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Tangent and obstruction spaces for hypersurface deformations

Statement

Assume the Axiom of Choice, inherited from the projective-space cohomology suppliers (The Axiom of Choice). Let k be a field, n≥2, d≥1, let f∈S=k[x0,…,xn] be homogeneous of degree d, let X=Z(f)⊆Pkn, and assume X smooth over k of pure dimension n−1. Then the embedded deformation functor of X in the fixed Pkn (Embedded deformations of a closed subscheme) has:

  1. tangent space H0(X,NX/Pn) at the trivial deformation, and NX/Pn≅OX(d), so the tangent space is H0(X,NX/Pn)≅H0(X,OX(d))≅(S/(f))d,dim⁡k=(n+dn)−1;
  2. vanishing obstruction space H1(X,NX/Pn)=H1(X,OX(d))=0, with the embedded deformation functor formally smooth and unobstructed: every embedded deformation over a small extension extends;
  3. for the abstract deformation functor of X as a k-scheme instead the tangent space is Ext⁡OX1(LX/k,OX)≅H1(X,TX/k) and the obstruction group is H2(X,TX/k) (Deformation cohomology of a smooth scheme: tangent, obstruction and automorphism spaces); the two problems are related by the normal bundle sequence 0→TX→i∗TPn→NX/Pn→0 (Conormal sequence for a closed immersion), which need not have vanishing maps, so the embedded and abstract deformation spaces are different in general.

Facts & Assumptions

Given: a field k, n≥2, d≥1, a homogeneous form f∈S of degree d with X=Z(f)⊆Pkn smooth of pure dimension n−1, and the Axiom of Choice.

[F1]

The embedded deformation functor of X in Pn is isomorphic to the equation-deformation functor R↦{F∈(S⊗kR)d:F≡f mod mR}/(R×), it is formally smooth and unobstructed, and its tangent space at the trivial deformation is (S/(f))d≅H0(X,OX(d)) of dimension (n+dn)−1. (Embedded flat deformations of a smooth hypersurface are deformations of its equation)

[F2]

NX/Pn=HomOX(I/I2,OX)≅OX(d) with I/I2≅OX(−d) invertible, H0(X,OX(d))≅(S/(f))d of the stated dimension, and H1(X,OX(d))=0. (Cohomology of twists on a smooth hypersurface, Internal Hom of module sheaves, Locally free sheaves of finite rank, degree projective hypersurface)

[F3]

For the smooth k-scheme X the abstract deformation tangent space is Ext⁡OX1(LX/k,OX)≅H1(X,TX/k) and the obstruction group is H2(X,TX/k). (Deformation cohomology of a smooth scheme: tangent, obstruction and automorphism spaces)

[F4]

For the smooth closed immersion i:X↪Pkn the normal bundle sequence 0→TX→i∗TPn→NX/Pn→0 is exact. (Conormal sequence for a closed immersion, Smooth closed immersion is regular with exact conormal sequence, Smooth morphism of schemes)

[F5]

Projective space is smooth by its polynomial charts and the Jacobian criterion with no relations (Relative Jacobian criterion with its presentation hypothesis). For Pk1, H1(Pk1,O(2))=0. (Cohomology of O(d) on projective space)

Proof

technique · read the tangent and obstruction spaces of the embedded functor from the equation functor and the normal-sheaf computation, and compare with the abstract deformation spaces through the normal bundle sequence
1.1F1F2given

Tangent space and normal sheaf. By [F1] the tangent space of the embedded deformation functor at the trivial deformation is (S/(f))d≅H0(X,OX(d)), of dimension (n+dn)−1; by [F2] the normal sheaf is NX/Pn≅OX(d), so H0(X,NX/Pn)≅H0(X,OX(d)) has the same dimension. This proves part (1).

1.2F1F2given

Obstruction space and formal smoothness. By [F2], H1(X,NX/Pn)=H1(X,OX(d))=0; independently, [F1] proves that the equation functor is formally smooth and unobstructed, so every embedded deformation over a small extension extends. This proves part (2).

2.1F2F3F4step 1.1

Comparison with abstract deformations. By [F3] the abstract deformation functor has tangent space H1(X,TX/k) and obstruction group H2(X,TX/k); [F4] provides the normal bundle sequence relating TX, i∗TPn and NX/Pn. No injectivity or surjectivity of the comparison map between embedded and abstract deformations is asserted, since the maps in the normal bundle sequence need not vanish; the two deformation problems are therefore different in general, as claimed in part (3).

3.1F3F5step 1.1algebra∎

For an explicit difference, take the line X=Z(x0)⊂Pk2, which is Pk1. Its embedded tangent space has dimension (32)−1=2 by step 1.1. On the two standard charts of P1, use coordinates u and v=u−1. The tangent frames satisfy ∂v=−u2∂u, so after changing one frame by −1 the tangent line bundle is O(2) (the standard twisting transition is u2). Thus [F5] gives H1(X,TX)=0, while the embedded tangent space has dimension two. This proves the claimed difference in general without identifying the two functors. Choice is inherited from the cited suppliers.

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