Alphabeta Math
ExampleConstruction: AI-adaptedVerification: AI-generated
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Single-vertex target case

PDF p. 3: Section 3, first paragraph after Figure 1

Example

Let k be a positive integer, and let H1,H2 be non-isomorphic finite simple connected graphs with at least one vertex each. If H1=K1, then K1∈Rindk(H1)∖Rindk(H2). The same conclusion with the target labels exchanged holds when H2=K1. Consequently, after these cases are handled, both connected targets have at least one edge.

Here K1 is the complete graph on one vertex. A graph is connected if every two of its vertices are joined by a path, a finite list of distinct vertices with consecutive vertices adjacent. The induced k-colour vertex-Ramsey class of a target consists of the graphs in which every vertex colouring by k available colours has a monochromatic induced copy of that target. An induced copy is the image of an injection preserving both adjacency and nonadjacency; monochromatic means that all its vertices have the same colour.

Facts & Assumptions

[F1]

By Graph and colouring conventions and Empty and complete graphs, complete bipartite graphs, and the convention that Pₙ and Cₙ have n vertices, a finite simple graph has edges consisting of pairs of distinct vertices, and K1 has one vertex and no edges.

[F2]

By Induced vertex-Ramsey class and Induced embeddings and induced copies of a graph, class membership requires a monochromatic induced embedding for every k-colouring; such an embedding is injective and preserves and reflects adjacency.

[F3]

By Walks, paths, connectedness and components in a simple graph on an arbitrary vertex set, any two vertices of a connected graph are joined by a path whose consecutive vertices are adjacent.

Verification

Given: The hypotheses of the example, first with H1=K1.

Goal: Establish the displayed class difference and the stated reduction.

1.1givenF1F2

For any k-colouring of K1, its only vertex is monochromatic, and the identity map is an induced embedding of H1=K1 into K1. Hence K1∈Rindk(H1).

2.1givenF1F2step 1.1

The nonempty graph H2 cannot have exactly one vertex: a finite simple graph on one vertex has no edges and is isomorphic to K1. Thus it has at least two vertices, so no injection from its vertex set to the one-vertex set of K1 exists. In particular, K1 contains no induced copy of H2 under any colouring; since k≥1, a k-colouring of K1 exists, and K1∉Rindk(H2). Exchanging the labels proves the symmetric case.

3.1givenF1F3step 2.1∎

If a nonempty connected simple graph has at least two vertices, a path between two distinct vertices has a consecutive pair, which is an edge. Every nonempty one-vertex simple graph is isomorphic to K1; hence, once the single-vertex cases have been handled, each connected target has an edge.

Depends on

Used by · 1

Dependency tree · 2 levels

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Sources