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Lower positive sectional curvature forces conjugate points

Statement

Assume the inherited Axiom of Countable Choice ACω. Let (M,g) be a complete Riemannian manifold of dimension n≥2 whose sectional curvatures are bounded below by k>0: every sectional curvature of every two-plane in every tangent space satisfies K≥k. Let p∈M and let γ:[0,∞)→M be a unit-speed geodesic with γ(0)=p. Then γ has a conjugate point to p: the first conjugate instant τ of p along γ is finite and τ≤πk.

No strictness is asserted at the endpoint: τ=π/k is possible and is realized on the round sphere of curvature k. Completeness is part of the hypotheses of the geometric setting of this page; the comparison argument below uses only the curvature bound and the absence of conjugate points.

Facts & Assumptions

Given: The inherited ACω of [A1], the complete n-dimensional Riemannian manifold (M,g) with K≥k>0, a point p∈M and a unit-speed geodesic γ:[0,∞)→M from p.

[A1]

The countable-choice premise is the inherited ACω (The Axiom of Countable Choice (ACω)), carried through the curvature and index-form suppliers used below; the Jacobi and parallel initial-value constructions require no choice.

[F1]

Rauch comparison, first form (Rauch comparison theorem first form): for unit-speed geodesics in n-dimensional manifolds and normal Jacobi fields J1,J2 with Ji(0)=0 and equal positive initial-derivative norms, if every relevant radial sectional curvature of M1 is at least every such curvature of M2, and M1 has no conjugate point in (0,T], then ∣J1(t)∣≤∣J2(t)∣ on [0,T].

[F2]

Comparison functions (Comparison sine, cosine and cotangent functions, Model functions solve the constant curvature jacobi equation): sn⁡k′′+ksn⁡k=0, sn⁡k(0)=0, sn⁡k′(0)=1, sn⁡k(t)>0 for 0<t<π/k and sn⁡k(π/k)=0 when k>0.

[F3]

Constant-curvature model (Constant sectional curvature and space form, Curvature tensor of constant sectional curvature): in a manifold of constant sectional curvature k the curvature tensor is R(X,Y)Z=k(g(Y,Z)X−g(X,Z)Y), so in particular every radial sectional curvature equals k and R(X,γ˙)γ˙=k(X−g(X,γ˙)γ˙).

[F4]

Parallel transport (Existence and uniqueness of parallel sections, Levi civita parallel transport preserves lengths angles and volume): along a geodesic there is a unique smooth parallel field with prescribed value at one time, and parallel transport is an isometry preserving orthogonality.

[F5]

Radial Jacobi data (Radial Jacobi tensor, Radial jacobi tensor is invertible before the first conjugate point, Jacobi field): for w in the normal space at γ(0) the radial field J(t)=A(t)w is the unique normal Jacobi field with J(0)=0, DtJ(0)=w, and A(t) is an isomorphism of normal spaces for every t>0 before the first conjugate instant; a Jacobi field with J(t0)=0=DtJ(t0) is identically zero.

[F6]

Conjugate points (Conjugate points along a geodesic and their multiplicity): γ(t0), t0>0, is conjugate to γ(0) along γ exactly when there is a nonzero Jacobi field along γ∣[0,t0] vanishing at both ends; the first conjugate instant is the infimum of such t0.

[F7]

Sectional curvature (Sectional curvature): a plane containing γ˙(t) has sectional curvature sec⁡, and K≥k means sec⁡≥k for every plane.

Proof

technique · direct: identify the explicit radial Jacobi field of the constant-curvature model, whose norm is $\operatorname{sn}_k$ and which vanishes at $\pi/\sqrt k$, and compare any radial field of $M$ with it through Rauch's first form; the model's zero forces a conjugate point
1.1F2F3F4given

The model radial field. [F2, F3, F4, given] Let Mkn be the complete, simply connected space form of constant curvature k, let γ~ be a unit-speed geodesic in Mkn and let w∈Tγ~(0)Mkn satisfy ∣w∣=1 and w⊥γ~′(0); write Φt for parallel transport along γ~ and Jk(t):=sn⁡k(t) Φtw. Then DtJk=sn⁡k′Φtw and Dt2Jk=sn⁡k′′Φtw=−ksn⁡kΦtw, while by [F3] and the normality of Jk (preserved by parallel transport [F4]) R(Jk,γ~′)γ~′=k(g(γ~′,γ~′)Jk−g(Jk,γ~′)γ~′)=kJk. Hence Dt2Jk+R(Jk,γ~′)γ~′=0: the field is a normal Jacobi field with Jk(0)=0,DtJk(0)=w,∣Jk(t)∣=sn⁡k(t)(0≤t≤π/k), and by [F2] it satisfies Jk(t)≠0 for 0<t<π/k and Jk(π/k)=0.

2.1F1F5F6F7step 1.1given∎

Rauch comparison and the conjugate point. [F1, F5, F6, F7, step 1.1, given] Let Tk:=π/k and suppose, for contradiction, that no t∈(0,Tk] is a conjugate instant of p along γ. Choose a unit normal vector w1∈{γ˙(0)}⊥, which exists because n≥2, and let J1(t):=A(t)w1 be the radial Jacobi field with J1(0)=0 and ∣DtJ1(0)∣=1 [F5]. By the supposition and [F5], A(t) is invertible for 0<t≤Tk, so J1(t)≠0 there; in particular DtJ1(0)=w1≠0, so J1 is not the zero field [F5]. Apply Rauch's first form [F1] with M1:=M,γ1:=γ,J1andM2:=Mkn,γ2:=γ~,J2:=Jk, the model field of step 1.1: both fields vanish at 0 and have initial derivative norm 1. Hypothesis 1 of [F1] holds because every radial sectional curvature of M is at least k by [F7] while every radial sectional curvature of the model equals k by [F3]; hypothesis 2 holds by the contradiction supposition. The conclusion is ∣J1(Tk)∣≤∣J2(Tk)∣=∣sn⁡k(Tk)∣=0, so J1(Tk)=0. Thus the nonzero Jacobi field J1 vanishes at t=0 and t=Tk, that is, Tk is a conjugate instant of p along γ [F6], contradicting the supposition. Therefore some t∈(0,Tk] is a conjugate instant, and the first conjugate instant τ satisfies τ≤Tk. The proof uses only the hypothetical field and the single model field fixed in step 1.1, so the inherited ACω of [A1] is not drawn on beyond its declaration.

Source locator

Datar Corollary 25.3.3 with its proof (printed p.189) obtains the conjugate point bound ≤π/κ under sec⁡≥κ>0 exactly as the contrapositive argument above: if no conjugate point occurred up to π/κ, the comparison with the spherical radial field sn⁡κ would force the actual field to vanish there. Eschenburg §3 (printed p.13) contains the same content as the strict specialisation of Rauch I; the proof here uses the in-run Rauch first form and the published model-function and space-form suppliers.

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