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Lipschitz graph area and calculus under Countable Choice

Statement

Assume Countable Choice. Let m≥1, let Q⊆Rm be open, and let h:Q→R be locally Lipschitz. Then h is differentiable almost everywhere, its partial derivatives are measurable and are its weak derivatives. On every open region where h is L-Lipschitz, ∣Dh∣≤L almost everywhere. Let Hm denote the repository's unnormalised Hausdorff measure, put cm=Hm((0,1]m), and write σm=cm−1Hm also on Euclidean spaces containing m-dimensional subsets. The graph map F(y)=(y,h(y)) satisfies, for every nonnegative Borel a, ∫F(Q)a(x) dσm(x)=∫Qa(F(y))1+∣Dh(y)∣2 dy. For the epigraph G={(y,z):y∈Q, z>h(y)}, a smooth vector field compactly supported away from the chart sides satisfies ∫Gdiv⁡ϕ dx=∫Qϕ(y,h(y))⋅(Dh(y),−1) dy. Thus its outward normal is (Dh,−1)/1+∣Dh∣2 almost everywhere. The sign reverses for a subgraph. The graph surface measure is locally finite and Radon on F(Q) with its relative topology, and its null sets coincide with graph images of Lebesgue-null subsets of the base.

Facts & Assumptions

Given: Countable Choice and the locally Lipschitz graph in the Statement.

[F1]

A Lipschitz interval function is absolutely continuous and has a derivative almost everywhere; these conclusions assume at most Countable Choice. (C1 implies Lipschitz, Lipschitz implies absolutely continuous, and absolutely continuous implies continuous and bounded variation, Absolutely continuous functions have integrable derivatives)

[F3]

Lebesgue differentiation of locally integrable functions holds under Countable Choice. (Lebesgue differentiation theorem on Rn)

Proof

Given: The graph in the Statement. All local arguments take place in a box compactly contained in a region on which h is Lipschitz.

1.1F1F2givenconstruct

We first need the integral identity for Lipschitz interval functions without invoking the stronger published general absolutely continuous FTC. If b is L-Lipschitz on [a,d], extend it constantly past the endpoints. Its difference quotients are bounded by L and converge to b′ almost everywhere by [F1]. For any a≤s<t≤d, dominated convergence gives ∫stb′(r) dr=lim⁡ϵ↓01ϵ(∫tt+ϵb(r) dr−∫ss+ϵb(r) dr)=b(t)−b(s). Coordinate difference quotients of h are measurable; [F1] and [F2] show their limits gi exist almost everywhere, with ∣gi∣≤L. Define them to be zero on the exceptional sets. Applying the preceding identity and one-dimensional integration by parts on each line, then [F2], gives ∫h∂iη=−∫giη for smooth compactly supported η. The same line identities hold for every coordinate line of h, outside the appropriate line-null exceptional set of derivatives.

2.1F2F3step 1.1algebra

For a cube C of side 2r and a Lipschitz w, join x to y by the m coordinate segments replacing their coordinates in order. Step 1.1 bounds ∣w(x)−w(y)∣ by the sum of the line integrals of ∣∂iw∣. Integrate in x,y∈C. For coordinate i, the unused coordinates contribute (2r)m−1, while the measure of endpoint pairs whose interval contains a fixed coordinate value is at most (2r)2. Thus, after division by ∣C∣, the triangle inequality yields ∫C∣w−wC∣≤2r∑i=1m∫C∣∂iw∣, where wC is its mean. Outside a null set, g=(gi) has strong Lebesgue points: apply [F3] to its coordinates and to ∣g−q∣ for every rational vector q, then approximate g(x) by such q. The countable union of the exceptional null sets is null under Countable Choice. Ball differentiation also gives cube differentiation by the fixed volume comparison. At such a point x, set p=g(x) and w(y)=h(y)−h(x)−p⋅(y−x). The displayed inequality gives ∫C(x,r)∣w−wC∣=o(rm+1). As w(x)=0 and w has a fixed Lipschitz bound, a mean with ∣wC∣≥ϵr would give ∣w−wC∣≥ϵr/2 on a cube of side proportional to r centered at x, contradicting this estimate. Thus wC=o(r). If ∣w(y)∣≥ϵr at some y in the half cube, the Lipschitz bound gives the same contradiction on a cube of side proportional to r centered at y. Hence sup⁡C(x,r/2)∣w∣=o(r), proving differentiability with derivative p. Difference quotients then give ∣p∣≤L. Countably many rational boxes cover Q, so the assertion is global.

3.1step 2.1constructalgebra

We prove the area identity first for bounded Borel base sets within one L-Lipschitz box. On the differentiability set, for any 0<ϵ<1/4, form countably many Borel pieces on each of which Dh lies within ϵ of a fixed rational vector p, the differentiability remainder is at most ϵ∣z−y∣ whenever ∣z−y∣<1/k, and the points lie in one cube of diameter less than 1/k. Such pieces cover the differentiability set: the remainder condition follows from differentiability, can be tested on countably many rational z by continuity, and is measurable; use increasing integers k and a rational-vector enumeration. Subtract earlier pieces to make them disjoint. For two points y,z of a single piece E, set Apv=(v,p⋅v). Then ∣F(z)−F(y)−Ap(z−y)∣≤2ϵ∣z−y∣≤2ϵ∣Ap(z−y)∣. Consequently F∘Ap−1:Ap(E)→F(E) is at most (1+2ϵ)-Lipschitz, and its inverse is at most (1−2ϵ)−1-Lipschitz. The sets F(E) are Borel because F is a homeomorphism from Q onto its graph.

4.1F2F4step 3.1algebra

Choose an orthonormal coordinate system on the range plane of Ap. Its square coordinate matrix has determinant of absolute value Jp=det⁡(ApTAp)=1+∣p∣2. Thus [F4] gives σm(Ap(E))=Jp∣E∣. Apply [F4] to the two maps in step 3.1 to obtain (1−2ϵ)mJp∣E∣≤σm(F(E))≤(1+2ϵ)mJp∣E∣. The function p↦1+∣p∣2 is 1-Lipschitz, so ∣Jp−1+∣Dh(y)∣2∣≤ϵ on E. The excluded base-null set has graph image of zero σm by [F4], since F is Lipschitz. Sum the displayed inequalities over the disjoint pieces, using ∣p∣≤L+ϵ. The difference between σm(F(B)) and ∫B1+∣Dh∣2 is bounded by Cm,Lϵ∣B∣. Letting ϵ↓0 proves equality. Exhaustion and countable localization extend it to arbitrary Borel B⊆Q; indicator functions, simple functions and monotone convergence prove the asserted integral formula.

5.1F2step 1.1step 2.1step 4.1algebra∎

For a compactly supported smooth scalar b in the chart, vertical integration gives ∫G∂zb=−∫Qb(y,h(y)) dy. For a horizontal coordinate put Bi(y)=∫h(y)∞b(y,z) dz. This is Lipschitz and compactly supported in Q; step 2.1 and ordinary differentiation of the smooth integral give ∂iBi=∫h(y)∞∂ib dz−b(y,h(y))gi almost everywhere. Its weak derivative integrates to zero by step 1.1 and [F2]. Apply these identities to the components of ϕ and sum. Step 4.1 converts the resulting flux into the unit-normal formula. The graph measure is a graph pushforward of the locally bounded measurable density 1+∣Dh∣2 dy; compact and open approximation in the base show it is locally Radon on the graph with its relative topology. The density is between 1 and 1+L2 on every local box, which also proves the null-set assertion.

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