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TheoremStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedjudge pass (gpt-6-luna)
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Simon query and output measurement produce a coset pair

Statement

For a Simon oracle with hidden nonzero string s, immediately after its one standard query the joint state is

2−n/2∑x∈{0,1}n∣x⟩∣f(x)⟩.

For each output value v in the image of f, the target Lüders instrument has probability 21−n and its conditional joint state factors as

∣x0⟩+∣x0⊕s⟩2⊗∣v⟩,

where x0 is either preimage of v. Outcomes outside the image have probability zero. Hence the address register conditional state is the normalized coset-pair vector shown above.

Facts & Assumptions

Given: A Simon oracle with n≥1, m≥n−1, and unique nonzero hidden string s.

[F1]

Simon hidden-XOR-period promise: every fiber is exactly one pair {x,x⊕s}, and s≠0.

[F2]

Standard bit-flip query convention: the ordinary oracle acts by Uf∣x⟩∣z⟩=∣x⟩∣z⊕f(x)⟩ on the ordered address and target bases.

[F3]

One Simon Fourier-sampling sample: the address is prepared uniformly by H⊗n, queried once, and the target is measured with the branch maps X↦PvXPv for Pv=I⊗∣v⟩⟨v∣.

[F4]

Finite projective measurements: a projective measurement is a finite family of pairwise orthogonal self-adjoint idempotents summing to the identity.

[F5]

Finite POVMs and their outcome law: a POVM is a finite family of nonnegative effects summing to the identity.

[F6]

A non-negative operator has a unique non-negative square root: every nonnegative operator has a unique nonnegative square root.

[F7]

The square-root Lüders maps form an instrument: for a finite POVM (Ev), the square-root maps X↦Ev1/2XEv1/2 form a finite instrument.

[F8]

Finite instruments and conditional states: an instrument assigns branch probability tr⁡(Iv(ρ)) and, on a positive branch, conditional state Iv(ρ)/tr⁡(Iv(ρ)).

[F9]

Instrument outcome weights normalize: for an input density operator, the branch weights of a finite instrument are nonnegative and sum to one.

[F10]

Ordered tensor registers, their inner product, and wire permutations: elementary tensor products use the displayed factor order and product inner product.

[F11]

The computational basis is orthonormal: each computational register basis is orthonormal.

[F12]

Dirac Notation Conversion: ∣w⟩⟨w∣ sends z to ⟨z,w⟩rootw.

[F13]

The basis-independent trace of an endomorphism of a finite-dimensional vector space: trace is the sum of diagonal entries in any finite-dimensional basis.

[F14]

Hadamard character sum on F_2^n: the tensor Hadamard sends ∣0n⟩ to the uniform vector 2−n/2∑x∣x⟩.

[F15]

A unit-vector outer product is a density operator: the outer product of a unit vector is a density operator.

Proof

1.1givenF2F3F10F11F14F15algebra

The Hadamard-character formula [F14] gives H⊗n∣0n⟩=2−n/2∑x∣x⟩. Applying [F2] to this vector and the zero target produces the displayed joint vector Ψ. Its 2n orthogonal terms all have squared coefficient 2−n by [F10]–[F11], so ∥Ψ∥=1 and ∣Ψ⟩⟨Ψ∣ is a density operator by [F15].

1.2givenF3F4F5F6F7F8

For each v, the maps in [F3] have projectors Pv. By [F10]–[F11], computational basis vectors are orthonormal, so the Pv are self-adjoint idempotents, pairwise orthogonal, and sum to the identity. Also ⟨Pvz,z⟩=⟨Pvz,Pvz⟩≥0, so these projectors form a POVM by [F4]–[F5]. The nonnegative square root of each projector is itself by [F6]; hence [F7] makes the branch maps a valid instrument with the probabilities and conditional states of [F8].

1.3givenF1F3F11constructalgebra

Fix v in the image and let x0 be one preimage. Set wv:=2−n/2(∣x0⟩+∣x0⊕s⟩)⊗∣v⟩. The post-query vector projected into branch v is 2−n/2∑x:f(x)=v∣x⟩∣v⟩=wv by [F1]. The two address basis vectors are distinct and orthonormal by [F1] and [F11].

2.1givenF3F12F13step 1.3algebra

The branch operator is the rank-one map ∣wv⟩⟨wv∣ for the projected vector wv in step 1.3. In the product basis its only nonzero diagonal entries are the two squared coefficients 2−n, by [F12]–[F13]. Thus the branch probability is tr⁡(∣wv⟩⟨wv∣)=21−n. An output outside the image has zero projected vector and therefore zero trace.

3.1givenF1F8F9F15step 1.3step 2.1algebra∎

Dividing the projected vector in step 1.3 by its norm 2(1−n)/2 gives the normalized conditional state in the Statement; it factors into an address vector and the fixed output basis vector ∣v⟩. Its rank-one outer product is a density operator by [F15], and its probability is positive, so it is the conditional state in [F8]. There are exactly 2n−1 image values by the fiber partition in [F1], and their probabilities sum to one as required by [F9].

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