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Coulomb infinitesimal kinetic bound

Statement

Assume the Axiom of Countable Choice and the Axiom of Choice (The Axiom of Countable Choice (ACω), The Axiom of Choice). Let γ>0, let H=L2(R3;C) (Hilbert space, The space Lp(μ) as the quotient by null functions), and let H0:=−Δ be the free operator of Real multiplication operators and free plus bounded-potential Schrödinger operators with domain D(H0)=W2,2(R3;C) (Integer-order Sobolev spaces and their norms): H0=F2∗M4π2∣ξ∣2F2 and H0u=−Δu for u∈D(H0), where Δu is the distributional Laplacian. Write M for the multiplication operator Mu:=u∣⋅∣,D(M):={u∈H:u∣⋅∣∈H}, and write ∥u∥2=∥u∥H. Then:

(a) for every u∈D(H0)=W2,2(R3;C) one has u/∣⋅∣∈L2 and

∥u∣⋅∣∥2≤2∥u∥2 ∥Δu∥2 ,∥u∣⋅∣∥2≤η∥Δu∥2+1η∥u∥2(η>0);

(b) M is a self-adjoint operator on H with D(H0)⊆D(M), symmetric on D(H0), with H0-bound zero in the sense that for every η>0 the pair (η,η−1) is admissible for M relative to H0;

(c) for every γ>0 the operator C:=H0−γM,D(C):=D(H0)=W2,2(R3;C), is self-adjoint on H, bounded below, and acts by Cu=−Δu−γu/∣⋅∣ for every u∈D(C); for every η∈(0,1/γ) one has C≥−γη−1/(1−γη) in the quadratic-form sense.

No sharp lower bound of C is claimed here, and no physical interpretation of C, H0, γ or Δ is asserted.

Facts & Assumptions

Given: the free operator H0=−Δ with D(H0)=W2,2(R3;C); the multiplier M; the constant γ>0; a function u of the stated regularity.

[F1]

H0=F2∗M4π2∣ξ∣2F2 is self-adjoint on D(H0)={f:∣ξ∣2F2f∈L2}=W2,2(R3;C) as a set with equivalent norms, H0≥0 in the quadratic-form sense, and H0f=−Δf for Schwartz f (Real multiplication operators and free plus bounded-potential Schrödinger operators, Integer-order W^{k,2} and H^k agree with equivalent norms, Integer-order Sobolev spaces and their norms).

[F2]

For every u∈W1,2(R3;C) one has u/∣⋅∣∈L2 and ∥u/∣⋅∣∥2≤2∥∇u∥2 (Three-dimensional Hardy bound).

[F3]

Plancherel: F2 is unitary and for the weak derivatives of u∈W2,2 the multipliers satisfy F2(∂iu)(ξ)=2πiξiF2u(ξ) and F2(Δu)(ξ)=−4π2∣ξ∣2F2u(ξ) a.e.; equivalently ∥∇u∥22=∫4π2∣ξ∣2∣F2u∣2 and ∥Δu∥22=∫16π4∣ξ∣4∣F2u∣2 (Plancherel theorem, Distributional derivatives are polynomial Fourier multipliers, Integer-order W^{k,2} and H^k agree with equivalent norms).

[F4]

Cauchy-Schwarz: ∫∣fg∣≤∥f∥2∥g∥2 (Cauchy-Schwarz inequality for L2).

[F5]

Kato-Rellich: if A is self-adjoint, B symmetric, D(A)⊆D(B) and the A-bound of B is less than one with admissible pair (a,b), then A+B on D(A) is self-adjoint and, when A≥γ0, satisfies A+B≥γ0−max⁡{a∣γ0∣+b,b/(1−a)} (Kato-Rellich theorem, Relative boundedness with respect to an operator).

[F6]

If a is a real finite-valued measurable function on R3, then Maf:=af on {f∈H:af∈H} is self-adjoint, and it is symmetric on every subspace on which both sides of the pairing are integrable, in particular on the set of f with af∈H (Real multiplication operators and free plus bounded-potential Schrödinger operators (a), Adjoint of a densely defined operator, Symmetric, self-adjoint and essentially self-adjoint operators).

Proof

1.1F3F4algebra

[Kinetic inequality] Let u∈W2,2(R3;C) and put g:=F2u. By [F3], ∥∇u∥22=∫4π2∣ξ∣2∣g(ξ)∣2 dξ and ∥Δu∥22=∫(4π2∣ξ∣2)2∣g(ξ)∣2 dξ, while ∥u∥22=∫∣g∣2. Writing 4π2∣ξ∣2∣g∣2=(∣g∣)(4π2∣ξ∣2∣g∣) and applying [F4] to the two factors gives ∥∇u∥22≤∥u∥2∥Δu∥2.

2.1step 1.1F2algebra

[Infinitesimal Coulomb bound] Combining step 1.1 with [F2] yields ∥u/∣⋅∣∥2≤2∥∇u∥2≤2∥u∥2∥Δu∥2. For η>0 the arithmetic-geometric mean inequality 2ab≤ηa+η−1b applied to a=∥Δu∥2, b=∥u∥2 gives 2∥u∥2∥Δu∥2≤η∥Δu∥2+η−1∥u∥2. This proves (a).

3.1step 2.1F1F3F6algebra

[Relative bound of the multiplier] By [F6] applied to a(x)=1/∣x∣ (finite-valued on R3∖{0} and arbitrary, say 0, at the origin, a null set) the operator M is self-adjoint on D(M)={f:f/∣⋅∣∈H}, and M is symmetric on D(M). Step 2.1 shows D(H0)=W2,2⊆D(M) and ∥Mu∥2=∥u/∣⋅∣∥2≤η∥Δu∥2+η−1∥u∥2=η∥H0u∥2+η−1∥u∥2 for every u∈D(H0), since Δu=−H0u on D(H0) by [F1] and [F3]. Hence (η,η−1) is an admissible pair for M relative to H0, and the H0-bound of M is zero; this is (b).

4.1step 3.1F1F3F5algebra∎

[Self-adjointness of the Coulomb operator] Fix γ>0 and let η∈(0,1/γ). Then B:=−γM is symmetric with D(H0)⊆D(B) and admissible pair (a,b)=(γη,γη−1) with a<1; indeed ∥Bu∥2=γ∥Mu∥2≤γη∥H0u∥2+γη−1∥u∥2 by step 3.1. By [F5] with A=H0≥0 (so γ0=0) the operator C=H0+B on D(H0) is self-adjoint with C≥−max⁡{0, b/(1−a)}=−γη−1/(1−γη). Moreover Cu=H0u−γu/∣⋅∣=−Δu−γu/∣⋅∣ for u∈D(H0), by [F1] and [F3]; this is (c).

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