Alphabeta Math
CorollaryStatement: Literature-sourcedProof: AI-adaptedSession-authored (Fable 5 assisted)precheck passaudited 2026-08-11
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

A polynomial ring in finitely many indeterminates over an integral domain is an integral domain

Statement

If RR is an integral domain, then R[x1,,xn]R[x_1,\ldots,x_n] is an integral domain for every nNn\in\mathbb N, including n=0n=0.

Facts & Assumptions

Given: An integral domain RR and the iterated polynomial rings P0=RP_0=R and Pn+1=Pn[xn+1]P_{n+1}=P_n[x_{n+1}].

[L1]

The iterated ring satisfies R[x1,,x0]=RR[x_1,\ldots,x_0]=R and R[x1,,xn+1]=R[x1,,xn][xn+1]R[x_1,\ldots,x_{n+1}]=R[x_1,\ldots,x_n][x_{n+1}] (Polynomial rings in finitely many commuting indeterminates by iteration).

[L2]

A one-variable polynomial ring over an integral domain is an integral domain (A polynomial ring over an integral domain is an integral domain).

[L3]

If a property holds at 00 and passes from nn to n+1n+1, it holds for every natural number (The principle of mathematical induction).

Proof

technique · induction
1.1

The ring P0=RP_0=R is a domain, giving the zero-indeterminate case.

basegivenL1
1.2

Fix nNn\in\mathbb N and assume that PnP_n is a domain.

ihgiven
2.1

Under that hypothesis, [L1] and [L2] make Pn+1=Pn[xn+1]P_{n+1}=P_n[x_{n+1}] a domain; together with the base case, [L3] proves the claim for every nn.

step 1.1step 1.2L1L2L3discharge-induction

Depends on

Used by

Dependency tree · next 3 levels

Direct dependencies and their dependencies through the next three levels: 25 results over 6 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.

Sources