Alphabeta Math
TheoremStatement: AI-adaptedProof: AI-adaptedprecheck passjudge pass (deepseek-v4-pro + gpt-5.6-terra)audited 2026-08-16
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The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
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Continuous integrands have complex and absolute line integrals along every rectifiable path

Statement

Let γ:[a,b]→C be rectifiable and let f be continuous on its trace. Then the complex line integral The complex line integral over a rectifiable path as a componentwise Riemann–Stieltjes integral and the absolute line integral The absolute line integral over a rectifiable path using its arc-length function both exist.

Facts & Assumptions

Given: A rectifiable γ=x+iy and a continuous f=u+iv on its trace.

[L1]

A planar path is rectifiable if and only if each coordinate function has bounded variation (A path in Rn is rectifiable exactly when every coordinate has bounded variation).

[L3]

If a real integrand is continuous and a real integrator has bounded variation, then its Riemann–Stieltjes integral exists (A continuous integrand is Riemann–Stieltjes integrable against every bounded-variation integrator).

Proof

technique · direct
1.1L1L3

By [L1], x and y have bounded variation. The four real functions u∘γ and v∘γ are continuous, so [L3] gives all four Stieltjes integrals in the complex definition.

1.2L2L3

The function ∣f∘γ∣ is continuous, and [L2] makes sγ a bounded-variation integrator, so [L3] gives the absolute integral.

2.1step 1.1step 1.2∎

Thus both definitions are well-defined. On a singleton or constant path the relevant integrators are constant and every integral is 0.

Depends on

Used by

Cited to discharge well-definedness by The absolute line integral over a rectifiable path using its arc-length function and The complex line integral over a rectifiable path as a componentwise Riemann–Stieltjes integral.

Dependency tree · two levels

26 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources