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TheoremStatement: Literature-sourcedProof: AI-adaptedSession-authored (Fable 5 assisted)precheck passaudited 2026-07-31verified 2026-08-08 (gpt-5.6-terra-codex-subscription)
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Any two continuous maps into a nonempty convex subset of Rn\mathbb{R}^n are homotopic by straight lines

Statement

Let n1n\ge1, let CRnC\subseteq\mathbb R^n be nonempty and convex in the sense stated in For continuous maps into a convex subset of Rn\mathbb{R}^n, the straight-line formula defines a continuous homotopy, and let f,g:XCf,g:X\to C be continuous. Then

H(x,t)=(1t)f(x)+tg(x)H(x,t)=(1-t)f(x)+tg(x)

is a homotopy from ff to gg.

Facts & Assumptions

Given: A nonempty convex CRnC\subseteq\mathbb R^n with n1n\ge1 and continuous maps f,g:XCf,g:X\to C.

[L1]

The straight-line formula defines a continuous map H:X×ICH:X\times I\to C (For continuous maps into a convex subset of Rn\mathbb{R}^n, the straight-line formula defines a continuous homotopy).

[A1]

A homotopy from ff to gg is a continuous H:X×ICH:X\times I\to C with H(x,0)=f(x)H(x,0)=f(x) and H(x,1)=g(x)H(x,1)=g(x) (Homotopies of continuous maps, homotopies relative to a subspace, and path homotopies relative to the endpoints).

Proof

technique · direct
1.1

The map H(x,t)=(1t)f(x)+tg(x)H(x,t)=(1-t)f(x)+tg(x) is continuous by [L1].

L1
1.2

Substitution gives H(x,0)=f(x)H(x,0)=f(x) and H(x,1)=g(x)H(x,1)=g(x) for every xXx\in X.

algebra
2.1

Thus HH satisfies the continuity and endpoint conditions of [A1], so it is a homotopy from ff to gg.

step 1.1step 1.2A1

Depends on

Used by

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