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Ramanujan and typical regular graphs synchronize for degree at least 600

PDF p. 1: Abstract; PDF p. 7: Corollary 1.6 and its proof; PDF p. 28: Section 5 opening

Statement

Assume countable choice. Every d-regular Ramanujan graph with d≥600 is globally synchronizing. For each fixed integer d≥600, a uniformly random labelled simple d-regular graph is globally synchronizing with high probability as its number of vertices tends to infinity through feasible orders. In this range 2d−1/d<0.0816.

Here a graph is finite and undirected, with at most one edge between a pair of vertices; loops are allowed in the deterministic assertion and count once in degrees. Its adjacency matrix is A, its vertex count is n>0, and J is the all-ones matrix. It is d-regular when each adjacency row sum is d, and it is Ramanujan in the article's convention when ∥A−(d/n)J∥op≤2d−1. The operator norm is induced by the Euclidean norm. Global synchrony means that, for phase-volume almost every initial state, the homogeneous Kuramoto trajectory in the rotating frame converges to a state with all phases equal.

In the random assertion, simple means no loops or repeated edges, the law is uniform over all labelled simple d-regular graphs on {1,…,n}, and a feasible order is one for which this set is nonempty. With high probability means that the probability tends to one along feasible orders, with d fixed.

Facts & Assumptions

[F1]

An (n,d,α)-expander has ∥A−(d/n)J∥op≤αd. The stated Ramanujan convention gives this inequality with α=2d−1/d (Adjacency spectral expander — Definition 1.3, Ramanujan graph convention used in the article).

[F2]

Under countable choice, every d-regular (n,d,α)-expander with d>0 and α≤0.0816 is globally synchronizing, including graphs with loops counted once in degrees (Regular spectral expansion implies synchronization — Theorem 1.4, The Axiom of Countable Choice (AC_ω)).

[F3]

For every fixed integer d≥3 and fixed ε>0, a uniform labelled simple d-regular graph is, with high probability along feasible orders, an (n,d,α)-expander for α=(2d−1+ε)/d (Typical regular graphs are almost Ramanujan, Uniform random regular graph convention).

Proof

Given: Countable choice and an integer d≥600; for the random assertion, d remains fixed while feasible orders tend to infinity.

Goal: Prove the deterministic and high-probability synchronization assertions and the numerical inequality.

1.1givenalgebra

Since d≥600, (d−600)(599d−600)≥0. Expanding and dividing by 90000d2>0 gives 4(d−1)/d2≤599/90000. Moreover 599⋅390625=233984375<234090000=2601⋅90000, so 599/90000<(51/625)2=(0.0816)2. Both sides being nonnegative, 2d−1/d<0.0816.

2.1F1F2step 1.1

For a d-regular Ramanujan graph, [F1] gives the expander condition with α=2d−1/d. By step 1.1 this parameter is below 0.0816, and d>0. Applying [F2] proves global synchrony.

3.1F2F3step 1.1algebra∎

Set ε=d2(0.0816−2d−1/d). By step 1.1 this is a fixed positive number, and (2d−1+ε)/d<0.0816. By [F3], the corresponding expander event has probability tending to one. On that event [F2] gives global synchrony; therefore the probability of global synchrony also tends to one. This proves the random assertion.

Source notes

The article's Corollary 1.6 and its proof state the two synchronization conclusions and use the threshold 0.0816. The source reference is attribution; the argument above uses the declared suppliers.

Depends on

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