Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedprecheck passjudge pass (gpt-5.6-terra)audited 2026-09-06
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Ext dimension shifting in the first variable

Statement

Assume the Axiom of Dependent Choice. Let A be abelian with enough projectives and enough injectives, fix supplied projective and injective resolution data on all its objects, and let 0⟶ΩM→iP0→εM⟶0 be the first stage of a projective resolution. For every object N there is an exact sequence 0→Hom⁡(M,N)→Hom⁡(P0,N)→Hom⁡(ΩM,N)→Ext⁡1(M,N)→0, and for every q≥1 there is a natural isomorphism Ext⁡q(ΩM,N)≅Ext⁡q+1(M,N).

Facts & Assumptions

Given: The displayed first stage and the remaining projective resolution ⋯→P2→P1→P0→M→0.

[L1]

A short exact sequence in the first variable gives the long exact Ext sequence (The long exact Ext sequence in the first variable).

Proof

technique · direct
1.1L1givenconstruct

Apply [L1] to 0→ΩM→P0→M→0. Its relevant terms are Ext⁡q(P0,N)→Ext⁡q(ΩM,N)→Ext⁡q+1(M,N)→Ext⁡q+1(P0,N).

2.1step 1.1algebra∎

Since P0 is projective, the outer groups vanish for q≥1 by Positive projective-resolution Ext vanishes on a projective first variable, giving the displayed natural isomorphism. The degree-zero end of the same long exact sequence is exactly the displayed five-term sequence.

Depends on

Used by

Dependency tree · two levels

21 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources