Alphabeta Math
CounterexampleConstruction: AI-adaptedVerification: AI-adaptedPipeline-generatedprecheck pass
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Finite speed of propagation does not imply strong Huygens

Statement refuted

The finite-speed property (Compact support expands at speed at most c) coexists with three distinct wave phenomena: the strong Huygens principle can fail (The strong Huygens principle in the homogeneous Cauchy setting), regularity need not improve, and nonnegative displacement data need not produce a nonnegative solution. The following compactly supported witnesses make these distinctions explicit.

  1. Failure of strong Huygens. Let c>0, x0∈Rn, t0>0 and n∈{1,2}. In dimension 1, choose u0=0 and a nonnegative nonzero u1∈Cc1(R) supported in (x0−ct0,x0+ct0). Then the d'Alembert formula gives u(x0,t0)=12c∫u1>0. In dimension 2, choose u0=0 and a nonnegative nonzero u1∈Cc2(R2) supported in Br(x0) for some r<ct0; the Poisson formula gives u(x0,t0)>0. In both cases the data vanish on a neighbourhood of S(x0,ct0), yet the value is nonzero, while finite speed still holds.

  2. No smoothing. There is a compactly supported F∈C2(R) that is not C3. The traveling wave u(x,t)=F(x−ct) solves the one-dimensional equation and remains C2 but not C3 for every t≥0. Its support translates at speed c.

  3. No maximum principle. In dimension 2, take a nonnegative nonzero u0∈Cc∞(Br(x0)) and u1=0. At any time t0>r/c, the displacement term of Poisson's formula gives u(x0,t0)<0. Thus the solution can change sign although the initial displacement is nonnegative and the initial velocity is zero.

All four data pairs are compactly supported. The d’Alembert witnesses extend C2 through time zero; for the smooth Poisson witnesses the descended sphere expression ∂t[tMU0(3)((x,0),ct)]+tMU1(3)((x,0),ct) extends smoothly through zero, since the signed-radius means are integrals of smooth data over the fixed compact sphere and may be differentiated there on any compact parameter set. Thus the initial regularity hypothesis is met and Compact support expands at speed at most c supplies the finite-speed bound. The no-smoothing and sign-change examples are independent of the Huygens witnesses; they show why the qualitative properties listed by Hunter require separate arguments.

Facts & Assumptions

Given: ACω; c>0; the compactly supported smooth data chosen in the proof; and a compactly supported C2 profile.

[F1]

For u0∈C2(R) and u1∈C1(R), the unique classical solution is u(x,t)=12(u0(x−ct)+u0(x+ct))+12c∫x−ctx+ctu1(y) dy. (d'Alembert's formula and uniqueness in one dimension)

[F2]

For u0∈C3(R2) and u1∈C2(R2), the two-dimensional solution is the Poisson expression u(x,t)=12πc∂∂t∫Bct(x)u0(y)c2t2−∣y−x∣2 dy+12πc∫Bct(x)u1(y)c2t2−∣y−x∣2 dy. (Poisson's formula in two dimensions by descent)

[F3]

Finite propagation: for a C2 solution defined on a neighbourhood of the initial slab, with data supported in a compact K and a source supported in {(x,t):dist⁡(x,K)≤ct} (in particular for a zero source), supp⁡u(⋅,t)⊆K+B‾ct(0) for every t. (Compact support expands at speed at most c)

[F4]

The strong Huygens principle in the homogeneous Cauchy setting is the statement that the value is carried by the sphere S(x0,ct0)=∂Bct0(x0): admissible perturbations vanishing on a neighbourhood of S do not change u(x0,t0). (The strong Huygens principle in the homogeneous Cauchy setting)

[F5]

For any centre and radius there is a smooth nonnegative bump equal to one on the concentric half-radius ball and supported inside the full ball, by translating A smooth bump between concentric Euclidean balls.

[F6]

A nonnegative integral is monotone and positively homogeneous; it vanishes exactly for functions zero almost everywhere. A continuous function positive somewhere is bounded below by a positive constant on a smaller ball of positive measure. (Monotonicity and nonnegative homogeneity of the nonnegative integral, A nonnegative measurable function has integral 0 exactly when it vanishes almost everywhere, Sphere and ball measures scale in Rn)

[F7]

A parameter derivative may pass under the integral when dominated by a fixed integrable function on the parameter interval. (Differentiation under the integral sign)

Proof

1.1givenF1F3F4F5F6

The one-dimensional Huygens witness: choose u0=0 and a smooth nonnegative nonzero bump u1 as in [F5] supported in (x0−ct0,x0+ct0). Formula [F1] gives u(x0,t0)=12c∫x0−ct0x0+ct0u1(y) dy>0. The data are compactly supported inside the open base interval, hence vanish on a neighbourhood of its boundary sphere; [F3] supplies finite speed.

1.2givenF2F3F4F5F6

The two-dimensional Huygens witness: choose 0<r<ct0 and the nonnegative nonzero smooth bump u1 of [F5] supported in Br(x0), with u0=0. Formula [F2] gives u(x0,t0)=12πc∫Br(x0)u1(y)c2t02−∣y−x0∣2 dy>0. Again the data vanish on a neighbourhood of S(x0,ct0), and [F3] applies.

1.3givenF1F8

Compact traveling wave with no smoothing: define F(s):={(1−s2)3∣s∣5/2,∣s∣<1,0,∣s∣≥1. At s=±1 the factor (1−s2)3 makes F,F′,F′′ tend to zero, so the extension by zero is compactly supported and C2. The power and product rules [F8] give F→0 and F′(s)=52sgn⁡(s)∣s∣3/2+O(∣s∣7/2)→0 as s→0. The difference quotients of F and F′ at zero tend to zero, so F′(0)=F′′(0)=0. Near s=0, F′′(s)=154∣s∣1/2+O(∣s∣5/2), so F′′(h)/h→+∞ as h↓0; hence F is not C3. Take u0=F, u1=−cF′. In [F1], by the FTC in [F8], the integral term equals −12(F(x+ct)−F(x−ct)), so the solution simplifies to u(x,t)=F(x−ct). It is C2 and not C3 at x=ct, and its compact support is translated exactly at speed c.

1.4givenF2F3F5F6F7

Nonnegative displacement becomes negative: take the nonnegative nonzero smooth bump u0 of [F5] supported in Br(x0), u1=0, and t0>r/c. Since the support is strictly inside Bct(x0) for t near t0, on a small closed time interval about t0 the quantity c2t2−r2 has a positive lower bound. Thus the integrand and its time derivative are uniformly bounded on the compact support, providing a constant integrable majorant; [F7] permits differentiating the displacement integral in [F2] over the fixed support: u(x0,t0)=−ct02π∫Br(x0)u0(y)(c2t02−∣y−x0∣2)3/2 dy<0. The strict inequality follows by [F6] because the kernel is positive and u0 is nonnegative and nonzero. Thus positivity is not preserved, despite nonnegative displacement and zero initial velocity; [F3] still gives finite speed.

2.1step 1.1step 1.2F3F4

Huygens conclusion: in steps 1.1 and 1.2 each data pair is supported strictly inside the relevant base ball, so it agrees with the zero pair on a neighbourhood of the sphere but gives a nonzero value at the vertex. This contradicts the defining data-insensitivity in [F4]. Finite propagation [F3] remains true; therefore finite speed does not imply strong Huygens, as recorded in Finite propagation is not the Huygens principle.

3.1step 1.3step 1.4∎

Regularity and positivity conclusions: step 1.3 retains a second-derivative cusp under translation, so the wave flow has no smoothing; step 1.4 gives an explicit failure of positivity preservation, hence of a maximum principle.

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

120 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources