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Periodic PIC deposition conserves charge and satisfies Poisson compatibility

Statement

For positions X1,…,XP∈TLd and real charges q1,…,qP, define Q=∑pqp and an admissible algebraic assignment shape wj as in Periodic PIC deposition shape and gather operators. Then hd∑j∈JNh−d∑p=1Pqpwj(Xp)=Q. Consequently the neutralized source ρj(X)=h−d∑pqpwj(Xp)−Q/Ld has mean zero and is in the range of the periodic Poisson operator; it therefore has a unique mean-zero potential for the gauge ϕˉ=0 by Periodic centered-difference Poisson solvability and zero-mean gauge.

Facts & Assumptions

Given: The finite periodic grid, particle positions and charges, the normalized assignment shape, and the periodic Poisson operator.

[F1]

Periodic PIC deposition shape and gather operators: ρj=h−d∑pqpwj(Xp)−Q/Ld, and an algebraic assignment has nonnegative weights.

[F2]

Periodic PIC deposition shape and gather operators: every algebraic assignment shape satisfies ∑jwj(x)=1 for every particle location.

[F3]

Periodic centered-difference Poisson solvability and zero-mean gauge: the range of Ah is exactly the zero-mean grid subspace, and every zero-mean source has a unique mean-zero solution.

Proof

1.1givenF1F2algebra

Before subtracting the background, sum the assigned density with cell volume. Since the sum is finite, interchange its particle and grid sums; [F2] gives hd∑jh−d∑pqpwj(Xp)=∑pqp∑jwj(Xp)=∑pqp=Q.

2.1F1step 1.1algebra

The background has total grid charge hd∣JN∣Q/Ld=LdQ/Ld=Q because hd∣JN∣=Ld. Hence ⟨ρ,1⟩h=0, equivalently ρˉ=0.

3.1F3step 2.1∎

By [F3], this zero-mean source has a solution and fixing its mean to zero selects exactly one potential.

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