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Korn coercivity with a partial Dirichlet segment
Statement
Assume the geometry of Partial-trace displacement space on a polygon and let . Then there is , depending on and , such that
Facts & Assumptions
Given: A nonempty bounded connected Lipschitz extension polygon , a straight Dirichlet segment of length , and as above.
Countable Choice is used by the bounded-Lipschitz divergence right inverse and the closure-defined approximation. (The Axiom of Countable Choice ())
The Axiom of Choice is used through the bounded C1 trace theorem and Poincare-Wirtinger on the bounded connected extension domain. (The Axiom of Choice, The trace operator on a bounded domain, Poincare-Wirtinger on bounded connected extension domains by Rellich compactness)
A nonempty open bounded set has finite positive Lebesgue measure: it contains a ball and is contained in a ball. (Euclidean balls have positive finite Lebesgue measure)
There is a bounded linear with and . (Divergence right inverse on bounded connected Lipschitz domains)
For of zero mean, ; apply this componentwise. (Poincare-Wirtinger on bounded connected extension domains by Rellich compactness)
is bounded and ; in particular for . (Partial-trace displacement space on a polygon, The partial-trace displacement space is a Hilbert space)
Every planar rigid motion satisfies . (A planar rigid motion is controlled by its trace on a segment)
is the closure of . (Zero-boundary Sobolev space as a norm closure)
, and ; adding a rigid motion does not change . (Small-strain elasticity with a frictionless contact gap, A planar rigid motion is controlled by its trace on a segment)
For finite-measure , every function is integrable and . (Cauchy-Schwarz inequality for )
Proof
Given: The polygon, trace segment and space of the statement, with the Axiom of Choice and Countable Choice available through [A1]–[A2].
Since is nonempty, open and bounded, [F0] gives . Hence , and [F7] with the Cauchy–Schwarz inequality makes every component of and its weak gradient integrable; boundedness of also makes and integrable. Thus the means in and exist. Put and . Then , , and by [F6].
Let and choose by [F1]. Define the matrix rowwise by and . For each row of has zero divergence, so distributional integration by parts gives . Approximate the actual by compactly supported smooth fields using [F5]; since in , the same identity holds for .
Set . In two dimensions , so the off-diagonal entries of agree and is symmetric. Write , which is skew-symmetric. Symmetric and skew-symmetric matrices are orthogonal in the Frobenius inner product, so and . By step 2.1, . The entries of are the entries of permuted and sign-changed, so . Also almost everywhere; integration gives . Thus [F1] and the triangle inequality imply . Therefore . If the gradient estimate is immediate; otherwise divide by . Then [F2] and give , hence .
For , [F3] gives . Apply [F4] and the trace bound [F3] to obtain . Since , step 3.1 yields , proving the assertion.
Depends on
- Small-strain elasticity with a frictionless contact gap
- Partial-trace displacement space on a polygon
- The partial-trace displacement space is a Hilbert space
- A planar rigid motion is controlled by its trace on a segment
- Divergence right inverse on bounded connected Lipschitz domains
- Poincare-Wirtinger on bounded connected extension domains by Rellich compactness
- The $L^p$ trace operator on a bounded $C^1$ domain
- Zero-boundary Sobolev space as a norm closure
- Cauchy-Schwarz inequality for $L^2$
- The Axiom of Countable Choice ($\mathrm{AC}_\omega$)
- The Axiom of Choice
- Euclidean balls have positive finite Lebesgue measure
Used by
Dependency tree · two levels
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Sources
- Walter Zulehner, Numerical Methods for Continuum Mechanics 1, complete 80-page lecture notes (standard reference, not scraped)
- Jean-Luc Guermond, MATH 661 Fall 2025, Part XI Chapter 53: Stokes equations: Basic ideas (standard reference, not scraped)