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Uniform H^{s-2} Lipschitz bound for the time derivative of a Galerkin solution

Statement

Assume Countable Choice (The Axiom of Countable Choice (ACω)). Let s≥5 be an integer, let I0 be a compact interval inside the coefficient time domain, and let K⊆O be compact. Let uN:J→XN be a Galerkin solution, with J⊆I0 an interval, values in K and ∥uN∥Hs≤R. Then, uniformly in N, ∥∂t2uN(t)∥Hs−2≤C(Aμ,B,K,R,s,I0), and consequently ∥∂tuN(t)−∂tuN(t′)∥Hs−2≤C(Aμ,B,K,R,s,I0)∣t−t′∣. No convexity of K is required.

Facts & Assumptions

Given: Integer s≥5, the interval J, the coefficient family, compact time/value sets, Countable Choice, and the stated Galerkin bounds.

[L2]

∥g∥Hs−1≤CR for g=∂tuN (Uniform time-derivative bounds for Galerkin solutions in every H^j, j at most s minus one).

[L3]

Coefficients and their derivatives have bounded compositions and multiplier norms, and homogeneous commutator bounds (Smooth composition, difference, coefficient product and commutator estimates on bounded H^s data).

[L5]

The norm-valued fundamental theorem of calculus holds for the finite-dimensional smooth curve (Fundamental theorem of calculus for Banach-valued continuous curves).

Proof

technique · direct
1.1L1L3L4algebra

(Uniform projected inverse.) Let M=PNA0(uN)PN on XN. Positivity gives ∥M−1h∥2≤a−1∥h∥2. For v=M−1h and ∣α∣=j≤s−2, differentiate PN(A0v)=h and pair with Dαv∈XN to obtain a∥Dαv∥2≤∥Dαh∥2+∥[Dα,A0]v∥2≤∥Dαh∥2+CR∥v∥Hj−1. Induction and summation give ∥M−1h∥Hs−2≤CR∥h∥Hs−2, uniformly in N.

1.2L1L2L3algebra

(Differentiate the mass equation.) Smoothness of the finite-dimensional ODE permits time differentiation. Set z=uN and g=∂tz. The differentiated Galerkin identity is M∂tg=−PN(A˙0g+A˙i∂iz+Ai∂ig+B˙), where F˙=Ft+Fug for each coefficient. The compositions Ft,Fu have bounded Hs−1 norm by [L3], and g,∂iz have bounded Hs−1 norm by [L2]. Since s−1≥4, the algebra bound makes A˙0g, A˙i∂iz and B˙ bounded in Hs−1; Ai∂ig is bounded in Hs−2 by the multiplier bound. Thus the whole projected source is bounded in Hs−2 by a constant depending on R, without any universal polynomial growth assumption.

2.1step 1.1step 1.2L5algebra∎

(Second derivative and Lipschitz conclusion.) Apply step 1.1 to step 1.2 to obtain ∥∂tg∥Hs−2≤CR. Integrate on the segment between t,t′ using [L5] to get ∥g(t)−g(t′)∥Hs−2≤CR∣t−t′∣. This proves both claims.

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