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The Einstein residual through the gauge vector, and the subsidiary wave equation satisfied by the gauge vector

Statement

Let (M,g,N) be a time-oriented smooth Lorentzian four-manifold with metric-selected connection ∇, let gˉ be a smooth background metric, let Ha=gbc(Γabc−Γˉabc) be the harmonic-gauge vector and let Eab=Gab+Λgab−κTab be the Einstein residual of a smooth symmetric tensor T (The harmonic gauge vector, the reduced Einstein equation and the Einstein residual). Then:

(a) On every open set where (g,T) solves the reduced Einstein equation, the identity Eab=12(∇aHb+∇bHa−gab∇cHc) holds on that set; and

(b) if (g,T) solves the reduced Einstein equation on an open set U and ∇aTab=0 on U, then the gauge vector satisfies the homogeneous linear wave equation □gHb+Ric⁡baHa=0on U, where □gHb=∇a∇aHb.

Facts & Assumptions

Given: the manifold and connection, the metrics g,gˉ, the gauge vector H, the constants Λ,κ, the tensor T and the residual E.

[L1]

Trace of the reduced equation: if (g,T) solves Ric⁡ab−∇(aHb)=κ(Tab−12Tgab)+Λgab, then S−∇cHc=−κT+4Λ with S=gabRic⁡ab and T=gabTab (The harmonic gauge vector, the reduced Einstein equation and the Einstein residual, The inverse metric, musical isomorphisms and index raising).

[L3]

Commutator identity: ∇a∇bHa−∇b∇aHa=RbaHa, with Rba the Ricci tensor in the framework's sign convention (The commutator of covariant derivatives on a vector field and its contracted component identity).

Proof

technique · direct
1.1L1algebra

(The residual identity (a).) Substituting the reduced equation into the definition of E and using the trace identity [L1]: Eab=Ric⁡ab−12Sgab+Λgab−κTab=∇(aHb)+κ(Tab−12Tgab)+Λgab−12Sgab+Λgab−κTab=∇(aHb)−12(∇cHc)gab, because S=∇cHc−κT+4Λ and the κT, Λ terms cancel in pairs (−12κTgab−12(−κT)gab=0 and Λgab+Λgab−12⋅4Λgab=0). Since ∇(aHb)−12(∇cHc)gab=12(∇aHb+∇bHa−gab∇cHc), this is (a).

1.2L2L4algebra

(Vanishing of the same divergence.) By definition E=G+Λg−κT and [L2], [L4] give ∇aEab=0+Λ∇agab−κ∇aTab=−κ∇aTab=0 on U by the on-shell conservation hypothesis.

2.1step 1.1L3L4algebra

(Divergence of the residual.) Take the divergence of (a): ∇aEab=12(∇a∇aHb+∇a∇bHa−∇b∇cHc)=12(□gHb+RbaHa), where the last equality uses the commutator identity [L3] in the form ∇a∇bHa−∇b∇cHc=RbaHa (with [L4] to raise the index freely).

3.1step 2.1step 1.2algebra∎

(Conclusion (b).) Comparing steps 2.1 and 1.2 gives □gHb+RbaHa=0 on U.

Remarks

Depends on

Dependency tree · 2 levels

Sources