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The unitary DFT for N=1 and N=2

Example

For N=1 the unitary transform of The unitary discrete Fourier transform on Z/NZ is the identity: the group Z/1Z has the single class [0]1, the only term of the defining sum is 1−1/2f([0]1)e0=f([0]1), and the matrix of F1 is the 1×1 matrix [ 1 ]=I1, which is its own inverse.

For N=2, write h=(h0,h1) for h∈CZ/2 with h0:=h([0]2) and h1:=h([1]2). Since e−πixk=(−1)xk for x,k∈{0,1},

F2(h0,h1)=2−1/2(h0+h1, h0−h1),

whose matrix relative to the classes [0],[1] is 12(111−1); this matrix is real and symmetric and satisfies A2=I2, so it is its own inverse. Since the reflection x↦−x is the identity on Z/1Z and on Z/2Z, the fourth-power identity of FN2 is reflection and FN4 is the identity reads F12=F22=id here, consistent with A2=I2 and with the inversion theorem Finite Fourier inversion for the unitary transform on Z/NZ; and F2 preserves the counting norm by Finite Parseval and Plancherel identity for the unitary DFT.

Facts & Assumptions

Given: A function f∈CZ/1 with f0:=f([0]1); a function h∈CZ/2 with h0:=h([0]2) and h1:=h([1]2); and the matrix A:=12(111−1).

[F1]

(FNu)(k)=N−1/2∑x=0N−1u([x]N)e−2πikx/N (The unitary discrete Fourier transform on Z/NZ), with 1−1/2=1 and 2−1/22−1/2=2−1 (Rational powers ar of a positive base, Laws of rational exponents).

[F3]

In Z/2Z the classes [0], [1] are distinct and [1]+[1]=[0]; in Z/1Z there is only [0], and −[0]=[0] (The congruence class [a]n and the quotient set Z/n, For every natural n, (Z/n,+) is an abelian group, multiplication is a commutative monoid operation, and both distributive laws hold).

[F4]

Matrix product and identity: (AB)ik=∑j∈naijbjk and In has entries 1 on the diagonal and 0 elsewhere (Rectangular matrix multiplication and the identity matrix In, including zero-sized shapes); CZ/2 is the vector space of functions on the two-element group (The vector space FX of all functions X→F with pointwise operations, and Fn as the case X=n={0,1,…,n−1}).

[L1]

FN2=R with R the reflection x↦−x, and FN4=id; at N=1,2 the reflection is the identity (FN2 is reflection and FN4 is the identity).

[L3]

The inverse transform is the positive-sign transform N−1/2∑k(FNu)(k)e2πikx/N (Finite Fourier inversion for the unitary transform on Z/NZ).

Verification

technique · direct
1.1F1F2F3

At N=1: (F1f)(0)=1−1/2f0e0=f0, so F1=id and its matrix is I1=[ 1 ].

1.2F1F2F3

At N=2: for k=0 both summands have factor e0=1, giving (F2h)(0)=2−1/2(h0+h1); for k=1 the factors are e0=1 at x=0 and e−πi=−1 at x=1, giving (F2h)(1)=2−1/2(h0−h1). These are the two entries of A(h0,h1)T.

1.3F4

The matrix A satisfies A2=12(111−1)(111−1)=12(1+11−11−11+1)=12(2002)=I2, by the entry formula of [F4]; hence A=A−1, and A is real and symmetric.

2.1F3L1L2step 1.3

The reflection is the identity on Z/1Z and on Z/2Z by [F3], so [L1] gives F12=id and F22=id; this is consistent with [ 1 ]2=[ 1 ] and with step 1.3, and by [L2] the transforms preserve the counting norm at both lengths (for N=2, the norm identity reads ∣h0+h1∣2+∣h0−h1∣2=2∣h0∣2+2∣h1∣2, which is the displayed matrix computation after multiplying by 12).

3.1L3step 1.1step 1.2step 1.3step 2.1∎

Steps 1.1 and 1.2 compute the two transforms and their matrices, step 1.3 verifies that the N=2 matrix is its own inverse, and step 2.1 reconciles both with inversion and the fourth-power identity; the example is verified.

Remarks

  • The degenerate length is not an exception. N=1 is a genuine case of every statement on this page: the transform is the identity, the orthogonality sum has its single coincident term, and the radix-two recursion later on this page terminates at this case as its base. Nothing in the definitions excludes it, and no separate convention is introduced for it.

  • At N=2 the transform is its own inverse. This is the smallest length at which the transform is not the identity while still being involutive; for N≥3 the reflection is not the identity, so the square of the transform is not the identity either, although the fourth power always is.

Depends on

Used by

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