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TheoremStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedprecheck passjudge pass (gpt-6.1-sol)audited 2026-10-02
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The Riemann-Hurwitz formula with the different

Statement

Assume the Axiom of Choice as inherited from the ramification and duality suppliers. Let f:C→D be a finite surjective morphism of smooth proper geometrically integral curves over a field k whose function-field extension k(C)/k(D) is separable (equivalently, a nonconstant morphism whose generic fibre is separable), with n=deg⁡(f) and different divisor Rf. Then 2g(C)−2=n (2g(D)−2)+deg⁡k(Rf), where g(C) and g(D) are the genera. Equivalently, for canonical divisors, KC is linearly equivalent to f∗KD+Rf, and the displayed identity is the degree identity obtained from it.

Facts & Assumptions

Given: A field k; a finite surjective morphism f:C→D of smooth proper geometrically integral curves whose function-field extension k(C)/k(D) is separable; n=deg⁡(f); the different divisor Rf on C.

[F1]

Under the separability hypothesis, the natural map f∗ωD→ωC has cokernel ΩC/D and there is a canonical isomorphism ωC≅f∗ωD⊗OC(Rf); equivalently KC is linearly equivalent to f∗KD+Rf for canonical divisors, where Rf is the different divisor. The different is defined by Rf=∑plp[p] with lp=length⁡OC,p(ΩC/D,p) a nonnegative integer vanishing exactly off the support of ΩC/D, so that Rf is an effective divisor supported on the differential ramification locus with lp≥ep−1. (Canonical bundle formula with the different, The different divisor of a generically separable morphism of curves)

[F2]

A nonconstant morphism of smooth proper geometrically integral curves is finite and surjective and has a positive degree n=deg⁡(f)=[k(C):k(D)]; for such a morphism, if E is a divisor on D then f∗E is defined and deg⁡k(f∗E)=ndeg⁡k(E), and for every invertible OD-module M one has deg⁡(f∗M)=ndeg⁡(M). (Nonconstant morphisms of proper curves are finite and surjective, Degree of a nonconstant morphism of curves, Fibres, pullbacks and degrees of divisors under a finite morphism of curves)

[F3]

For a smooth proper geometrically integral curve C of genus g(C) and any canonical divisor KC one has deg⁡k(KC)=2g(C)−2; likewise deg⁡k(KD)=2g(D)−2 on D. (The canonical divisor has degree 2g - 2, Canonical bundle and canonical divisors)

[F4]

On a smooth proper geometrically integral curve, divisors are finite sums of closed points with additive degree deg⁡k(D)=∑xnx[κ(x):k], the Weil and Cartier descriptions agree, and every invertible sheaf is OC(D) for a divisor D well defined modulo linear equivalence, so degrees of invertible sheaves are computed by deg⁡k of any associated divisor. (Divisors on a smooth proper curve, Degree divisor proper curve, Cartier and Weil divisors agree on a smooth curve)

[F5]

The Axiom of Choice: every family of nonempty sets has a choice function. (The Axiom of Choice)

Proof

Proof technique: direct; take the degree of the canonical ramification formula and evaluate with deg⁡ω=2g−2 on both curves.

1.1F1F2F4given

(Set-up.) By [F2] the morphism f is finite and surjective with n=deg⁡(f)=[k(C):k(D)]≥1, and pullback of divisors along f is defined with deg⁡k(f∗E)=ndeg⁡k(E) for divisors E on D; by [F1] the different Rf=∑plp[p] is an effective divisor on C determined by the lengths of the torsion module ΩC/D, and by [F4] divisors on C and D have additive degrees and any invertible sheaf has a well-defined degree given by any associated divisor.

2.1F1F4step 1.1

(Canonical formula.) Since k(C)/k(D) is separable, [F1] provides the isomorphism ωC≅f∗ωD⊗OC(Rf); with KC and KD canonical divisors, ωC≅OC(KC), ωD≅OD(KD) and OC(Rf) the sheaf of the effective divisor Rf by [F1] and [F4], this says exactly that KC is linearly equivalent to f∗KD+Rf.

3.1F2F4step 2.1

(Degree identity.) Taking degrees of the two isomorphic invertible sheaves of step 2.1 using the degree conventions of [F4] gives deg⁡k(KC)=deg⁡k(f∗KD+Rf)=deg⁡k(f∗KD)+deg⁡k(Rf)=ndeg⁡k(KD)+deg⁡k(Rf), where the middle step is additivity of deg⁡k [F4] and the last step is the pullback formula of [F2].

4.1F3step 2.1step 3.1

(Genera.) By [F3] one has deg⁡k(KC)=2g(C)−2 and deg⁡k(KD)=2g(D)−2, so substituting into step 3.1 gives 2g(C)−2=n(2g(D)−2)+deg⁡k(Rf), which is the displayed Riemann-Hurwitz identity, obtained exactly as the degree identity of the linear equivalence KC∼f∗KD+Rf of step 2.1.

5.1F5step 2.1step 4.1∎

The Axiom of Choice [F5] is used exactly through the ramification and duality suppliers cited above, each of which assumes it; together steps 2.1 and 4.1 prove both the linear equivalence and the numerical identity.

Depends on

Used by

Dependency tree · two levels

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Sources