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Quantum bounded-expectation guarantee and query cost

Statement

Let g:X→[a,b] be exactly encoded with a≤b, let V be the coherent sampler of Coherent finite sampler and observable value, and let μ=∑xpxg(x). If a=b, the algorithm Amplitude-estimation expectation estimator returns a=μ exactly. If a<b, then for rational 0<ε≤b−a and 0<δ<1 it returns μ~ with ∣μ~−μ∣≤ε with probability at least 1−δ. Writing q=(μ−a)/(b−a) and M for its QA13 phase-register size, the median output also obeys ∣μ~−μ∣≤(b−a)(2πq(1−q)M+π2M2) with probability at least 1−δ in either declared QA13 access mode. For a<b, in repeated controlled-Q access it uses exactly r(M−1) controlled-Grover calls, where M and r are the current QA13 median-interface parameters. In this mode its controlled-sampler/reflection query count is O((b−a)ε−1(1+ln⁡(1/δ))) for all 0<δ<1, and O((b−a)ε−1ln⁡(1/δ)) when 0<δ≤1/2. If a=b, the algorithm returns a exactly with no quantum query.

For a<b, in supplied controlled-power access it instead uses exactly rm controlled-power queries, where M=2m; sum their separately declared costs over all r runs. No M−1 constituent-call expansion is inferred for a supplied power.

The query bound is an oracle statement. Every controlled or inverse sampler call, good-state reflection, initial-state reflection, rotation, arithmetic operation, state preparation, and classical order-statistic computation retains its separately supplied cost.

Facts & Assumptions

Given: The finite coherent sampler, exact finite value encoding, the bounded interval [a,b], the parameters ε,δ in the Statement, and either declared QA13 access mode. The controlled-sampler/reflection bound assumes repeated controlled-Q access.

[F1]

Coherent finite sampler and observable value supplies V∣0⟩=∑xpx∣x⟩∣g(x)⟩∣wx⟩ with unit work vectors; Measurement law of a coherent sampler proves sample outcome probability px.

[F2]

Amplitude-estimation expectation estimator computes q(x)=(g(x)−a)/(b−a), rotates a flag with good probability q(x), runs the QA13 median estimator, and returns a+(b−a)q~.

[F3]

Amplitude-estimation additive error and success probability: for a single QFT estimate and M≥4, ∣q~−q∣≤2πq(1−q)/M+π2/M2 with probability at least 8/π2.

[F4]

Median confidence amplification for amplitude estimation chooses the least power of two M≥88/(7η) for target η and the least positive odd r satisfying 2r≥(2/δ)8, then returns the median of r fresh runs.

[F5]

Explicit median confidence guarantee for amplitude estimation states that this median has additive error at most η with probability at least 1−δ.

[F6]

In repeated controlled-Q access, Median amplitude-estimation query cost gives exactly r(M−1) controlled-Q calls and its stated logarithmic query bounds. The median threshold also gives M<176/(7η).

[F7]

Chernoff bound for independent bernoulli trials gives Pr⁡(∣S−ES∣≥u)≤2e−2u2/r for a sum of r independent Bernoulli indicators.

[F8]

Rational bounds for pi used in finite schedules gives π<22/7 and 8/π2>98/121.

[F9]

The natural logarithm as the inverse of the exponential function defines the natural logarithm, and The natural logarithm has derivative 1/x and equals the integral from 1 to x of 1/t gives ln⁡2=∫12dt/t, hence 0<ln⁡2<1.

[F10]

Controlled Unitary Access and Inverse Unitary Access keep controlled and inverse calls explicit; Circuit-family and computation cost model separates oracle, gate, width, precision, and classical bit costs. Quantum query algorithm specifies fresh independent executions.

[F11]

Order, continuity, range, and the product, quotient, and reciprocal laws for the natural logarithm gives strict increase, ln⁡(xy)=ln⁡x+ln⁡y and ln⁡(1/x)=−ln⁡x for positive inputs. Iterating the product identity gives ln⁡(xn)=nln⁡x for a positive integer n. The natural logarithm as the inverse of the exponential function gives ln⁡(exp⁡u)=u.

[F12]

Amplitude-estimation query and precision complexity gives exactly m supplied controlled-power queries per QFT run at M=2m, with their separately declared costs.

Proof

1.1givenF1F2algebra

Since q(x)=(g(x)−a)/(b−a), the interval promise gives q(x)∈[0,1]. By [F1]–[F2], the good-flag probability after the controlled rotation is ∑xpxq(x)=(∑xpxg(x)−a∑xpx)/(b−a)=(μ−a)/(b−a)=q.

1.2givenF3F4

For one QAE run, [F3] gives the stated probability-error radius E=2πq(1−q)/M+π2/M2 with success at least 8/π2. Since fresh runs in [F4] are independent, if the median is outside [q−E,q+E], at least (r+1)/2 of their failure indicators are one.

1.3givenF3F4F6F10F12algebra

Suppose a<b. In repeated controlled-Q access, [F4] and [F6] give exactly r(M−1) controlled-Grover calls, M<176/(7η), and the stated logarithmic query bounds. Substitute η=ε/(b−a). In supplied controlled-power access, [F4] and [F12] give r runs of m power queries, hence exactly rm such queries with their declared costs summed. Neither access choice changes the ideal QFT output law in [F3]. The separate input-access costs in [F10] are not converted into gates without the supplied implementations.

2.1givenF7F8step 1.2algebra

Set p0=98/121. By [F8], each failure indicator has mean at most 1−p0. If S is their sum, the median-failure event entails S−ES≥r(p0−1/2). Applying [F7] to this containing event bounds its probability by 2e−cr, where c=2(75/242)2=5625/29282 and 8c>1.

3.1givenF4F9F11step 2.1algebra

Put L=ln⁡(2/δ)>0. Taking logarithms of the positive threshold 2r≥(2/δ)8 in [F4] and applying the product law repeatedly as in [F11] gives rln⁡2≥8L. Because 0<ln⁡2<1 by [F9], r>8L, and 8c>1 gives cr>L. By [F11], ln⁡(δ/2)=−L and ln⁡(e−cr)=−cr<−L, so strict increase implies 2e−cr<δ. Therefore the median error radius is at most E with probability at least 1−δ. The same event implies error at most η whenever M≥88/(7η) and 0<η≤1, because q(1−q)≤1/2, π/M≤η/4, and π2/M2≤η2/16≤η/16.

4.1givenF2F5step 3.1algebra

For the algorithm choose η=ε/(b−a)≤1. By [F2], ∣μ~−μ∣=(b−a)∣q~−q∣. The median guarantee [F5] gives the requested additive error; step 3.1 supplies the stronger radius, and multiplication by b−a gives the Statement.

5.1givenF1algebra∎

If a=b, the value is constant g(x)=a for every x, so μ=a by the probability normalization and the exact-return branch has zero error and zero quantum calls.

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