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Jones's bound: under choice, a closed discrete subspace of a normal space cannot have more subsets than a dense set has subsets
Statement
Assume the Axiom of Choice. If is a closed discrete subspace of a normal space and is dense, then there is an injection . In cardinal notation, .
Facts & Assumptions
Given: A normal space , a closed discrete , and a dense .
The Axiom of Choice supplies a choice function for every family of nonempty sets (The Axiom of Choice).
Every subset of a discrete subspace is closed in that subspace; because is closed in , each subset of is closed in (Subspace topology: the traces of the open sets, its closed sets and its bases, the continuity of the inclusion, and the characteristic property of a map into a subspace).
Normality separates disjoint closed sets by disjoint open sets, and every nonempty open set meets a dense subset (Normal spaces and spaces, with the source disagreement over whether normality includes stated explicitly, Dense, nowhere dense and codense subsets of a topological space, and the criterion by basic open sets).
Proof
For every , the sets and are disjoint closed subsets of . By normality there is an open containing and an open containing with .
Apply [A1] to choose one such pair for every , and define .
If , take after interchanging them if necessary. Then , a nonempty open set meeting ; a point of lies in and not in .
Thus is injective. By [F3], this is the asserted cardinal inequality.
Depends on
- Normal spaces and $T_4$ spaces, with the source disagreement over whether normality includes $T_1$ stated explicitly
- Dense, nowhere dense and codense subsets of a topological space, and the criterion by basic open sets
- Subspace topology: the traces of the open sets, its closed sets and its bases, the continuity of the inclusion, and the characteristic property of a map into a subspace
- The Axiom of Choice
- Cardinal sum $\kappa \oplus \lambda$, product $\kappa \otimes \lambda$ and exponentiation $\kappa^{\lambda}$, and why they are written apart from the ordinal operations
- Assuming the Axiom of Choice, $2^{\kappa} = \lvert \mathcal{P}(\kappa) \rvert$, and Cantor's theorem in cardinal form: $\kappa < 2^{\kappa}$
Used by
Dependency tree · next 3 levels
Direct dependencies and their dependencies through the next three levels: 76 results over 22 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.
Sources
- G. Gruenhage, General Topology Course Notes, Jones's lemma (standard reference, not scraped)
- Samuel Gomes da Silva, Closed discrete subsets of separable spaces and relative versions of normality, countable paracompactness and property (a) (standard reference, not scraped)