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A cut point that is not conjugate because two minimizers arrive

Statement refuted

Refuted claim. Let (M,g) be a complete, connected Riemannian manifold without boundary, let p∈M, and let q∈Cut⁡(p) be a cut point of p reached by a minimizing geodesic segment γ from p to q. Then p and q are conjugate along γ.

Facts & Assumptions

Given: The countable-choice axiom ACω; a circumference L>0; the flat circle CL=R/(LZ) with period-coordinate metric dx2; the base point p=[x]; the antipode q=[x+L/2]; and the two opposite semicircles γ+(t)=[x+t] and γ−(t)=[x−t] on [0,L/2].

[A1]

The exact choice assumption is ACω of The Axiom of Countable Choice (ACω). It is inherited only through the flat-circle example's maximal-geodesic, Hopf--Rinow and cut-time interfaces; the one-dimensional Jacobi calculation below uses no choice, and no full Axiom of Choice is used.

[F1]

In the flat circle CL the antipodal cut-time statement holds: both unit directions have cut time L/2, the cut locus is the single antipode Cut⁡(p)={[x+L/2]}, and at that cut point the two opposite semicircles are distinct minimizing geodesics (Cut locus of a point on a flat circle).

[F2]

The points γ(a) and γ(b) are conjugate along the affinely parametrized geodesic segment γ:[a,b]→M exactly when the space Kγ(a,b)={J∈J(γ):J(a)=0, J(b)=0} of Jacobi fields vanishing at both endpoints contains a nonzero field (Conjugate points along a geodesic and their multiplicity).

[F3]

A smooth field J along γ is Jacobi exactly when it satisfies the Jacobi equation Dt2J+R(J,γ˙)γ˙=0 (Jacobi field).

[F4]

In a coordinate chart of a Riemannian metric, the Levi-Civita Christoffel symbols are given by the Christoffel formula; for the period chart of CL the metric matrix is the constant 1×1 matrix (1), so the formula gives Γ111=0 (Christoffel formula for the levi civita connection).

[F5]

In a coordinate chart the curvature components are recovered from the Christoffel symbols by the coordinate curvature formula; when the Christoffel symbols vanish identically in the chart, every component Rℓkij vanishes, so the curvature operator R is zero at each point of the chart (Coordinate formula for the curvature tensor).

[F6]

For a local frame e with connection form B(t)=ωγ(t)(γ˙(t)), a field V(t)=e(γ(t))v(t) has covariant derivative DtV=e(γ(t))(v′(t)+B(t)v(t)) (Local frame formula for covariant differentiation along a curve); a section is parallel exactly when DtV=0 (Parallel section along a curve). In the period chart of CL the coordinate field ∂x is a frame along either semicircle, and its connection form vanishes because it is built from the symbols Γ111=0 of [F4].

Proof

technique · realize the two minimizing semicircles of the flat circle example, note that the flat connection makes the coordinate frame parallel and the curvature zero, and solve the resulting scalar Jacobi equation $j''=0$ with two endpoint zeros
1.1F1

By [F1], q lies in Cut⁡(p), and γ+ and γ− are distinct minimizing geodesics from p to q with common length L/2. In a period chart containing the image of the closed semicircle, γ+ lifts to the affine line s↦x+s and γ− lifts to s↦x−s; each lift has constant unit coordinate speed on [0,L/2].

1.2F4F5F6

In that period chart the metric coefficient is the constant 1, so [F4] gives vanishing Christoffel symbols, [F5] gives R=0 at every point of the chart, and [F6] makes the coordinate field ∂x a parallel frame along the semicircle, since its connection form is built from those vanishing symbols.

2.1F3F5F6step 1.2

Let J be a smooth vector field along γ+. On the chart domain write J(t)=j(t)∂x for a smooth real function j. As ∂x is parallel by step 1.2, the frame formula [F6] gives DtJ=j′∂x and Dt2J=j′′∂x, while the curvature term vanishes because R=0 by step 1.2. Thus, by [F3], J is a Jacobi field along γ+ exactly when the scalar equation j′′(t)=0 holds on [0,L/2], whose solutions are j(t)=a+bt with constants a,b∈R.

3.1F3step 2.1algebra

Suppose J is a Jacobi field along γ+ with J(0)=J(L/2)=0. By step 2.1, j(t)=a+bt with a=j(0)=0 and a+bL/2=j(L/2)=0. Since L/2>0, the second equation forces b=0, hence j=0 and J=0. The same calculation applies to γ−, whose chart lift s↦x−s has the same constant metric coefficient and the same vanishing symbols.

4.1F2step 3.1

Consequently Kγ+(0,L/2)={0} and Kγ−(0,L/2)={0}: the only Jacobi field along either minimizing semicircle vanishing at both endpoints is the zero field. By the conjugacy definition [F2], p and q are not conjugate along either semicircle.

5.1A1F1F2step 1.1step 4.1

Therefore q is a cut point of p, reached by the two distinct minimizing geodesics γ+ and γ−, and it is not conjugate to p along either of them; the claim in the Statement refuted is false. Boundary and choice audit: the two semicircles have positive length L/2, so both endpoint times are distinct and the endpoint zeros are genuine; the circle is one-dimensional and nonempty, with no degenerate interval and no constant geodesic among the two witnesses; the zero field is the only endpoint-vanishing Jacobi field and it cannot witness conjugacy by [F2]. Exactly ACω is used, and only to invoke the flat-circle example's cut-time interface by [A1]; the Jacobi computation selects nothing. The refuted claim is a one-way implication, so no converse case arises.

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Source locator

Lee, Riemannian Manifolds: An Introduction to Curvature, Chapter 10, printed p.190 / PDF label P206, lines 7559–7571, observes that the flat cylinder has no conjugate points and that wrappings longer than halfway stop minimizing; that geometry is realized here on the flat circle, and the local nonconjugacy calculation is carried out rather than quoted. Datar, Lectures on Riemannian Geometry, Appendix C.14.2, printed p.278 / PDF labels P284–285, lines 14021–14050, states Klingenberg's lemma with an exercise outline relating nonconjugate cut points to two minimizing geodesics; the explicit circle witness above does not use that exercise as a proof.

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