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Handle Cancellation Slides and Elementary Moves — Examples

1 · Prerequisites

2 · Summary

The examples make the two elementary moves concrete. A 0-1 pair is cancelling as soon as the attaching 0-sphere of the band has one point on the belt sphere of the ball, and the model is the identity that two balls joined by a band are one ball; a 1-2 pair on a surface cancels when the attaching circle of the disc runs through exactly one point of the belt 0-sphere of the band, and the matrix definition deliberately does not cover these endpoint cases. On the four-dimensional side, a 1-handle attached to a 4-ball has middle boundary S1×S2, and two 2-handles attached along disjoint circles realize an elementary row operation: sliding the second 2-handle over the first changes the matrix column (±1,0)T to (±1,±1)T, exactly the row operation of the matrix-operation proposition.

The two counterexamples display the hypotheses that the theorem cannot drop. A finger move of a sphere across a belt circle produces three transverse intersections with local signs +1,+1,−1, so the algebraic intersection is still a unit while the geometric intersection has three points: a unit entry does not supply the single point the cancellation theorem needs. This inserted opposite pair can be removed by reversing the finger isotopy; a general algebraic-to-geometric conversion needs separate geometric hypotheses, such as those of the Whitney trick. Finally, a 2-handle attached to a solid torus along a circle that bounds a disk in the boundary disjoint from the belt circle has vanishing intersection with the belt sphere, so the pair is not geometrically cancelling and in fact cannot cancel: the attaching circle is null-homotopic in the solid torus, so the total space stays with fundamental group Z while the lower stage is simply connected.

3 · Logical flowchart

4 · Definitions, theorems and proofs

None yet.

5 · Examples, counterexamples and false statements

ExampleConstruction: Literature-sourcedVerification: Literature-sourcedprecheck passOpen item page →

A cancelling zero-one handle pair

Example

Assume ACω. In dimension n≥1 attach a 0-handle h0 to a compact manifold W as a disjoint ball Dn and then attach a 1-handle h1 by an embedding S0×Dn−1→∂+(W⊔Dn) whose attaching 0-sphere consists of one point on the new boundary sphere Sn−1 of h0 (its belt sphere) and one point on ∂+W. In the endpoint convention of the definition the pair is geometrically cancelling, exactly one point of the 0-sphere lying in the belt sphere with transversality automatic, and W⊔Dn∪h1≅W relative to ∂−W. The local model is the identity (S0×Dn)∪h1≅Dn: two n-balls joined by a 1-handle are one n-ball.

Facts & Assumptions

Given: Dimension n≥1, a compact manifold W, a 0-handle h0 attached as a disjoint ball Dn and a 1-handle h1 attached by an embedding S0×Dn−1→∂+(W⊔Dn) whose attaching 0-sphere has one point on the new boundary sphere Sn−1 of Dn and one point on ∂+W.

[F1]

Geometrically cancelling adjacent handle pair and K handle core cocore attaching region and belt sphere: the belt sphere of a 0-handle is the new boundary sphere Sn−1 (disconnected when n=1), the attaching sphere of a 1-handle is a 0-sphere, and the endpoint convention counts exactly one point of the 0-sphere lying in the belt sphere, transversality being automatic.

[F2]

The standard complementary pair fills a ball: for the standard embedding the union of the standard 0-handle and the standard 1-handle is an n-disc: in its case k=0 the standard complementary pair fills the ball, i.e. (S0×Dn)∪h1≅Dn for the standard hemisphere embedding.

[F3]

Handle cancellation, Attaching a smooth handle with corner rounding and The Axiom of Countable Choice (ACω): assume ACω; a geometrically cancelling pair may be deleted, giving a diffeomorphism relative to the incoming boundary; attachments are formed with corners rounded. The assumption is used through the standard-pair model of [F2] and through this deletion.

Verification

Given: The configuration of the statement.

1.1F1given

The attaching 0-sphere of h1 consists of two points, one on the belt sphere Sn−1 of the attached 0-handle and one on ∂+W; in the endpoint convention of [F1] exactly one point of the 0-sphere lies in the belt sphere, with transversality automatic in these dimensions. Hence the pair is geometrically cancelling.

2.1F2step 1.1

The local model is [F2] with k=0: two n-balls joined by a 1-handle form one n-ball, (S0×Dn)∪h1≅Dn, and the total is the boundary connected sum of W with a disc along the point of ∂+W at which the second foot lands.

3.1F1F2F3step 2.1given∎

By [F3] the cancelling pair may be deleted from W⊔Dn∪h1; equivalently the boundary connected sum with a disc is W again, so W⊔Dn∪h1≅W relative to ∂−W. The attaching-belt matrix is not defined for k=0 (the definition requires 1≤k≤n−2), so this endpoint case is handled directly by the geometric criterion.

ExampleConstruction: Literature-sourcedVerification: Literature-sourcedprecheck passOpen item page →

A cancelling one-two handle pair on a surface

Example

Assume ACω. In dimension n=2 start with a closed disc D2 (a 0-handle) and attach a 1-handle (a band) along two disjoint intervals of ∂D2, with attaching orientations chosen so the disc orientation extends over the band; the result is an annulus whose two boundary circles each contain exactly one point of the belt sphere S0 of the band. Attach a 2-handle (a disc) along one boundary circle. Then the attaching sphere of the 2-handle meets the belt sphere of the 1-handle in exactly one point, the pair is geometrically cancelling, and D2∪h1∪h2≅D2. The transverse count of the unique intersection point is 1 mod 2 and has local sign ±1; the matrix definition of this page is stated for 1≤k≤n−2 and does not cover the endpoint case n=2, which is handled here directly by the geometric criterion.

Facts & Assumptions

Given: Dimension n=2: a closed disc D2 as a 0-handle, a 1-handle (band) attached along two disjoint intervals of ∂D2, with attaching orientations chosen so the disc orientation extends over the band, and then a 2-handle (disc) attached along one boundary circle of the resulting annulus.

[F1]

Attaching a smooth handle with corner rounding and K handle core cocore attaching region and belt sphere: the 1-handle D1×D1 has attaching region S0×D1 and outgoing region D1×S0, so its belt sphere in the outgoing boundary is a 0-sphere {0}×S0; the 2-handle D2×D0 has attaching sphere S1×{0}.

[F2]

Geometrically cancelling adjacent handle pair: in dimension n=2 and k=1 the attaching sphere of the 2-handle is a circle and the belt sphere of the 1-handle is a 0-sphere in the middle boundary (the two boundary circles of the annulus); they meet transversely in isolated points, and the pair is geometrically cancelling when exactly one point of the belt sphere lies on the attaching circle.

[F3]

Handle cancellation, The local oriented intersection sign, The mod 2 intersection number and The Axiom of Countable Choice (ACω): assume ACω; a geometrically cancelling pair may be deleted, so the total is diffeomorphic to the initial disc; the unique transverse intersection has local sign ±1 and mod-2 count 1.

Verification

Given: The configuration of the statement.

1.1F1given

Attaching a band to D2 along two disjoint boundary intervals gives the annulus S1×[0,1], whose two boundary circles each contain exactly one of the two points of the belt sphere S0={0}×S0 of the band: the two points are the end points of the cocore arc {0}×D1, one on each boundary circle.

2.1F2F3step 1.1

Attaching the 2-handle along one boundary circle makes the attaching circle meet the belt sphere in exactly one point, and the intersection is isolated and automatic in these dimensions; by [F2] the pair is geometrically cancelling, with the transverse count equal to 1 modulo 2 and local sign ±1 by [F3].

3.1F2F3step 2.1given∎

By [F3] the pair cancels: D2∪h1∪h2≅D2 relative to the incoming boundary. The attaching-belt matrix is not defined here: its definition requires 1≤k≤n−2, and with n=2 and k=1 we have k=n−1, so the endpoint case is handled directly by the geometric criterion.

ExampleConstruction: Literature-sourcedVerification: Literature-sourcedprecheck passOpen item page →

A handle slide realizes an elementary row operation

Example

Assume ACω. In dimension n=4 start from the 0-handle D4 and attach the standard 1-handle h1 along the equatorial embedding, so that D4∪h1≅S1×D3 and the middle boundary is N=∂+(D4∪h1)≅S1×S2 with belt sphere B={p}×S2 of h1 a 2-sphere. Attach two 2-handles g1,g2 to N along embedded circles γ1,γ2⊆N with disjoint images, for instance γ1=S1×{u1} and γ2 a small circle in a coordinate ball disjoint from B∪γ1, with product/local framings. They are chosen so that γ1 meets B transversely in exactly one point and γ2 is disjoint from B. Indexing rows by the 2-handles and the single column by the 1-handle, the attaching-belt matrix is the column (±1,0)T over Z for suitable orientations, respectively (1,0)T over Z2. Slide the 2-handle g2 over g1. The total 4-manifold is unchanged by the slide, while the same column becomes (±1,±1)T over Z, respectively (1,1)T over Z2: exactly the elementary row operation R2↦R2±R1.

Facts & Assumptions

Given: Dimension n=4; the 0-handle D4 with the standard 1-handle h1 attached, middle boundary N=∂+(D4∪h1) and belt sphere B⊆N of h1; two embedded circles γ1,γ2⊆N with disjoint images, with γ1 meeting B transversely in exactly one point and γ2∩B=∅; the 2-handles g1,g2 attached to N along γ1,γ2 with chosen framings.

[F1]

Attaching a smooth handle with corner rounding and K handle core cocore attaching region and belt sphere: in dimension 4 a 1-handle has attaching region S0×D3, outgoing region D1×S2 and belt sphere S2; a 2-handle has attaching sphere S1 and attaching region S1×D2.

[F2]

The standard complementary pair fills a ball: attaching the standard 1-handle to D4 along the equatorial embedding gives D4∪h1≅S1×D3 with outgoing boundary S1×S2, and up to this diffeomorphism the belt sphere of h1 is the fiber sphere {p}×S2.

[F3]

Attaching-belt intersection matrix of adjacent-index handles: for n=4 and k=1 the matrix is defined (1≤k≤n−2=2), its rows are the (k+1)-handles gi and its columns the k-handles ej, and Mij is the intersection number of the attaching sphere of gi with the belt sphere of ej in the middle boundary, over Z or Z2 according to the orientations.

[F4]

The oriented intersection number, The local oriented intersection sign and The mod 2 intersection number: transverse complementary-dimensional intersections are finite with local signs ±1; a single transverse point of a circle with a 2-sphere has entry ±1 over Z and 1 over Z2, and disjoint spheres have entry 0.

[F5]

Handle slide of one k handle over another and Handle slides preserve the relative diffeomorphism type: assume ACω; a slide of g2 over g1 is defined here (index 2, middle boundary of dimension 3, so 1≤2≤3−1), replaces the attaching circle of g2 by the band sum with a framed parallel copy of the attaching circle of g1, and leaves the total 4-manifold unchanged.

[F6]

Handle slides act by elementary basis change on handle chains and Elementary matrix operations are realized by handle slides: assume ACω; under the disk-push diffeomorphism together with its specified lower-stage homotopy, the slid core satisfies [C2′]=[C2]±[C1] in the handle chain group, so intersecting the fixed belt sphere with both sides gives M2,1′=M2,1±M1,1, the elementary row operation R2↦R2±R1; this is case (ii) of the matrix-operation proposition because k+1=2≤n−2=2.

[F7]

The Axiom of Countable Choice (ACω): ACω is assumed; it is used through [F5] and [F6].

Verification

Given: The configuration of the statement.

1.1F1F2F3F4given

By [F1] and [F2] the middle boundary is N≅S1×S2 and the belt sphere of h1 is B={p}×S2, a 2-sphere; the 2-handles are attached along the circles γi, so the matrix is the column with entries Mi1=I(γi,B). By hypothesis γ1 meets B in exactly one transverse point and γ2 is disjoint from B, so by [F4] the column is (±1,0)T over Z for suitable orientations and (1,0)T over Z2.

2.1F5F6F7step 1.1

Slide the 2-handle g2 over g1; the move is legitimate in the range of [F5], the total 4-manifold is unchanged, and the slid attaching circle γ2′ has core class [C2′]=[C2]±[C1] by [F6]. Countable Choice enters only through the slide and basis-change suppliers [F5] and [F6].

3.1F4F6step 2.1

Recomputing the same column with the slid handle, M2,1′=I(γ2′,B)=I(γ2,B)±I(γ1,B)=0±(±1) over Z, respectively 0+1=1 over Z2: the column becomes (±1,±1)T, respectively (1,1)T, which is exactly the elementary row operation R2↦R2±R1 on the matrix.

4.1F3F5F6step 3.1given∎

The construction is legitimate in the range of both the matrix definition and the slide: with n=4 and k=1 one has 1≤k≤n−2=2 and k+1=2≤n−2, so the example realizes case (ii) of Elementary matrix operations are realized by handle slides in the lowest dimension in which the row operation is available.

CounterexampleConstruction: Literature-sourcedVerification: Literature-sourcedprecheck passjudge pass (gpt-6.1-sol)Open item page →

Algebraic intersection one with three geometric points

Statement refuted

Assume ACω. In the standard 4-dimensional model W=D4∪h2 whose middle boundary is N≅S2×S1 with belt sphere B={p}×S1 of the 2-handle, let A⊂N be the 2-sphere obtained from S2×{u0} by a finger move across B. Then A meets B transversely in exactly three points with local signs +1,+1,−1; the oriented intersection number is I(A,B)=1 and the mod-2 number is 1, while the attaching sphere A and the belt sphere B do not meet in one point. Hence the attached 3-handle and the 2-handle form a pair whose matrix entry is a unit but which is not geometrically cancelling: the cancellation theorem does not apply, although reversing this specific finger isotopy removes the extra pair. A general algebraic-to-geometric conversion is a separate Whitney-trick issue with additional hypotheses.

Facts & Assumptions

Given: The standard 4-dimensional model W=D4∪h2 with middle boundary N≅S2×S1, belt sphere B={p}×S1, and a 2-sphere A⊆N obtained from S2×{u0} by a finger move across B.

[F1]

Attaching-belt intersection matrix of adjacent-index handles and K handle core cocore attaching region and belt sphere: the belt sphere of the 2-handle in the middle boundary is a circle, and the attaching sphere of a 3-handle attached to N is a 2-sphere; the matrix entry is the oriented, respectively mod-2, intersection number of the attaching sphere with the belt sphere.

[F2]

Algebraic cancellation does not yet give geometric cancellation: on N=S2×S1 there are an embedded 2-sphere and an embedded circle meeting transversely in exactly three points with local signs +1,+1,−1, so that the oriented intersection number is 1 although the geometric intersection has three points; the configuration is realized with the sphere as the attaching sphere of a 3-handle and the circle as the belt sphere of the 2-handle in the standard model.

[F3]

The oriented intersection number, The local oriented intersection sign and The mod 2 intersection number: the oriented number is the sum of local signs over the transverse intersection, and the mod-2 number is its cardinality modulo two.

[F4]

Geometric cancellation is a unit entry in the handle matrix and Handle cancellation: a single transverse point gives a unit entry, and only then does the cancellation theorem apply; a unit entry does not by itself supply a single geometric intersection point.

[F5]

The Axiom of Countable Choice (ACω): ACω is assumed; it is used through the intersection-number and cancellation suppliers.

Counterexample

Given: The configuration of the statement.

1.1F2given

The model W=D4∪h2 has middle boundary N≅S2×S1 with belt sphere B={p}×S1 of the 2-handle; the sphere A obtained by the finger move meets B transversely in exactly three points with local signs +1,+1,−1.

2.1F3step 1.1

By [F3] the oriented intersection number is the sum 1+1−1=1, a unit in Z, and the mod-2 number is the cardinality 3≡1 modulo 2, a unit in Z2; the geometric intersection set has three points and the two spheres do not meet in one point.

3.1F1F4F5step 2.1∎

Reading the sphere as the attaching sphere of a 3-handle attached to N and the circle as the belt sphere of the 2-handle, [F1] gives matrix entry 1: a unit entry, but not a geometrically cancelling configuration. Hence the attaching spheres do not satisfy the single-point hypothesis of [F4], the cancellation theorem does not apply, and no single-point conclusion follows from the matrix alone. This inserted finger pair can be removed by the inverse finger isotopy of [F2].

CounterexampleConstruction: Literature-sourcedVerification: Literature-sourcedprecheck passOpen item page →

Adjacent-index handles with zero intersection do not cancel

Statement refuted

Assume ACω. In dimension n=3 start from W0=D3, attach the standard 1-handle h1 along two disks of ∂D3, so that W1=D3∪h1≅S1×D2 is a solid torus, and attach a 2-handle h2 along an embedded circle γ⊂∂W1 that bounds a closed disk in ∂W1 disjoint from the belt sphere S1 of h1; such a circle is disjoint from the belt sphere, so the matrix entry is 0 over both Z and Z2. Then the pair (h1,h2) is not geometrically cancelling and does not cancel: W1∪h2 has fundamental group Z, because the attaching circle is null-homotopic in the solid torus and the relation it adds is trivial, while W0=D3 is simply connected. Hence no diffeomorphism relative to the lower stage removes the pair.

Facts & Assumptions

Given: In dimension n=3 the manifold W0=D3 with a 1-handle h1 attached along two disks of ∂D3, giving W1=D3∪h1≅S1×D2, and a 2-handle h2 attached along an embedded circle γ⊆∂W1 that bounds a closed disk in ∂W1 disjoint from the belt sphere S1 of h1.

[F1]

Attaching a smooth handle with corner rounding and K handle core cocore attaching region and belt sphere: attaching a 1-handle to D3 along two disks of the boundary and rounding the corner gives the solid torus S1×D2, whose boundary is a torus; the belt sphere of the 1-handle is the meridian {p}×S1 of that torus, a 2-handle attaches along a circle, and a circle in the boundary that bounds a disk there is null-homotopic in the solid torus.

[F2]

Attaching-belt intersection matrix of adjacent-index handles and Geometric cancellation is a unit entry in the handle matrix: the matrix entry is the intersection number of γ with the belt sphere; if the two are disjoint the entry is 0 over both Z and Z2, whereas a geometrically cancelling pair would have a unit entry.

[F3]

Seifert–van Kampen identifies the fundamental group with a group pushout: for two open path-connected sets with path-connected overlap, the fundamental group is the pushout of the two groups over the overlap group. A collar thickening of an attached 2-handle gives such a cover with the old manifold and handle as deformation retracts, and overlap retracting onto the attaching annulus S1×D1.

[F4]

Handle cancellation and Geometrically cancelling adjacent handle pair: a cancelled pair may be deleted, so if (h1,h2) cancelled then W1∪h2 would be diffeomorphic to D3 relative to the lower stage, in particular simply connected.

[F5]

The Axiom of Countable Choice (ACω): ACω is assumed; it is used through [F3] and [F4].

Counterexample

Given: The configuration of the statement.

1.1F1given

Take W1=S1×D2 with its boundary torus S1×S1; the belt sphere of the 1-handle is the meridian {p}×S1. The attaching circle γ bounds a closed disk in ∂W1 that avoids {p}×S1, so γ is disjoint from the belt sphere and, bounding a disk in the boundary torus, is null-homotopic in W1.

2.1F2step 1.1

Since the two circles are disjoint, the attaching-belt matrix entry is 0 over both Z and Z2; in particular the pair is not geometrically cancelling, because a geometrically cancelling pair has a unit entry by [F2].

2.2F3step 1.1constructalgebra

Thicken the old stage and handle slightly across their seam to obtain open path-connected sets U,V, with U≃W1, V≃D2×D1, and U∩V≃S1×D1. By [F3], π1(U∪V) is the pushout of π1(W1)←Z→1; the map into π1(W1) is represented by γ, which is null-homotopic by step 1.1. The pushout is therefore π1(W1). The product contraction S1×D2→S1×{0} gives π1(W1)≅Z, so π1(W1∪h2)≅Z. This is a direct handle-gluing argument and does not assume an unspecified one-critical-point Morse presentation.

3.1F4F5step 2.1step 2.2

By [F4] a cancellation of the pair would give a diffeomorphism W1∪h2≅W0=D3 relative to the lower stage, hence an isomorphism of fundamental groups Z≅1, which is impossible. Therefore the pair does not cancel, even though both the algebraic and the geometric intersection counts are zero.

4.1F2F4step 3.1∎

Consequently the single-point criterion of the cancellation theorem cannot be replaced by a count-only condition: an adjacent-index pair with vanishing (algebraic and geometric) intersection need not cancel, and no diffeomorphism relative to the lower stage removes the pair.

Sources