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Feller converse to Lindeberg-Feller
Statement
Assume AC. Let a centered row-wise independent triangular array satisfy and . If , then it satisfies the Lindeberg condition.
Facts & Assumptions
The scalar centered exponential increment has modulus at most u^2; its proof also gives 1-cos(u)<=u^2/2. Second-order characteristic-function expansion.
Near-one products differ from the exponential of their summed increments by o(1). Products of near-one characteristic factors.
The independent row sum has product characteristic function. Characteristic functions under affine maps and independent sums.
The assumed weak convergence gives pointwise characteristic-function convergence. Levy continuity theorem forward direction.
Under AC N(0,1) has transform exp(-t^2/2). Characteristic function of a normal law.
Euler form gives unit modulus and -1<=cos<=1. , , and .
Exponential addition and real extension identify the modulus as exp(real part). , and the complex exponential extends the real exponential.
The real nonnegative exponential series gives exp(d)>=1+d for d>=0. The complex exponential by its power series.
Centering, real parts and finite sums commute with integration. The Lebesgue integral is linear on .
Complex expectation is bounded by the expectation of its absolute value. The modulus of an integral is bounded by the integral of the modulus.
For total row variance one, Lindeberg is exactly convergence of the summed tail second moments. Total row variance and the Lindeberg condition.
Proof
Given: Assume AC. Let a centered row-wise independent triangular array satisfy and . If , then it satisfies the Lindeberg condition.
Fix real t and put and . Centering, [F1], [F9] and [F10] give . Thus , , and . By [F2]–[F5] and the assumed normal limit, . This inference uses the forward continuity theorem only, not Lindeberg sufficiency.
Define the nonnegative function . Nonnegativity follows from the cosine Taylor bound in [F1]; also because . Hence is finite and nonnegative. Total variance one and [F9] give . Exponential addition and Euler modulus show . Step 1.1 therefore implies . Since the nonnegative series gives , we obtain . No complex logarithm or subsequence of measures is needed.
Now fix any and take the single frequency . On we have , and yields . On the complementary set d_t is nonnegative. Integrating and summing gives . This is precisely [F11], for every positive epsilon. AC is inherited from the target normal-law construction; the proof uses no Helly selection, uniqueness inversion or backward application of sufficiency. Zero entries and t=0 in the earlier steps are harmless, but the final chosen t is nonzero.
Depends on
- Second-order characteristic-function expansion
- Products of near-one characteristic factors
- Characteristic functions under affine maps and independent sums
- Levy continuity theorem forward direction
- Characteristic function of a normal law
- $\exp(x+iy)=e^x(\cos y+i\sin y)$, $|\exp(x+iy)|=e^x$, and $e^{i\pi}+1=0$
- $\exp(z+w)=\exp z\,\exp w$, and the complex exponential extends the real exponential
- The complex exponential by its power series
- The Lebesgue integral is linear on $L^1(\mu)$
- The modulus of an integral is bounded by the integral of the modulus
- Total row variance and the Lindeberg condition
- The Axiom of Choice
Used by
Nothing in the library uses this result yet.
Dependency tree · two levels
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Sources
- Billingsley, Probability and Measure, Theorems 28.1-28.4 and Example 28.4 (standard reference, not scraped)