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LemmaStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedprecheck passjudge pass (gpt-5.6-terra)audited 2026-09-14
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Local slice for a free proper action

Statement

Let a Lie group G act smoothly, freely, and properly on a smooth manifold M. For every xM there is an embedded submanifold SM through x such that

A:G×SGS,A(g,s)=gs,

is a diffeomorphism onto an open saturated neighborhood of x. In particular, its restriction near (e,x) is a diffeomorphism onto a neighborhood of x, and gSS implies g=e.

Facts & Assumptions

Given: A smooth free proper left action of G on M and a point xM.

[F1]

Properness means that the action-graph map Θ(g,y)=(gy,y) has compact inverse images of compact subsets. Free and proper Lie-group actions.

[F2]

The constant-rank theorem gives local normal forms for constant-rank maps, and a smooth map with invertible differential is locally a diffeomorphism. The constant-rank theorem for manifolds, The smooth inverse function theorem on manifolds.

Proof

Proof technique: construct a transverse submanifold and use properness to exclude returns.

1.1

Let Φx:GM be the orbit map. From ΦxLg=(ygy)Φx and the fact that both outside maps are diffeomorphisms, Φx has constant rank. Its fibre over x is the stabilizer Gx={e} by freeness. If d(Φx)e had a nonzero kernel, the constant-rank normal form [F2] would make the local fibre through e positive-dimensional, contradicting that it is a singleton. Thus d(Φx)e is injective.

givenF2algebra
2.1

By [F3], choose a complement N to d(Φx)e(TeG) in TxM. In a chart at x, the inverse image of the coordinate subspace corresponding to N is, after shrinking, an embedded submanifold S0 through x with TxS0=N. The differential of A0:G×S0M, A0(g,s)=gs, at (e,x) is (X,v)d(Φx)eX+v, hence is an isomorphism. By [F2], there are an identity neighborhood VG and a neighborhood of x in S0, again denoted S0, on which A0V×S0 is a diffeomorphism onto an open neighborhood of x.

F2F3step 1.1construct
3.1

Choose a compact neighborhood C of x and shrink S0 into its interior. Properness makes P=Θ1(C×C) compact. Its projection to G is therefore the compact transporter K={gG:gCC}. The set KV is compact by [F4].

F1F4step 2.1
4.1

For every gKV, freeness gives gxx. Choose disjoint neighborhoods of these two points. Continuity of the action then supplies neighborhoods Og of g and Ng of x such that gNgNg= for all gOg. The Og cover the compact set KV, so finitely many suffice. Intersect their corresponding Ng and shrink S0 to a submanifold neighborhood S of x inside that finite intersection and inside C. Then gSS= for gKV; it is also empty for gK because SC.

givenF4step 3.1construct
5.1

If gSS, step 4.1 gives gV. For s,tS with gs=t, the two points (g,s) and (e,t) of V×S0 have the same image under the injective local map from step 2.1, so g=e and s=t. Consequently A:G×SGS is bijective.

step 2.1step 4.1
6.1

The differential of A is invertible at every (g,s): at (e,s) this follows after the preceding shrinking from the local diffeomorphism in step 2.1, and arbitrary g follows by translation in the source and the action diffeomorphism in the target. Thus A is a bijective local diffeomorphism, hence a diffeomorphism onto its open image. Its image is saturated by definition and contains x. The construction uses only a finite subcover in step 4.1 and no choice principle.

F2step 2.1step 5.1

Depends on

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