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CorollaryStatement: Literature-sourcedProof: AI-adaptedprecheck passjudge pass (gpt-5.6-terra)audited 2026-09-04
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Markov's inequality for random variables

Statement

If X:Ω[0,+] is a nonnegative random variable on a probability space and a>0, then P(Xa)E[X]a.

Facts & Assumptions

Given: A nonnegative random variable X and a real number a>0.

[L1]

Expectation is integration against the probability measure (Expectation of a nonnegative or integrable random variable).

[L2]

The integral Markov inequality states μ({ft})t1fdμ for nonnegative measurable f and t>0 (Chebyshev-Markov inequality for the integral).

Proof

technique · direct
1.1

Apply [L2] to the probability measure P, the function X, and the threshold a>0. Rewriting the integral by [L1] gives P(Xa)E[X]a.

L1L2
2.1

Step 1.1 is exactly Markov's inequality for random variables.

step 1.1

Depends on

Used by

Dependency tree · two levels

8 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources