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Exact spherical-shell coordinate marginal and fixed-block Gaussian limit

Statement

Assume the Axiom of Countable Choice ACω as defined in The Axiom of Countable Choice (ACω). Let D≥2, 1≤k<D, and R>0. Let Z1,…,ZD be independent real random variables with common Lebesgue probability density ϕ(x):=(2π)−1/2e−x2/2; its integral is one by the Gaussian integral in Gaussian, gamma and beta product integrals, and this is the standard-normal coordinate law. Set Z=(Z1,…,ZD) and define P:=RZ/∣Z∣ when Z≠0, and P:=0 when Z=0. The joint density of Z makes P(Z=0)=0. The distribution of P is rotationally invariant, meaning that for every orthogonal map Q∈O(D) and Borel set A⊆RD, P(QP∈A)=P(P∈A). It is concentrated on the sphere in the precise sense that P(∣P∣=R)=1. Its first k coordinates have Lebesgue density

fD,k(y)=Γ(D/2)Γ((D−k)/2)(πR2)k/2(1−∣y∣2R2)(D−k−2)/2(∣y∣<R),

and zero for ∣y∣≥R. This density is integrable even when it diverges at the boundary. Also E[Pi]=0, E[PiPj]=0 for i≠j, and E[Pi2]=R2/D.

For fixed k and σ>0, set RD=D σ and let D→∞ through integers D>k. If g:Rk→R is bounded and Lipschitz in the Euclidean norm, meaning that finite constants Bg,Lg satisfy ∣g(x)∣≤Bg and ∣g(x)−g(y)∣≤Lg∣x−y∣ for all x,y∈Rk, then

E g((P1,…,Pk))⟶E g(σ(Z1,…,Zk)).

This is a fixed-block bounded-Lipschitz test limit; it makes no claim uniform in k or for unbounded test functions. If k=D, the projection is singular on the sphere and the displayed Lebesgue density is not asserted.

Facts & Assumptions

Given: The Axiom of Countable Choice ACω, integers D,k with D≥2 and 1≤k<D, radius R>0, and the product probability law of D independent coordinates with density ϕ(x)=(2π)−1/2e−x2/2.

[F1]

Gaussian, gamma and beta product integrals: Γ(a) is finite for a>0, Γ(1/2)=π, positive gamma densities with the same scale convolve by adding their shape parameters, and the Gaussian second and fourth moments are 1 and 3 for a standard normal coordinate.

[F2]

A C^1 diffeomorphism satisfies the change-of-variables formula for nonnegative Lebesgue measurable functions: assuming ACω, for a C1 diffeomorphism T:U→V between open subsets of Euclidean space and nonnegative Lebesgue-measurable f on V, the Lebesgue integral transforms by ∣det⁡DT∣.

[F3]

On Borel subsets of R^{m+n}, the product lambda_m times lambda_n agrees with lambda_{m+n}: assuming ACω, product Lebesgue measure and Euclidean Lebesgue measure agree on Borel subsets of Rm+n for positive integers m,n.

[F4]

Tonelli's theorem for nonnegative measurable functions on a sigma-finite product: for a nonnegative product-measurable function on a product of sigma-finite measure spaces, either order of integration agrees with the product integral.

[F5]

The Axiom of Countable Choice (ACω): ACω says every sequence of nonempty sets has a choice function; it is the explicit set-theoretic hypothesis used by [F2].

Proof

1.1givenF2F3F5algebra

Under Countable Choice [F5], the Borel product-measure identity [F3] and independence give the joint Lebesgue density ϕD(z)=(2π)−D/2e−∣z∣2/2. A singleton has Lebesgue measure zero, so Z≠0 almost surely. For any orthogonal Q and Borel A⊆RD, the map Q−1:RD→RD is a C1 diffeomorphism with ∣det⁡Q−1∣=1; applying [F2] to 1AϕD and using ∣Q−1z∣=∣z∣ gives P(QZ∈A)=P(Z∈A). Since Q(RZ/∣Z∣)=RQZ/∣QZ∣ off the null event, the law of P is invariant under every orthogonal map, and ∣P∣=R almost surely.

1.2F1F2algebra

Write Z=(A,B) with A∈Rk and B∈RD−k. The vectors are independent. On each open half-line (0,∞) and (−∞,0), the map z↦z2/2 is a C1 diffeomorphism onto (0,∞); applying [F2] to the Gaussian density times the indicator of any Borel target set on each branch shows that each Zj2/2 has density w−1/2e−w/Γ(1/2). Repeated gamma convolution from [F1] then shows T:=∣B∣2 has density tb−1e−t/2/(2bΓ(b)) for t>0, where b=(D−k)/2, independently of A.

1.3givenconstructalgebra

For fixed t>0, the first k coordinates y=RA/∣A∣2+t range over ∣y∣<R. The inverse is A=t y/R2−∣y∣2. Its derivative has radial eigenvalue t R2/(R2−∣y∣2)3/2 and k−1 tangential eigenvalues t/(R2−∣y∣2)1/2, hence Jacobian tk/2R2/(R2−∣y∣2)k/2+1.

2.1F1F2F3F4step 1.2step 1.3algebra

The map Ψ(y,t):=(A(y,t),t) from U:={(y,t):∣y∣<R, t>0} to V:=Rk×(0,∞) is a C1 diffeomorphism, with inverse (a,t)↦(Ra/∣a∣2+t,t). Apply [F2] to the nonnegative joint density of (A,T) and this diffeomorphism. The product Lebesgue measure on Rk×(0,∞) agrees with Euclidean Lebesgue measure on Borel sets by [F3], and Tonelli's theorem [F4] gives the marginal density by integration in t. Substituting the Gaussian density of A, the gamma density of T, and the Jacobian from step 1.3 yields fD,k(y)=R2(2π)k/22bΓ(b)(R2−∣y∣2)k/2+1∫0∞tD/2−1exp⁡ ⁣(−tR22(R2−∣y∣2))dt. The substitution u=tR2/[2(R2−∣y∣2)] evaluates the integral as Γ(D/2)[2(R2−∣y∣2)/R2]D/2. Since D/2=k/2+b, simplification gives the displayed density. Its boundary singularity, when present, has exponent b−1>−1 and is integrable in the radial variable; the pushforward construction shows total mass one. Because T=∣B∣2>0 almost surely, the marginal has no boundary atom at ∣y∣=R.

2.2step 1.1givenalgebra

Sign changes of one Gaussian coordinate show E[Pi]=0 and E[PiPj]=0 for i≠j. Permutation invariance makes all E[Pi2] equal, while ∑i=1DPi2=R2 almost surely; summing expectations gives E[Pi2]=R2/D.

3.1F1step 1.1algebra∎

For each finite D, take the product Gaussian vector Z=(Z1,…,ZD) in that dimension and set SD:=D−1∑i=1DZi2. By [F1] and independence, ESD=1, E[(SD−1)2]=2/D, and E∣Z1:k∣2=k. Fix 0<δ<1/2 and M>0. On ED={∣Z1:k∣≤M, ∣SD−1∣≤δ}, SD∈[1/2,3/2] and the identity ∣u−1/2−1∣=∣u−1∣/[u(1+u)] gives ∣SD−1/2−1∣≤2δ; hence ∣σZ1:k/SD−σZ1:k∣≤2σMδ. If g is bounded Lipschitz with bound Bg and Lipschitz constant Lg, then M21{∣Z1:k∣>M}≤∣Z1:k∣2 and δ21{∣SD−1∣>δ}≤(SD−1)2 imply P(EDc)≤k/M2+2/(Dδ2). Therefore ∣Eg(P1:k)−Eg(σZ1:k)∣≤Lg2σMδ+2Bg(kM2+2Dδ2). Choose M large, then δ small, then D large. The right side becomes arbitrarily small, proving the stated test convergence without assuming independence between Z1:k and SD.

Remarks

This is a specified rotational Gaussian-direction preparation. It is not a general coarea formula, a proof that every energy-shell measure has this marginal, or a dynamical equilibration result.

Depends on

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