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Weak Neumann and transmission existence with interface charges

Statement

Assume the Axiom of Choice for the actually cited Sobolev trace, lift and mean-zero density interfaces, and its Countable Choice consequence for the measure and variational interfaces (The Axiom of Choice, The Axiom of Countable Choice (ACω)). Let Ω⊂R3 be a bounded connected C1 domain, let ε be measurable symmetric uniformly elliptic (Weak Dirichlet problem with prescribed fractional Sobolev boundary data), let ρ∈L2(Ω), and let g∈H−1/2(∂Ω), the bounded real dual of the boundary trace space (The fractional Sobolev space on a compact C1 boundary). Define ℓ(v)=∫Ωρv+⟨g,Tv⟩ on H1(Ω) (The Lp trace operator on a bounded C1 domain). A weak Neumann solution is a u∈H1 with

∫Ω∇v⋅ε∇u=ℓ(v)for every v∈H1(Ω).

Such a solution exists if and only if ℓ(1)=0, and is then unique up to an additive constant; normalising ∫Ωu=0 makes it unique. On finitely many connected components the compatibility and normalisation are imposed separately on each component. For finitely many disjoint smooth stationary interfaces with piecewise smooth uniformly elliptic ε, bulk data ρ∈L2 and prescribed sheet charge σ on the interfaces defining a bounded trace functional on H1 (for instance σ∈L2 of each smooth compact interface), the same argument gives weak Dirichlet or compatible Neumann existence for the transmission problem, with the globally H1 potential having identical one-sided trace; where the solution is classically smooth on each side, integration by parts gives the jump n⋅[ε∇u]=−σ, equivalently n⋅[D]=σ for the explicitly defined mathematical flux D:=−ε∇u on each side. General piecewise classical regularity remains a separate requirement.

Facts & Assumptions

Given: A bounded connected C1 domain Ω with outward normal n; a uniformly elliptic symmetric measurable ε with constants 0<α≤β<∞; data ρ∈L2(Ω) and g∈H−1/2(∂Ω); the functional ℓ and the weak Neumann problem of the Statement.

[F1]

Trace and lift interfaces. Under AC the trace T:H1(Ω)→H1/2(∂Ω) is bounded and onto by The sharp trace theorem: boundedness and range in the fractional space at p=2. It has a bounded linear right inverse R:H1/2(∂Ω)→H1(Ω) by A bounded right inverse of the trace, supported in a prescribed collar, with TR=id and ∥Rg∥H1≤C∥g∥H1/2. The trace is the same operator as the H1→L2 trace of The Lp trace operator on a bounded C1 domain. Prescribed fractional Dirichlet solvability is supplied by Weak Dirichlet problem with prescribed fractional Sobolev boundary data; its boundary space is The fractional Sobolev space on a compact C1 boundary, and the standing AC is The Axiom of Choice.

[F2]

Mean-zero coercivity. On a bounded connected C1 domain, ∥v−vΩ∥L2≤CΩ∥∇v∥L2, where vΩ is the mean; hence the gradient norm is equivalent to the full H1 norm on the closed mean-zero subspace (Mean-zero Poincare inequality on a bounded connected C1 domain). The full H1 space is complete and Hilbert by The gradient norm dominates the H-one norm on zero-boundary Sobolev space; the mean functional is continuous by Cauchy-Schwarz, so its kernel is a closed Hilbert subspace. On H01 that supplier also gives ∥v∥2≤2L∥∇v∥2 and equivalence of the gradient and full norms for any enclosing cube Ω⊆(−L,L)3.

[F3]

Symmetric coercive solver. A symmetric bounded coercive bilinear form on a real Hilbert space with a bounded functional has a unique solution, under Countable Choice (Unique solution of a symmetric coercive variational problem on a Hilbert space, The Axiom of Countable Choice (ACω)).

Proof

technique · direct
1.1givenF1F4algebra

Boundedness of ℓ: ∣ℓ(v)∣≤∥ρ∥2∥v∥2+∥g∥H−1/2∥Tv∥H1/2≤C(1+∥ρ∥2+∥g∥H−1/2)∥v∥H1 by the trace bound [F1] and Cauchy-Schwarz [F4].

2.1step 1.1givenalgebra

Necessity of compatibility: the constant function 1 lies in H1(Ω) with ∇1=0, so testing the equation with v=1 gives 0=ℓ(1); hence ℓ(1)=0 is necessary for existence.

2.2step 1.1F2F3F4algebra

Assume now the compatibility condition ℓ(1)=0. Let H∗1={v∈H1(Ω):∫Ωv=0}, a closed subspace, and restrict the symmetric form a(w,v)=∫Ω∇v⋅ε∇w and the functional ℓ to it; a is bounded by β in gradient norm: the nonnegative quadratic bx(ξ+tη,ξ+tη) for bx(ξ,η)=ξ⋅ε(x)η gives ∣bx(ξ,η)∣≤β∣ξ∣∣η∣, and Cauchy-Schwarz [F4] gives ∣a(w,v)∣≤β∥∇w∥2∥∇v∥2. It is coercive with a(v,v)≥α∥∇v∥22≥c∥v∥H12 by the equivalence of norms of [F2], and ℓ remains bounded by step 1.1, so the solver [F3] gives a unique u∗∈H∗1 with a(u∗,v)=ℓ(v) for every v∈H∗1.

3.1step 2.2step 2.1algebra

Extension to all of H1: every v∈H1 decomposes as v=v∗+c with v∗∈H∗1 and constant c=vΩ; then a(u∗,v)=a(u∗,v∗)+a(u∗,c)=a(u∗,v∗)=ℓ(v∗)=ℓ(v∗)+c ℓ(1)=ℓ(v) by the compatibility assumed in step 2.2 and ∇c=0, so u∗ solves the full weak Neumann problem; normalising ∫u∗=0 selects this representative.

4.1step 3.1F2algebra

Uniqueness: for two solutions u1,u2 the difference w satisfies ∫∇v⋅ε∇w=0 for all v∈H1; testing v=w gives α∥∇w∥22≤∫∇w⋅ε∇w=0, so ∇w=0 and, by the mean-zero inequality [F2], w−wΩ=0, i.e. w is constant; hence solutions are unique up to additive constants and the mean-zero normalisation makes the solution unique.

5.1step 1.1step 3.1step 4.1F1F2F3algebra

Finitely many connected components: on a bounded C1 domain with components Ω1,…,ΩN, H1(Ω) is the direct sum of the H1(Ωj) extended by zero, the gradient form and the functional ℓ split, and the trace space splits accordingly, so the argument of steps 1.1-4.1 applies on each component separately: compatibility ℓ(1Ωj)=0 is required on each component and the solution is unique up to one constant per component, fixed by the per-component mean-zero normalisation.

6.1step 5.1F1F2F3F4algebra

Transmission: include the bounded interface functional ⟨σ,TΣv⟩ in ℓ. For Dirichlet data use the right-inverse lift G of [F1] and solve a(w,v)=ℓ(v)−a(G,v) on H01 by [F3] and zero-boundary coercivity of [F2]; then u=G+w has the prescribed outer trace and solves the full interface weak problem. For Neumann data apply steps 2.2–5.1 with this modified ℓ and its componentwise compatibility. The one-sided traces coincide: localized global H1 functions can be approximated by smooth ambient restrictions using [F4]; their traces coincide on the interface, and bounded one-sided trace maps pass that equality to the H1 limit.

7.1step 6.1F1F4algebra∎

Classical jump: where the transmission solution is classically smooth on each side of an interface Σ with unit normal n pointing from the side labelled minus to the side labelled plus, and [W]=W+−W−, apply the divergence theorem to ∇v⋅ε∇u on each side and subtract the weak equation; the bulk terms cancel and the remaining boundary identity is n⋅[ε∇u]=−σ, i.e. n⋅[D]=σ for the explicitly defined mathematical flux D:=−ε∇u, since [D]=−[ε∇u]; this is conditional on the one-sided classical smoothness, and general piecewise classical regularity remains a separate requirement.

Depends on

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