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A noncommuting two-noise equation requires an area term

Example

Let W1,W2 be independent standard Brownian coordinates and solve from (0,0) the two-dimensional SDE dXt1=dWt1,dXt2=Xt1dWt2. Its diffusion fields are σ1(x1,x2)=(1,0) and σ2(x1,x2)=(0,x1). They are noncommuting: L1σ2=(0,1) while L2σ1=(0,0). On the first step, the exact second coordinate and its Milstein Taylor increment are I12=∫0hWs1dWs2. Although I12+I21=ΔW1ΔW2, the individual area term is not determined by the two endpoint increments.

Facts & Assumptions

Given: AC; a filtered probability space whose filtration satisfies the usual conditions; and a standard two-dimensional Brownian motion W=(W1,W2) adapted to that filtration such that Wt−Ws is independent of Fs and has its standard two-dimensional normal law with covariance (t−s)I2 for every 0≤s<t (for example, the usual augmentation of the joint natural filtration of (W1,W2)), as required by Continuous Brownian Ito processes; a step length h>0; and the It^o integrals in the Definition.

[F1]

Continuous Brownian Ito processes: Brownian coordinates are independent and increments after time zero are normal with their stated variances.

[F2]

Milstein updates, iterated Brownian integrals, and commutative noise: Liσj=Dσj σi and Iij=∫0hWsidWsj.

[F3]

Ito isometry and linearity in predictable L2: EI122=E∫0h(Ws1)2ds.

[F4]

Standard normal and normal laws: Brownian increments have Gaussian densities, and independent coordinates have product law.

[F5]

Conditional expectation given a sigma algebra: conditional expectation is characterized by integrals on events in the conditioning sigma algebra.

[F6]

Basic algebra and order properties of conditional expectation: conditional expectation is linear, preserves expectation, and is L1-contractive.

[F7]

Cauchy-Schwarz for random variables: E∣Z∣≤(E∣Z∣2)1/2 for square-integrable Z.

[F8]

Conditional expectation is the l2 orthogonal projection: for I∈L2 and J=E[I∣G], E[(I−J)Z]=0 for every Z∈L2(G), in particular Z=J.

[A1]

The Axiom of Choice: AC is inherited through [F1], [F3], and the conditional-expectation interface [F6].

Verification

Given: The assumptions above.

1.1F1F2givenalgebra

The Jacobian of σ2 sends (1,0) to (0,1), so L1σ2=(0,1); the Jacobian of the constant field σ1 is zero, so L2σ1=(0,0). Thus commutativity fails. Starting from X0=(0,0), the first coordinate is Wt1 and the second is ∫0tWs1dWs2. The general Milstein Taylor update [F2] therefore has second-coordinate increment I12 on the first step.

1.2F3L1given

By [L1], the endpoints determine I12+I21=UV, where U=ΔW1 and V=ΔW2. Let πn={0=s0<⋯<sqn=h} be deterministic partitions with mesh ∣πn∣→0, and put Sn=∑k=0qn−1Wsk1(Wsk+12−Wsk2). The It^o isometry [F3] gives E∣Sn−I12∣2=∑k∫sksk+1(s−sk)ds≤h∣πn∣/2→0.

2.1F1F5F6F7step 1.2algebra

For 0<s<h, write A=Ws1 and U−A=Wh1−Ws1; their joint density is ps(a)ph−s(u−a), where pr is the N(0,r) density. Dividing by the marginal density ph(u) and completing the square gives E[A∣U=u]=(s/h)u. At s=0 and s=h the same formula follows from A=0 and A=U, respectively. For ℓk=sk+1−sk, the pair Bk=Wsk+12−Wsk2 and V−Bk has density pℓk(b)ph−ℓk(v−b) when ℓk<h; completing the square gives E[Bk∣V=v]=(ℓk/h)v, and if ℓk=h then Bk=V gives the same result. Independence of the two Brownian coordinate processes [F1] makes the joint density of (A,U,Bk,V) the product of these two pair densities. Dividing by ph(u)ph(v) shows that the conditional density of (A,Bk) given (U,V)=(u,v) factors, so E[ABk∣U,V]=(s/h)U(ℓk/h)V. Therefore E[Sn∣σ(U,V)]=UVh2∑ksk(sk+1−sk)⟶UV2, because the sum is a left Riemann sum for ∫0hs ds=h2/2. By [F7], step 1.2 implies Sn→I12 in L1; conditional expectation is L1-contractive by [F6], so [F5] gives E[I12∣σ(U,V)]=UV/2.

3.1F1F3F4F5F8step 2.1A1algebra∎

The isometry [F3] gives EI122=∫0hE(Ws1)2ds=h2/2. Also U,V are independent with second moments h, so step 2.1 gives J:=E[I12∣σ(U,V)]=UV/2 and EJ2=E[U2V2]/4=h2/4. By [F8], E[(I12−J)J]=0; expanding the square therefore gives E∣I12−J∣2=EI122−EJ2=h2/4>0. If I12 were a measurable function of (U,V), the conditional-expectation identity [F5] would give I12=J almost surely, contradicting this positive residual. Thus the endpoint increments do not determine the required area sample, and any approximation has a separate error and cost.

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