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The knot exterior has a peripheral torus basis
Statement
Assume countable choice. For a smooth oriented knot with a chosen product tubular neighbourhood , let be the positive fibre meridian and let be the product section of . Then is a torus and form a basis of . The curve is a product section; this statement does not assert that it is the preferred zero-homology longitude.
Statement references
Facts & Assumptions
Given: Countable choice, a smooth oriented knot , its chosen tubular exterior, and the product trivialization of the normal disk bundle.
Countable choice, written , is The Axiom of Countable Choice ().
Knot exterior retains and the tube coordinates as part of the exterior data.
Meridian and preferred longitude orients the fibre meridian as the boundary of its oriented normal disk.
Tubular exterior and boundary torus supplies and under [A1].
Cellular homology computes singular homology identifies cellular and singular homology for the finite CW structure on the torus.
Cellular homology defines cellular homology as .
Cellular boundary from three consecutive skeleta defines the cellular differential by the connecting map of successive skeleta followed by the quotient map.
Cellular boundary is the incidence degree matrix computes each cellular boundary coefficient as the degree of the corresponding attaching map after collapsing the other cells.
Proof
In product coordinates on , the meridian is the second factor loop and the section is the first factor loop. Give the torus its standard product CW structure: take the quotient of a square by identifying opposite edges, with one vertex, the two oriented factor loops as its -cells, and the open square as its -cell attached by the commutator .
The cellular chain groups in dimensions are . The differential is zero because each -cell starts and ends at the only vertex. By [F7], each coefficient of is the degree of the attaching map after collapsing the other -cell. The commutator traverses each factor once in each orientation, so both degrees are zero. Thus by [F5] and [F6], with the factor loops as basis.
By [F4], the same two classes form a basis of singular .
Peripheral torus diagram
Use coordinates on the product torus, with in the oriented knot direction and in the oriented meridian direction. The square's opposite edges are identified in the same direction. The horizontal and vertical loops are the product section and meridian ; the diagonal is a representative of . The diagram records the basis convention and is not used in the proof.
Depends on
Used by
- An arbitrary parallel push-off need not be preferred Counterexample
- Finite-volume hyperbolic knot exterior Definition
- Worked case: the unknot exterior Example
- Nontrivial knot exteriors are irreducible and boundary-incompressible Lemma
- The standard two-tetrahedron figure-eight gluing is complete Lemma
- Homology and preferred longitude of a knot exterior Theorem
Dependency tree · two levels
25 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- Alessia Cattabriga and Stefano Francaviglia, Knot Theory and Applications: Lecture Notes (standard reference, not scraped)
- Allen Hatcher, Algebraic Topology (standard reference, not scraped)