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The regular preimage of the collapse recovers the original framed submanifold

Statement

Assume ACω. Let (N,φ) be a closed framed codimension-k submanifold of a closed smooth X, with k≥1. For the normalized smooth Pontryagin–Thom representative f of The Pontryagin-Thom map of a framed submanifold, its centre y0 is regular, f−1(y0)=N, and the basis b0 fixed there induces exactly φ. Thus the framed regular preimage is (N,φ) on the nose. Arbitrary unnormalized collapses represent the same homotopy class but need not induce this literal framing.

Facts & Assumptions

Given: (N,φ), a compatible tube Φ inducing the identity on the normal quotient, and the normalized smooth representative f.

[F1]

With u=φs(v), the target coordinate of f(Φ(s,v)) is u/a(∣u∣2) for ∣u∣<r, with a=1 near zero and positive before the cutoff; elsewhere the value is ∞ (The Pontryagin-Thom map of a framed submanifold).

[F2]

A compatible chart fixes N and induces the identity on its normal quotient (Pontryagin–Thom collapse with specified normal data). The preimage framing is the differential on that quotient followed by the coordinate isomorphism determined by the target basis (Framed regular preimages of a map to a sphere).

Proof

1.1F1givenalgebra

Since φs is invertible and a is positive on the finite-value region, u/a(∣u∣2)=0 precisely when v=0. The remaining points map to ∞≠y0. Hence f−1(y0)=N.

2.1F1F2step 1.1algebra∎

Near v=0 the target coordinate is exactly φs(v). Its vertical derivative is φs, and its derivative on TsN is zero. Compatibility of the tube identifies the vertical quotient with ν(N)s by the identity, so the normal derivative of f in the b0 coordinates is exactly φs. It is surjective, proving regularity and f∗b0=φ.

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