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TheoremStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedprecheck passjudge pass (gpt-6-sol)audited 2026-09-30
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Projective morphisms are proper

Statement

Assume the Axiom of Choice. Every projective morphism in the finite-dimensional H-projective convention of this page is proper: if f:X→S factors over S as X→iPSn⟶S with n≥0, i a closed immersion and the second arrow the projection, then f is proper. The empty source, the empty base and the case n=0 are included, and no Noetherian, field, reducedness or nonemptiness hypothesis is imposed.

Facts & Assumptions

Given: The Axiom of Choice and a projective morphism f:X→S with a factorization X→iPSn→πS over S, where n≥0, i is a closed immersion and π is the projection.

[F1]

A morphism f:X→S is projective on this page if for some n≥0 it factors over S as X→iPSn→S with i a closed immersion; the relative projective space and its projection are those of the cited chart construction, and n=0 is allowed with PS0≅S. (Projective morphisms before Proj)

[F2]

Assume AC. For every scheme S and every n≥0 the projection PSn→S is proper. (Finite-dimensional projective space is proper over every base)

[F3]

Assume AC. Every closed immersion is finite, hence proper; the empty closed immersion is included. (Closed immersions are proper)

[F4]

Assume AC. A composite of proper morphisms is proper. (Properness survives composition)

[F5]

The Axiom of Choice states that every family of nonempty sets has a choice function. (The Axiom of Choice)

Proof

technique · direct: write $f$ as a closed immersion into a relative projective space followed by the projection, and compose the two proper morphisms
1.1F1

By [F1] the morphism f admits a factorization f=π∘i over S, where n≥0, i:X→PSn is a closed immersion and π:PSn→S is the projection of the relative projective space.

2.1F3step 1.1

By the AC-qualified [F3] the closed immersion i is finite, hence proper.

2.2F2step 1.1

By the AC-qualified [F2] the projection π:PSn→S is proper.

3.1F1F4step 2.1step 2.2

Since f=π∘i is a composite of the proper morphisms i and π, the AC-qualified [F4] shows that f is proper.

4.1F1F2F3F5step 3.1∎

This proves the theorem for the finite-dimensional H-projective convention fixed in [F1]; the separate projective-bundle convention of the sources is not treated here and is not claimed. The Axiom of Choice [F5] is assumed and is used only through [F2], [F3] and [F4]. The degenerate cases are included: for n=0 the projection is the isomorphism PS0≅S and f is the closed immersion i; if S=∅ then PSn=X=∅ and the morphisms are the empty ones; if i is the identity then f=π is the projection, proper by [F2]; and if X=∅ then i is the empty closed immersion, proper by [F3]. No Noetherian, field, reducedness or nonemptiness hypothesis is imposed.

Depends on

Used by

Dependency tree · two levels

39 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources