Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedprecheck passjudge pass (gpt-6-luna)
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Instrument outcome weights normalize

Statement

For a finite instrument (Ia)a∈Ω and a density operator ρ on its input space, the branch weights pa=tr⁡(Ia(ρ)) form a probability distribution on Ω.

Facts & Assumptions

Given: A finite instrument (Ia)a∈Ω and an input density operator ρ.

[F1]

Finite instruments and conditional states: each outcome map is completely positive and ∑atr⁡(Ia(X))=tr⁡(X) for every input operator X; pa=tr⁡(Ia(ρ)).

[F2]

Completely positive maps: complete positivity includes the r=1 extension, which is the original map and therefore preserves nonnegativity.

[F5]

Density operator: on a nonzero finite-dimensional complex inner-product space, a density operator is nonnegative and has trace one.

[F3]

A non-negative operator is equivalently self-adjoint with nonnegative eigenvalues, a positive semidefinite matrix in an orthonormal basis, or an operator of the form S^*S: a nonnegative operator has an orthonormal basis in which its matrix is diagonal with nonnegative real diagonal entries.

[F4]

The basis-independent trace of an endomorphism of a finite-dimensional vector space: trace is the basis-independent matrix trace of a finite-dimensional endomorphism.

[F6]

Non-negative and positive operators: a nonnegative operator is self-adjoint and has nonnegative quadratic form on every vector.

Proof

1.1givenF1F2F3F4F5F6

For each a, complete positivity [F1]–[F2] at r=1 sends the nonnegative input ρ from [F5] to a nonnegative τa:=Ia(ρ) in the sense of [F6]. By [F3], τa has nonnegative diagonal entries in an orthonormal basis, and [F4] therefore gives pa=tr⁡(τa)≥0.

1.2givenF1F5

Apply the trace-preservation identity in [F1] to X=ρ. It gives ∑a∈Ωpa=tr⁡(ρ)=1 by [F5]. Thus the nonnegative branch weights sum to one.

2.1step 1.1step 1.2algebra∎

For any a, 1−pa=∑b≠apb≥0 by step 1.1, including the empty sum when Ω={a}. Hence pa∈[0,1] for every outcome, and the weights form a finite probability distribution.

Depends on

Used by

Cited to discharge well-definedness by Finite instruments and conditional states.

Dependency tree · two levels

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Sources