Alphabeta Math
LemmaStatement: AI-adaptedProof: AI-generatedPipeline-generated
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

The bounded-Lipschitz dual discrepancy is bounded by split transport cost

Statement

Assume AC for the Jordan decompositions in Sign-preserving transport cost for finite signed measures. Let d≥1. If finite signed Borel measures ω,ν on Rd have the same positive-part mass and the same negative-part mass, and their total variations have finite first moments, then the couplings in C±(ω,ν) exist, C±(ω,ν)<∞, and dBL(ω,ν)≤C±(ω,ν).

Facts & Assumptions

Given: The signed measures and matching Jordan-part masses of the Statement, with finite first moments of their total variations.

[A1]

Assume the Axiom of Choice for existence of the Jordan parts (The Axiom of Choice).

[F1]

Jordan decomposition gives positive mutually singular parts ω+,ω− and ν+,ν− (Jordan decomposition of a signed measure into unique mutually singular positive parts, Measures on sigma-algebras).

[F2]

The product of finite measures exists with the product marginals, and Tonelli integrates nonnegative costs (For sigma-finite factors, the product measure exists, has the rectangle formula, is sigma-finite, and is unique, Tonelli's theorem for nonnegative measurable functions on a sigma-finite product); the product sigma-algebra of Euclidean Borel spaces is the Euclidean product Borel sigma-algebra (The Borel product of R^m and R^n is the Borel sigma-algebra of R^{m+n}). The Euclidean triangle inequality gives ∣x−y∣≤∣x∣+∣y∣ (Cauchy-Schwarz ∣⟨x,y⟩∣≤∥x∥2∥y∥2 with its equality case, the triangle inequality for ∥⋅∥2, the parallelogram law and polarisation). Also, ∣ω∣=ω++ω− and ∣ν∣=ν++ν−; hence each Jordan part is dominated by its total variation measure. For a nonnegative simple function, the simple integral is monotone under this measure domination by its defining finite sum; taking the supremum over simple minorants in the nonnegative integral definition gives ∫∣x∣dωσ≤∫∣x∣d∣ω∣ and the analogous bound for νσ (For a signed measure, total variation is nu-plus plus nu-minus, finite partitions suffice, and nu-plus and nu-minus are extremal, The nonnegative Lebesgue integral, The integral of a nonnegative simple function).

[F3]

The definitions of dBL and C± use tests bounded by one with Lipschitz constant at most one, and positive/negative couplings (Bounded-Lipschitz dual discrepancy for finite signed measures, Sign-preserving transport cost for finite signed measures).

Proof

1.1A1F1F2givenconstruct

For a sign with common mass m>0, the measure (ωσ⊗νσ)/m has marginals ωσ,νσ by [F2]; its cost is at most ∫∣x∣dωσ+∫∣y∣dνσ<∞ by ∣x−y∣≤∣x∣+∣y∣ and [F2]. If m=0, both parts vanish and the zero measure is a coupling. Applying this to each sign proves nonempty finite-cost coupling sets.

2.1F3step 1.1algebra

Fix any admissible π+,π− and any test ϕ in [F3]. The marginals give ∫ϕd(ω−ν)=∫(ϕ(x)−ϕ(y))dπ+−∫(ϕ(x)−ϕ(y))dπ−. Each absolute integrand is at most ∣x−y∣ by the Lipschitz bound. Thus ∣∫ϕd(ω−ν)∣ is at most the sum of the two coupling costs.

3.1F3step 1.1step 2.1∎

Taking the supremum over tests and then the infimum over the nonempty coupling sets in step 1.1 proves dBL(ω,ν)≤C±(ω,ν)<∞. No minimizing coupling is used.

Depends on

Used by

Dependency tree · two levels

55 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources