Alphabeta Math
RemarkRemark: AI-adaptedProof: AI-generated
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Connectivity and the lower Laplacian parameter

PDF p. 19: Prose after Proposition 3.2; PDF p. 20: Remark 3.5

Statement

Let G be an (n,d∗,α,c−,c+)-expander with n≥2 and d∗>0. Its adjacency matrix is A, its degree matrix is D, its Laplacian is L=D−A, and ΔL=L−d∗I+(d∗/n)J, where J is the all-ones matrix. Write λ2(L) for the second-smallest eigenvalue of L, counting multiplicity. Then λ2(L)≥(1+c−)d∗. In particular, c−>−1 implies that G is connected.

Conversely, connectivity guarantees that some admissible lower parameter exceeds −1, with the other parameters chosen appropriately. It does not force an arbitrarily prescribed admissible c− to exceed −1.

Facts & Assumptions

[F1]

The expander definition includes c−d∗I⪯ΔL⪯c+d∗I, and the Loewner order means nonnegativity of the corresponding quadratic forms. Two-sided spectral expander — Definition 1.9 Loewner order, Hermitian inner product, and operator norm

[F2]

For nonempty V, P=J/n is the orthogonal projection onto the constant vectors, and Q=I−P projects onto 1⊥={f:∑xf(x)=0}. The constant projection and centering decomposition

[F3]

The Laplacian is positive semidefinite, its kernel consists of functions constant on each connected component, and for n≥2 zero is a simple Laplacian eigenvalue exactly when the graph is connected. Support connectivity and the unnormalized Laplacian kernel

[F4]

A normal endomorphism of a finite-dimensional complex inner-product space has an orthonormal eigenbasis. Complex spectral theorem: a normal endomorphism of a finite-dimensional complex inner product space has an orthonormal eigenbasis, and conversely

Proof

Given: The expander and parameter hypotheses in the statement.

Goal: Prove the spectral lower bound, its connectivity consequence, and the qualified converse.

1.1givenF1F2F3F4algebra

By the centered-matrix identity, L=ΔL+d∗(I−P). For f∈1⊥, [F1] and [F2] therefore give f∗Lf≥(1+c−)d∗∥f∥2. Also L1=0 by the degree definition, and L is real symmetric. Thus [F4] gives an orthonormal eigenbasis including 1/n; by [F3] all its eigenvalues are nonnegative. Each other basis vector lies in 1⊥, so its eigenvalue is at least (1+c−)d∗. Consequently λ2(L)≥(1+c−)d∗.

2.1F1F2F3F4step 1.1choosealgebra

If c−>−1, the lower bound in step 1.1 is positive because d∗>0. Hence zero is simple, and [F3] gives connectivity. Conversely, suppose G is connected. By [F3] and [F4], its smallest eigenvalue is zero and λ2(L)>0. For any chosen d∗>0, put c−=min⁡{0,λ2(L)/d∗−1}. On 1⊥, the eigenbasis gives ΔL=L−d∗I⪰c−d∗I; on the constant subspace both sides have quadratic values 0 and c−d∗∥f∥2, respectively. Thus the lower inequality holds and c−>−1. Since the matrices are finite-dimensional and self-adjoint, choose c+ large enough for the upper inequality and α large enough for ∥ΔA∥≤αd∗. These choices make the connected graph an expander with a lower parameter exceeding −1.

3.1F1F2F4algebra∎

The choice of lower parameter need not be optimal. For the connected graph K2 with d∗=1, A=(0110) and L=(1−1−11). On the constant and zero-sum vectors, respectively, ΔA=A−J/2 has eigenvalues 0,−1, while ΔL=L−I+J/2 has eigenvalues 0,1. Hence K2 is a (2,1,1,−1,1)-expander, although its prescribed c−=−1. This proves the stated limitation.

Source notes

The article states the unqualified equivalence between c−>−1 and connectivity and gives the displayed lower-bound argument. The counterexample above shows why the converse requires the existential qualification. This paragraph attributes the claim to Expander graphs are globally synchronizing, PDF pp. 19–20; the proof uses the mathematical suppliers listed above.

Depends on

Used by · 1

Dependency tree · 2 levels

Each result is drawn at its shortest distance from this item. Arrows run from prerequisites to the items that use them; this item has a heavier outline. External source nodes link directly to the cited text. The view shows up to two dependency steps; open a prerequisite to continue.

Sources