match across interior facets by [F4]; normal traces of a global H(div) lift satisfy the cancellation proved in step 1.2. Thus range membership is precisely the stated compatibility, with the global lift infimum norms.

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