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Lipschitz graph area and calculus under Countable Choice
Statement
Assume Countable Choice. Let , let be open, and let be locally Lipschitz. Then is differentiable almost everywhere, its partial derivatives are measurable and are its weak derivatives. On every open region where is -Lipschitz, almost everywhere. Let denote the repository's unnormalised Hausdorff measure, put , and write also on Euclidean spaces containing -dimensional subsets. The graph map satisfies, for every nonnegative Borel , For the epigraph , a smooth vector field compactly supported away from the chart sides satisfies Thus its outward normal is almost everywhere. The sign reverses for a subgraph. The graph surface measure is locally finite and Radon on with its relative topology, and its null sets coincide with graph images of Lebesgue-null subsets of the base.
Statement references
Facts & Assumptions
Given: Countable Choice and the locally Lipschitz graph in the Statement.
A Lipschitz interval function is absolutely continuous and has a derivative almost everywhere; these conclusions assume at most Countable Choice. ( implies Lipschitz, Lipschitz implies absolutely continuous, and absolutely continuous implies continuous and bounded variation, Absolutely continuous functions have integrable derivatives)
Completed Euclidean Fubini and Tonelli hold under Countable Choice. (Tonelli and Fubini for the completed product, with only almost-everywhere section measurability, The Euclidean Lebesgue measure is the completion of the product of the factor Lebesgue measures)
Lebesgue differentiation of locally integrable functions holds under Countable Choice. (Lebesgue differentiation theorem on )
Hausdorff measure on an -plane, divided by , is Euclidean -volume; isometries preserve it and -Lipschitz maps increase it by at most . Invertible linear maps scale Euclidean volume by the absolute determinant. (Euclidean Hausdorff measure is proportional to Lebesgue measure, Similarities scale Hausdorff measure exactly, Lipschitz maps control Hausdorff measure, A linear map of sends Lebesgue measurable sets to Lebesgue measurable sets, with when is invertible and Lebesgue null when it is not)
Proof
Given: The graph in the Statement. All local arguments take place in a box compactly contained in a region on which is Lipschitz.
We first need the integral identity for Lipschitz interval functions without invoking the stronger published general absolutely continuous FTC. If is -Lipschitz on , extend it constantly past the endpoints. Its difference quotients are bounded by and converge to almost everywhere by [F1]. For any , dominated convergence gives Coordinate difference quotients of are measurable; [F1] and [F2] show their limits exist almost everywhere, with . Define them to be zero on the exceptional sets. Applying the preceding identity and one-dimensional integration by parts on each line, then [F2], gives for smooth compactly supported . The same line identities hold for every coordinate line of , outside the appropriate line-null exceptional set of derivatives.
For a cube of side and a Lipschitz , join to by the coordinate segments replacing their coordinates in order. Step 1.1 bounds by the sum of the line integrals of . Integrate in . For coordinate , the unused coordinates contribute , while the measure of endpoint pairs whose interval contains a fixed coordinate value is at most . Thus, after division by , the triangle inequality yields where is its mean. Outside a null set, has strong Lebesgue points: apply [F3] to its coordinates and to for every rational vector , then approximate by such . The countable union of the exceptional null sets is null under Countable Choice. Ball differentiation also gives cube differentiation by the fixed volume comparison. At such a point , set and . The displayed inequality gives . As and has a fixed Lipschitz bound, a mean with would give on a cube of side proportional to centered at , contradicting this estimate. Thus . If at some in the half cube, the Lipschitz bound gives the same contradiction on a cube of side proportional to centered at . Hence , proving differentiability with derivative . Difference quotients then give . Countably many rational boxes cover , so the assertion is global.
We prove the area identity first for bounded Borel base sets within one -Lipschitz box. On the differentiability set, for any , form countably many Borel pieces on each of which lies within of a fixed rational vector , the differentiability remainder is at most whenever , and the points lie in one cube of diameter less than . Such pieces cover the differentiability set: the remainder condition follows from differentiability, can be tested on countably many rational by continuity, and is measurable; use increasing integers and a rational-vector enumeration. Subtract earlier pieces to make them disjoint. For two points of a single piece , set . Then . Consequently is at most -Lipschitz, and its inverse is at most -Lipschitz. The sets are Borel because is a homeomorphism from onto its graph.
Choose an orthonormal coordinate system on the range plane of . Its square coordinate matrix has determinant of absolute value . Thus [F4] gives . Apply [F4] to the two maps in step 3.1 to obtain The function is -Lipschitz, so on . The excluded base-null set has graph image of zero by [F4], since is Lipschitz. Sum the displayed inequalities over the disjoint pieces, using . The difference between and is bounded by . Letting proves equality. Exhaustion and countable localization extend it to arbitrary Borel ; indicator functions, simple functions and monotone convergence prove the asserted integral formula.
For a compactly supported smooth scalar in the chart, vertical integration gives . For a horizontal coordinate put . This is Lipschitz and compactly supported in ; step 2.1 and ordinary differentiation of the smooth integral give almost everywhere. Its weak derivative integrates to zero by step 1.1 and [F2]. Apply these identities to the components of and sum. Step 4.1 converts the resulting flux into the unit-normal formula. The graph measure is a graph pushforward of the locally bounded measurable density ; compact and open approximation in the base show it is locally Radon on the graph with its relative topology. The density is between and on every local box, which also proves the null-set assertion.
Depends on
- The Axiom of Countable Choice ($\mathrm{AC}_\omega$)
- Dominated convergence
- Monotone convergence for the integral
- $C^1$ implies Lipschitz, Lipschitz implies absolutely continuous, and absolutely continuous implies continuous and bounded variation
- Absolutely continuous functions have integrable derivatives
- Tonelli and Fubini for the completed product, with only almost-everywhere section measurability
- The Euclidean Lebesgue measure is the completion of the product of the factor Lebesgue measures
- Lebesgue differentiation theorem on $\mathbb{R}^n$
- A linear map $T$ of $\mathbb{R}^n$ sends Lebesgue measurable sets to Lebesgue measurable sets, with $\lambda_n(T[E])=|\det T|\,\lambda_n(E)$ when $T$ is invertible and $T[E]$ Lebesgue null when it is not
- Euclidean Hausdorff measure is proportional to Lebesgue measure
- Lipschitz maps control Hausdorff measure
- Similarities scale Hausdorff measure exactly
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Sources
- Glaucio Terra, Introduction to Geometric Measure Theory, Rademacher Section 5.1.2 and area Section 5.2 (standard reference, not scraped)