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A Morse gradient zero contributes (−1)λ to the index

Statement

Assume ACω (The Axiom of Countable Choice (ACω)) for the canonical smooth tangent-bundle structure.

Let M be a closed smooth n-manifold, n≥1, and let f:M→R be a Morse function (Morse functions and excellent Morse functions), let g be a Riemannian metric on M (Riemannian metric and riemannian manifold) and let p be a critical point of f of index λ=ind⁡(p) (Nondegenerate critical points, nullity, index, and coindex). Then grad⁡gf has a nondegenerate zero at p with ind⁡p(grad⁡gf)=(−1)λ,ind⁡p(−grad⁡gf)=(−1)n−λ.

Facts & Assumptions

Given: A closed smooth manifold M, a Morse function f, a Riemannian metric g and a critical point p of f of Morse index λ.

[F1]

The gradient grad⁡gf is a smooth vector field on M and it vanishes exactly at the critical points of f (The Riemannian gradient is the metric dual of the differential, The Riemannian gradient vanishes exactly at the critical points).

[F2]

In coordinates, differentiating the gradient formula at a critical point gives D(grad⁡gf)p=g(p)−1Hp, because dfp=0 kills the derivatives of the inverse metric. Thus the linearization (vertical derivative) of grad⁡gf is the Hessian bilinear form Hess⁡pf, read through g; the critical Hessian of a Morse function is nondegenerate with λ negative and n−λ positive entries in its inertia normal form, so the linearization is invertible and p is a nondegenerate zero of grad⁡gf (The intrinsic Hessian of a smooth function at a critical point, At a critical point, the intrinsic Hessian agrees with the Levi-Civita Hessian, Nondegenerate critical points, nullity, index, and coindex, Nondegenerate zero of a vector field).

[F3]

A nondegenerate zero has index equal to the sign of the determinant of its linearization (The index of a nondegenerate vector-field zero), the sign of the determinant of a nondegenerate symmetric form with λ negative and n−λ positive entries in its inertia normal form is (−1)λ (Nondegenerate critical points, nullity, index, and coindex), and negating the field multiplies the index by (−1)n (Negation scales the local index by (−1)n); the index of the negated function swaps, ind⁡p(−f)=n−λ (Index and coindex swap under negation).

Proof

1.1F1F2algebra

By [F1] the field grad⁡gf has a zero at p (and only at the critical points), and by [F2] its linearization there is the nondegenerate Hessian with λ negative and n−λ positive entries in its inertia normal form; hence p is a nondegenerate zero and sign⁡det⁡(Dgrad⁡gf)p=(−1)λ.

2.1F2F3step 1.1algebra∎

The determinant formula [F3] gives ind⁡p(grad⁡gf)=(−1)λ, and the negation rule gives ind⁡p(−grad⁡gf)=(−1)n(−1)λ=(−1)n−λ, the second formula; equivalently, −grad⁡gf=grad⁡g(−f) has index (−1)ind⁡p(−f)=(−1)n−λ by the index swap of [F3].

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