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A handle slide realizes an elementary row operation

Example

Assume ACω. In dimension n=4 start from the 0-handle D4 and attach the standard 1-handle h1 along the equatorial embedding, so that D4∪h1≅S1×D3 and the middle boundary is N=∂+(D4∪h1)≅S1×S2 with belt sphere B={p}×S2 of h1 a 2-sphere. Attach two 2-handles g1,g2 to N along embedded circles γ1,γ2⊆N with disjoint images, for instance γ1=S1×{u1} and γ2 a small circle in a coordinate ball disjoint from B∪γ1, with product/local framings. They are chosen so that γ1 meets B transversely in exactly one point and γ2 is disjoint from B. Indexing rows by the 2-handles and the single column by the 1-handle, the attaching-belt matrix is the column (±1,0)T over Z for suitable orientations, respectively (1,0)T over Z2. Slide the 2-handle g2 over g1. The total 4-manifold is unchanged by the slide, while the same column becomes (±1,±1)T over Z, respectively (1,1)T over Z2: exactly the elementary row operation R2↦R2±R1.

Facts & Assumptions

Given: Dimension n=4; the 0-handle D4 with the standard 1-handle h1 attached, middle boundary N=∂+(D4∪h1) and belt sphere B⊆N of h1; two embedded circles γ1,γ2⊆N with disjoint images, with γ1 meeting B transversely in exactly one point and γ2∩B=∅; the 2-handles g1,g2 attached to N along γ1,γ2 with chosen framings.

[F1]

Attaching a smooth handle with corner rounding and K handle core cocore attaching region and belt sphere: in dimension 4 a 1-handle has attaching region S0×D3, outgoing region D1×S2 and belt sphere S2; a 2-handle has attaching sphere S1 and attaching region S1×D2.

[F2]

The standard complementary pair fills a ball: attaching the standard 1-handle to D4 along the equatorial embedding gives D4∪h1≅S1×D3 with outgoing boundary S1×S2, and up to this diffeomorphism the belt sphere of h1 is the fiber sphere {p}×S2.

[F3]

Attaching-belt intersection matrix of adjacent-index handles: for n=4 and k=1 the matrix is defined (1≤k≤n−2=2), its rows are the (k+1)-handles gi and its columns the k-handles ej, and Mij is the intersection number of the attaching sphere of gi with the belt sphere of ej in the middle boundary, over Z or Z2 according to the orientations.

[F4]

The oriented intersection number, The local oriented intersection sign and The mod 2 intersection number: transverse complementary-dimensional intersections are finite with local signs ±1; a single transverse point of a circle with a 2-sphere has entry ±1 over Z and 1 over Z2, and disjoint spheres have entry 0.

[F5]

Handle slide of one k handle over another and Handle slides preserve the relative diffeomorphism type: assume ACω; a slide of g2 over g1 is defined here (index 2, middle boundary of dimension 3, so 1≤2≤3−1), replaces the attaching circle of g2 by the band sum with a framed parallel copy of the attaching circle of g1, and leaves the total 4-manifold unchanged.

[F6]

Handle slides act by elementary basis change on handle chains and Elementary matrix operations are realized by handle slides: assume ACω; under the disk-push diffeomorphism together with its specified lower-stage homotopy, the slid core satisfies [C2′]=[C2]±[C1] in the handle chain group, so intersecting the fixed belt sphere with both sides gives M2,1′=M2,1±M1,1, the elementary row operation R2↦R2±R1; this is case (ii) of the matrix-operation proposition because k+1=2≤n−2=2.

[F7]

The Axiom of Countable Choice (ACω): ACω is assumed; it is used through [F5] and [F6].

Verification

Given: The configuration of the statement.

1.1F1F2F3F4given

By [F1] and [F2] the middle boundary is N≅S1×S2 and the belt sphere of h1 is B={p}×S2, a 2-sphere; the 2-handles are attached along the circles γi, so the matrix is the column with entries Mi1=I(γi,B). By hypothesis γ1 meets B in exactly one transverse point and γ2 is disjoint from B, so by [F4] the column is (±1,0)T over Z for suitable orientations and (1,0)T over Z2.

2.1F5F6F7step 1.1

Slide the 2-handle g2 over g1; the move is legitimate in the range of [F5], the total 4-manifold is unchanged, and the slid attaching circle γ2′ has core class [C2′]=[C2]±[C1] by [F6]. Countable Choice enters only through the slide and basis-change suppliers [F5] and [F6].

3.1F4F6step 2.1

Recomputing the same column with the slid handle, M2,1′=I(γ2′,B)=I(γ2,B)±I(γ1,B)=0±(±1) over Z, respectively 0+1=1 over Z2: the column becomes (±1,±1)T, respectively (1,1)T, which is exactly the elementary row operation R2↦R2±R1 on the matrix.

4.1F3F5F6step 3.1given∎

The construction is legitimate in the range of both the matrix definition and the slide: with n=4 and k=1 one has 1≤k≤n−2=2 and k+1=2≤n−2, so the example realizes case (ii) of Elementary matrix operations are realized by handle slides in the lowest dimension in which the row operation is available.

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